在一段时间后停止Ruby-jRuby-thread
我试图用jRuby创建一个简单的多线程程序。它需要根据指定的时间量启动和停止线程,例如运行五秒钟,然后停止。我对这类东西很陌生,所以它可能很基本,但我无法让它工作 相关代码如下所示:在一段时间后停止Ruby-jRuby-thread,ruby,multithreading,jruby,Ruby,Multithreading,Jruby,我试图用jRuby创建一个简单的多线程程序。它需要根据指定的时间量启动和停止线程,例如运行五秒钟,然后停止。我对这类东西很陌生,所以它可能很基本,但我无法让它工作 相关代码如下所示: require 'java' require 'timeout' require './lib/t1.rb' require './lib/t2.rb' class Threads [...] def manage_threads thread2 = T2.new # Wait for
require 'java'
require 'timeout'
require './lib/t1.rb'
require './lib/t2.rb'
class Threads
[...]
def manage_threads
thread2 = T2.new
# Wait for 5 seconds before the thread starts running..
thread2.run(wait_time = 5)
Timeout::timeout(10) do
thread1 = T1.new {}
end
end
class T1 < Thread
def initialize
while super.status != "sleep"
puts "Thread 1"
sleep(1)
end
end
end
class T2
include java.lang.Runnable
def run wait_time
thread = Thread.new do
sleep(wait_time)
loop do
puts "Thread 2"
sleep(1)
end
end
end
def stop_thread(after_run_time)
sleep(after_run_time)
end
end
有没有人对如何使用1有什么建议。启动一个线程,运行一段时间。2.启动一个新线程,并行运行两个线程。2.停止线程1,但继续运行线程2。如有任何提示/建议,将不胜感激 我想我解决了
这就成功了:
def run wait_time
thread = Thread.new do
sleep(wait_time)
second_counter = 0
loop do
puts "Thread 2"
second_counter += 1
if second_counter == 15
sleep
end
sleep(1)
end
end
end
def run wait_time
thread = Thread.new do
sleep(wait_time)
second_counter = 0
loop do
puts "Thread 2"
second_counter += 1
if second_counter == 15
sleep
end
sleep(1)
end
end
end