Spring mvc cvc complex type.2.4.c:匹配的通配符是严格的,但是找不到元素';构造函数arg';
这是我的spring-security.xmlSpring mvc cvc complex type.2.4.c:匹配的通配符是严格的,但是找不到元素';构造函数arg';,spring-mvc,spring-security,password-encryption,Spring Mvc,Spring Security,Password Encryption,这是我的spring-security.xml <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:util="http://www.springfr
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:util="http://www.springframework.org/schema/util"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.2.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.2.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util-3.1.xsd">
<http auto-config="true" use-expressions="true">
<intercept-url pattern="/admin**" access="hasRole('ROLE_ADMIN')" />
<intercept-url pattern="/signup" access="permitAll"></intercept-url>
<intercept-url pattern="/signin" access="permitAll"></intercept-url>
<intercept-url pattern="/logout" access="permitAll"></intercept-url>
<intercept-url pattern="/denied" access="permitAll"></intercept-url>
<intercept-url pattern="/**" access="isAuthenticated()"></intercept-url>
<access-denied-handler error-page="/403" />
<form-login login-page="/signin" default-target-url="/home"
authentication-failure-url="/denied" />
<logout logout-success-url="/logout"></logout>
</http>
<authentication-manager>
<authentication-provider>
<password-encoder ref="passwordEncoder" hash="sha-256"/>
<jdbc-user-service data-source-ref="dataSource"
users-by-username-query=
"select email,password, 'true' as enabled from user_login where email=? limit 1"
authorities-by-username-query=
"select email, role from user_roles where email =? " />
</authentication-provider>
</authentication-manager>
<beans:bean id="passwordEncoder" class="org.springframework.security.authentication.encoding.ShaPasswordEncoder">
<constructor-arg value="256"/>
</beans:bean>
</beans:beans>
我得到了这个错误
cvc复杂类型.2.4.c:匹配的通配符是严格的,但找不到元素“构造函数arg”的声明。
-安全命名空间不支持元素[constructor arg]的修饰
-配置问题:安全命名空间不支持元素[constructor arg]的修饰有问题的资源:文件(项目路径)
我如何解决这个错误
。我想输入密码并检查密码是否与数据库密码匹配。我认为问题在于
beans
不是默认名称空间。所以你可以试试
<beans:bean id="passwordEncoder" class="org.springframework.security.authentication.encoding.ShaPasswordEncoder">
<beans:constructor-arg value="256"/>
或者将bean声明为默认名称空间
<beans xmlns="http://www.springframework.org/schema/beans"
我认为问题在于bean
不是默认名称空间。所以你可以试试
<beans:bean id="passwordEncoder" class="org.springframework.security.authentication.encoding.ShaPasswordEncoder">
<beans:constructor-arg value="256"/>
或者将bean声明为默认名称空间
<beans xmlns="http://www.springframework.org/schema/beans"