Select 每天为最新值创建视图(无跳过的天数)
我有一个每天记录每个设备固件版本的表。如果设备出现故障,则用于填充设备固件的脚本将无法达到该值,因此没有脱机天数的记录。我需要一个视图,该视图将每天返回每个设备的最新固件版本,无论设备是否已关闭。这在Postgres SQL中非常有效:Select 每天为最新值创建视图(无跳过的天数),select,subquery,case,where-clause,denodo,Select,Subquery,Case,Where Clause,Denodo,我有一个每天记录每个设备固件版本的表。如果设备出现故障,则用于填充设备固件的脚本将无法达到该值,因此没有脱机天数的记录。我需要一个视图,该视图将每天返回每个设备的最新固件版本,无论设备是否已关闭。这在Postgres SQL中非常有效: SELECT d.ip, d.date, CASE WHEN f.firmware_version IS NOT NULL THEN f.firmware_version ELSE (--Use last
SELECT
d.ip,
d.date,
CASE
WHEN f.firmware_version IS NOT NULL THEN f.firmware_version
ELSE (--Use last available firmware_version for the device:
SELECT l.firmware_version
FROM firmware l
WHERE l.date < d.date AND l.firmware_version IS NOT NULL
ORDER BY l.date DESC
LIMIT 1)
END AS firmware_version
FROM
devices d --Table with a record for every device every day
LEFT JOIN firmware f ON d.date = f.date AND d.ip = f.ip
然而,我们正在过渡到Denodo,我无法让这个查询在Denodo中工作。case语句中的子查询似乎失败了。有人知道我如何用这样的逻辑在Denodo中创建视图吗?我想出来了!它有点长,有点复杂,但它的工作方式正是我所希望的。如果对其他人有帮助,以下是解决方案:
--Get all values of firmware prior to the listed date
--Note: Will need to find the latest firmware for each date in a later step
WITH firmware_prep (
ip,
date_main,
date_firmware,
firmware
) AS (
SELECT
d.ip,
d.date,
f.date,
f.firmware
FROM
device d LEFT JOIN
firmware f ON (d.ip = f.ip AND f.date <= d.date AND f.firmware IS NOT NULL)
)
SELECT
s.ip,
s.date_main AS date,
f.firmware
FROM
(--Here's where you find which firmware date is the latest available date for each listed date:
SELECT
ip,
date_main,
MAX(date_firmware) AS select_date
FROM
firmware_prep
GROUP BY
ip,
date_main
) s LEFT JOIN
firmware f ON s.select_date = f.date AND s.ip = f.ip