Servlets Java Servlet，http状态404，请求的资源不可用
我正试图使用EclipseIDE和Tomcat7服务器在java中创建一个servlet。当我在服务器上运行HelloForm时，它会显示表单，但在输入数字并单击“提交”后，它会显示：Servlets Java Servlet，http状态404，请求的资源不可用,servlets,http-status-code-404,Servlets,Http Status Code 404,我正试图使用EclipseIDE和Tomcat7服务器在java中创建一个servlet。当我在服务器上运行HelloForm时，它会显示表单，但在输入数字并单击“提交”后，它会显示： HTTP Status 404 - /Test2/HelloWorld type Status report message /Test2/HelloWorld description The requested resource is not available. Apache Tomcat/7.0.4
HTTP Status 404 - /Test2/HelloWorld
type Status report
message /Test2/HelloWorld
description The requested resource is not available.
Apache Tomcat/7.0.47
<!DOCTYPE html>
<html>
<body>
<form action="HelloWorld" method="post">
Enter 1st number : <input type="text" name="num1"> <br>
Enter 2st number : <input type="text" name="num2"> <br> <input
type="submit">
</form>
</body>
</html>
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance "xmlns= "http://java.sun.com/xml/ns/javaee" xsi: schemaLocation ="http: //java.sun.com/ xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0">
<servlet>
<servlet-name>HelloWorldServlet</servlet-name>
<servlet-class>mypkg.HelloWorld</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>HelloWorldServlet</servlet-name>
<url-pattern>/sayhello</url-pattern>
</servlet-mapping>
</web-app>
<!DOCTYPE html>
<html>
<body>
<form action="HelloWorld" method="post">
Enter 1st number : <input type="text" name="num1"> <br>
Enter 2st number : <input type="text" name="num2"> <br> <input
type="submit">
</form>
</body>
</html>
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance "xmlns= "http://java.sun.com/xml/ns/javaee" xsi: schemaLocation ="http: //java.sun.com/ xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0">
<servlet>
<servlet-name>HelloWorldServlet</servlet-name>
<servlet-class>mypkg.HelloWorld</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>HelloWorldServlet</servlet-name>
<url-pattern>/sayhello</url-pattern>
</servlet-mapping>
</web-app>
HelloWorldServlet
mypkg.HelloWorld
HelloWorldServlet
/打招呼
@WebServlet（“/HelloWorld”）package mypkg;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
@WebServlet("/sayhello")
public class HelloWorld extends HttpServlet {
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
}
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
int num1 = Integer.parseInt(request.getParameter("num1"));
int num2 = Integer.parseInt(request.getParameter("num2"));
int sum = num1 + num2;
System.out.println(sum);
PrintWriter out = response.getWriter();
out.println("Addition : " + sum);
}
}
web.xml@WebServletServlet 3.0<web-app
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
version="3.0">
您错过了
@WebServlet（“/HelloWorld”）package mypkg;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
@WebServlet("/sayhello")
public class HelloWorld extends HttpServlet {
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
}
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
int num1 = Integer.parseInt(request.getParameter("num1"));
int num2 = Integer.parseInt(request.getParameter("num2"));
int sum = num1 + num2;
System.out.println(sum);
PrintWriter out = response.getWriter();
out.println("Addition : " + sum);
}
}
web.xml@WebServletServlet 3.0<web-app
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
version="3.0">
我试过了，但它说javax.servlet.annotation无法解析。我已经添加了web.xml，还指定了servlet名称和servlet映射，但仍然不起作用。您是否在eclipse的项目facets中包含了Apache tomcat运行时？因为servlet JAR是由容器本身提供的。是的，我已经包括了这就是问题所在，现在它可以工作了，谢谢：）我试过了，但它说javax.servlet.annotation无法解析。我已经添加了web.xml，还指定了servlet名称和servlet映射，但仍然不起作用。您是否在eclipse的项目方面包含了Apache tomcat运行时？因为servlet JAR是由容器本身提供的。是的，我已经包括了这就是问题所在，现在它可以工作了。谢谢：）