Spring boot JPA规范筛选嵌套对象

我试图获取嵌套对象属性，但获取illegalArgument异常

AuditTestingPlanSpecification name = new AuditTestingPlanSpecification(new SearchCriteria("auditPlanId.auditPlanEntity", ":",dates));
        Page<AuditTestingPlanMaster> a = auditTestingPlanMasterRepository.findAll(name, ten);

类AuditPlanMaster.java

@Entity
@Table(name = "audit_testing_plan_master")
@Cache(usage = CacheConcurrencyStrategy.NONSTRICT_READ_WRITE)
public class AuditTestingPlanMaster implements Serializable {

    private static final long serialVersionUID = 1L;
    @Id
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "sequenceGenerator")
    @SequenceGenerator(name = "sequenceGenerator")
    private Long id;

    @Column(name = "risk_area_id")
    private Long riskAreaId;

    @Column(name = "expected_revert_date")
    private Instant expectedRevertDate;

    @Column(name = "created_date")
    private Instant createdDate;

    @Column(name = "last_modified_date")
    private Instant lastModifiedDate;

    @JoinColumn(name = "audit_plan_id", referencedColumnName = "id")
    private AuditPlanMaster auditPlanId;

//getters & setters
}

@Entity
@Table(name = "audit_plan_master")
@Cache(usage = CacheConcurrencyStrategy.NONSTRICT_READ_WRITE)
public class AuditPlanMaster implements Serializable {

    private static final long serialVersionUID = 1L;
    @Id
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "sequenceGenerator")
    @SequenceGenerator(name = "sequenceGenerator")
    private Long id;

    @Column(name = "remarks", length = 255)
    private String remarks;

    @Column(name = "audit_plan_entity", length = 50)
    private String auditPlanEntity;

    @Column(name = "start_date")
    private Instant startDate;

    @Column(name = "end_date")
    private Instant endDate;

    //getters & setters

}

我要获取其AuditPlanMaster.auditPlanEntity字符串与提供的筛选器值匹配的所有AuditTestingPlanMaster对象

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提前感谢您的时间和帮助。

我也遇到了同样的问题，下面是我如何处理它的一个片段。我的问题是从内部usuario对象访问id字段时，在我的情况下，id就像您的auditPlanEntity，而usuario就像auditplanMaster：

public static Specification<UsuarioErrorEquipo> usuarioContains(String codigoUsuario) { 
    return (root, query, builder) -> {
        Path<Usuario> u = root.get("usuario");
        return builder.equal(u.get("id"), codigoUsuario);
    };
}

公共静态规范usuarioContains（字符串codigoUsuario）{
返回（根、查询、生成器）->{
路径u=root.get（“usuario”）；
返回生成器。相等（u.get（“id”）、codigoUsuario）；
};
}

我相信，在你的情况下，应该是这样的：

Path<AuditPlanMaster> u = root.get("auditPlanId");
return builder.equal(u.get("auditPlanEntity"), "the value you want to compare");

路径u=root.get（“auditPlanId”）； 返回builder.equal（u.get（“auditPlanEntity”），“要比较的值”）；

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我也有同样的问题，你找到什么了吗？这能回答你的问题吗？

public static Specification<UsuarioErrorEquipo> usuarioContains(String codigoUsuario) { 
    return (root, query, builder) -> {
        Path<Usuario> u = root.get("usuario");
        return builder.equal(u.get("id"), codigoUsuario);
    };
}

Path<AuditPlanMaster> u = root.get("auditPlanId");
return builder.equal(u.get("auditPlanEntity"), "the value you want to compare");