Spring integration 如何在spring integration http入站适配器中验证传入json并返回json响应_Spring Integration_Spring Integration Http

Spring integration 如何在spring integration http入站适配器中验证传入json并返回json响应

spring-integration

Spring integration 如何在spring integration http入站适配器中验证传入json并返回json响应,spring-integration,spring-integration-http,Spring Integration,Spring Integration Http,我正在尝试设置一个只接受json的http:inbound网关。我的xml配置看起来像 <int-http:inbound-gateway id="inboundGateway" supported-methods="POST" request-payload-type="eu.model.MyRequest" request-channel="inputChannel&q

我正在尝试设置一个只接受json的

http:inbound网关。我的xml配置看起来像
<int-http:inbound-gateway id="inboundGateway"
        supported-methods="POST"
        request-payload-type="eu.model.MyRequest"
        request-channel="inputChannel"
        mapped-response-headers="Return-Status, Return-Status-Msg, HTTP_RESPONSE_HEADERS" 
        path="/myService"
        reply-timeout="50000"
        message-converters="converters"
        merge-with-default-converters="false"
        validator="myValidator">
         <int-http:request-mapping consumes="application/json"/>
    </int-http:inbound-gateway>
    
    <util:list id="converters">
      <bean class="org.springframework.http.converter.json.MappingJackson2HttpMessageConverter" />
    </util:list>

我的端点激活器方法看起来像
public Message<MyResponse> handle(Message<MyRequest> message) {
logger.info("Received {}", message);
...}

该组件中的逻辑如下所示：
    message = prepareRequestMessage(servletRequest, httpEntity, headers, payload);
        }
        catch (Exception ex) {
            MessageConversionException conversionException =
                    new MessageConversionException("Cannot create request message", ex);
            MessageChannel errorChannel = getErrorChannel();
            if (errorChannel != null) {
                ErrorMessage errorMessage = buildErrorMessage(null, conversionException);
                if (expectReply) {
                    return this.messagingTemplate.sendAndReceive(errorChannel, errorMessage);
                }
                else {
                    this.messagingTemplate.send(errorChannel, errorMessage);
                    return null;
                }
            }
            else {
                throw conversionException;
            }
        }

因此，如果您为
配置了错误通道
，则可以处理抛出的集成WebExchangeBindexception
，并根据需要生成自定义回复
注意：我们可能需要在文档中提到这种方法。目前，它只指向处理验证错误的标准SpringMVC方法：。请随意提出GH问题 评论不用于扩展讨论；此对话已完成。使用5.4.0版解决了此问题
<body>
<h1>HTTP Status 400 – Bad Request</h1>
<hr class="line" />
<p><b>Type</b> Status Report</p>
<p><b>Message</b> Validation failure</p>
<p><b>Description</b> The server cannot or will not process the request due to something that is perceived to be a
    client error (e.g., malformed request syntax, invalid request message framing, or deceptive request routing).
</p>
<hr class="line" />
<h3>Apache Tomcat/8.5.58</h3>

public class MyRequestValidator implements Validator {

    private static final Logger logger = LoggerFactory.getLogger(MyRequestValidator.class);

    @Override
    public boolean supports(Class<?> clazz) {
        return CisRequest.class.equals(clazz);
    }

    @Override
    public void validate(Object target, Errors errors) {
        logger.debug("validatorCalled");
        ValidationUtils.rejectIfEmptyOrWhitespace(errors, "msisdn", "msisdn.required");
    }

}


    <servlet>
        <servlet-name>inboundGateway</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>\WEB-INF\classes\spring-integration-context.xml</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>
 
    <!-- Note: All <servlet> elements MUST be grouped together and
        placed IN FRONT of the <servlet-mapping> elements -->

    <servlet-mapping>
        <servlet-name>inboundGateway</servlet-name>
        <url-pattern>/*</url-pattern>
    </servlet-mapping>

    message = prepareRequestMessage(servletRequest, httpEntity, headers, payload);
        }
        catch (Exception ex) {
            MessageConversionException conversionException =
                    new MessageConversionException("Cannot create request message", ex);
            MessageChannel errorChannel = getErrorChannel();
            if (errorChannel != null) {
                ErrorMessage errorMessage = buildErrorMessage(null, conversionException);
                if (expectReply) {
                    return this.messagingTemplate.sendAndReceive(errorChannel, errorMessage);
                }
                else {
                    this.messagingTemplate.send(errorChannel, errorMessage);
                    return null;
                }
            }
            else {
                throw conversionException;
            }
        }