Scala 案例类查询参数-招摇过市单据
我正在为我的应用程序编写一个API。 该应用程序允许管理员使用查询参数搜索用户 我的问题 在我的控制器中有很多查询参数,它们占用了很多空间。目前,我已通过将所有QueryParameters作为方法中的参数来解决此问题,如下所示:Scala 案例类查询参数-招摇过市单据,scala,spring-boot,refactoring,swagger,openapi,Scala,Spring Boot,Refactoring,Swagger,Openapi,我正在为我的应用程序编写一个API。 该应用程序允许管理员使用查询参数搜索用户 我的问题 在我的控制器中有很多查询参数,它们占用了很多空间。目前,我已通过将所有QueryParameters作为方法中的参数来解决此问题,如下所示: def findUser ( @ApiParam(name = "firstName", value = "First name", `type` = "query") @RequestParam(value = "f
def findUser (
@ApiParam(name = "firstName", value = "First name", `type` = "query")
@RequestParam(value = "firstName", required = false) firstName: String,
@ApiParam(name = "surname", value = "Surname", `type` = "query")
@RequestParam(value = "surname", required = false) surname: String,
@ApiParam(name = "email", value = "Email adress", `type` = "query")
@RequestParam(value = "email", required = false) email: String,
@ApiParam(name = "telephoneNumber", value = "Phone number", `type` = "query")
@RequestParam(value = "telephoneNumber", required = false) telephoneNumber: String,
@ApiParam(name = "landlineNumber", value = "Land line number", `type` = "query")
@RequestParam(value = "landlineNumber", required = false) landlineNumber: String,
@ApiParam(name = "dateOfBirth", value = "Date of Birth", `type` = "query")
@RequestParam(value = "dateOfBirth", required = false) dateOfBirth: String,
@ApiParam(name = "postalAddress", value = "Postal adress", `type` = "query")
@RequestParam(value = "postalAddress", required = false) postalAddress: String,
@ApiParam(name = "postCode", value = "Post code", `type` = "query")
@RequestParam(value = "postCode", required = false) postCode: String
) = {
// doing stuff
}
问题:
有没有办法将所有查询参数提取到Swagger文档中的类或对象中?如下图所示:
def allQueryParamsInACaseClass (
queryParams : AllQueryParams
)
我使用
@modeldattribute
修复了它,然后用@BeanProperties
创建了一个case类
def allQueryParamsInACaseClass (
@ModelAttribute queryParams: AllQueryParams
)
case class AllQueryParams (
...
@ApiParam(name = "firstName", value = "First name", `type` = "query")
@RequestParam(value = "firstName", required = false) @BeanProperty firstName: String,
..
)