Sequelize.js 拆下'；包括'；响应中的表名-Sequelize

你好，我有以下问题：

    const availAll = await InstructorAvail.findAll({
        raw: true,
        where: {
            [Op.or]: [
                { date: sun, instructorId: instructorId },
                { date: mon, instructorId: instructorId },
                { date: tues, instructorId: instructorId },
                { date: wed, instructorId: instructorId },
                { date: thurs, instructorId: instructorId },
                { date: fri, instructorId: instructorId },
                { date: sat, instructorId: instructorId },
            ],
        },
        include: [{ model: Timeslots, required: true }],
    })

这将返回以下内容，我希望实现的是删除“时间段”：

        {
            "uuid": "cef9aff7-2b2a-4ac4-aa19-95003f5ee00c",
            "date": "09May21",
            "timeslot": "480",
            "timeslotid": 29,
            "status": 1,
            "instructorId": 69,
            "createdAt": "2021-05-10T20:46:45.000Z",
            "updatedAt": "2021-05-10T20:46:45.000Z",
            "Timeslots.id": 29,
            "Timeslots.uuid": "0ff2019f-336c-439b-8876-fb4a44651556",
            "Timeslots.time_integer": 480,
            "Timeslots.name": "08:00 am",
            "Timeslots.period": "morning",
            "Timeslots.createdAt": "2021-05-10T18:52:37.000Z",
            "Timeslots.updatedAt": "2021-05-10T18:52:37.000Z"
        },

我想使用属性简化json，并从响应中删除“时间段”：

    const availAll = await InstructorAvail.findAll({
        raw: true,
        where: {
            [Op.or]: [
                { date: sun, instructorId: instructorId },
                { date: mon, instructorId: instructorId },
                { date: tues, instructorId: instructorId },
                { date: wed, instructorId: instructorId },
                { date: thurs, instructorId: instructorId },
                { date: fri, instructorId: instructorId },
                { date: sat, instructorId: instructorId },
            ],
        },
        attributes: [
            'id',
            'uuid',
            'date',
            'timeslot',
            'status',
            'instructorId',
            'createdAt',
            'updatedAt',
        ],
        include: [{ 
            model: Timeslots, 
            required: true, 
            attributes: [
              ['Timeslots.name', 'name'],
              ['Timeslots.period', 'period'],
         ]}],
    })

有人知道这是否可能吗

---

提前感谢

所以我最终通过修改代码解决了这个问题，如下所示：

const availAll = await InstructorAvail.findAll({
        raw: true,
        where: {
            [Op.or]: [
                { date: sun, instructorId: instructorId },
                { date: mon, instructorId: instructorId },
                { date: tues, instructorId: instructorId },
                { date: wed, instructorId: instructorId },
                { date: thurs, instructorId: instructorId },
                { date: fri, instructorId: instructorId },
                { date: sat, instructorId: instructorId },
            ],
        },
        attributes: [
            'id',
            'uuid',
            'date',
            'timeslot',
            'status',
            'instructorId',
            'Timeslots.name',  //insert nested table.columnName here
            'Timeslots.period',
        ],
        include: [{ 
            model: Timeslots, 
            required: true, 
            attributes: [] // return nothing from nested table here
        }],
    })

这为我提供了输出：

{
                "id": 9127,
                "uuid": "3d642c18-1e86-419c-8f6d-a6fba772e974",
                "date": "27May21",
                "timeslot": "870",
                "timeslotId": 42,
                "status": 1,
                "instructorId": 69,
                "name": "14:30 am",
                "period": "afternoon"
            },

---

您的示例代码将从响应中删除您不想要的大多数属性，如果您不想要

时隙中的任何属性，请使用
属性：[]
谢谢您的回复，您的建议是解决方案的一部分。我刚刚添加了我需要的完整解决方案。