Scala 如果所有组件都是None,则如何返回None,否则
我有一个案例类,如:Scala 如果所有组件都是None,则如何返回None,否则,scala,Scala,我有一个案例类,如: case class Part1(id: Int) case class Part2(id: Int) case class Part3(id: Int) 上述所有零件均包含在以下零件类别中: case class Parts(part1: Option[Part1], part2: Option[Part2], part3: Option[Part3]) 现在,在我的代码中,我有: case (maybePart1, maybePart2, maybePart3) =
case class Part1(id: Int)
case class Part2(id: Int)
case class Part3(id: Int)
上述所有零件均包含在以下零件类别中:
case class Parts(part1: Option[Part1], part2: Option[Part2], part3: Option[Part3])
现在,在我的代码中,我有:
case (maybePart1, maybePart2, maybePart3) =>
Parts(maybePart1, maybePart2, maybePart3)
但我真正想做的是,如果它们都是None,则返回None,否则返回我在上面所做的
如何执行此操作?如果所有的case语句都是
None
,请为其添加另一个case语句:
case (None, None, None) => None
case (maybePart1, maybePart2, maybePart3) =>
Some(Parts(maybePart1, maybePart2, maybePart3))
如果案例都是
None
,只需为案例添加另一个案例语句即可:
case (None, None, None) => None
case (maybePart1, maybePart2, maybePart3) =>
Some(Parts(maybePart1, maybePart2, maybePart3))