Sql server 2008 如何求一组和？SQL Server 2008

我有一个查询，其中有一个sum，如下所示：

SELECT
    Table1.ID, SUM(Table2.[Number1] + Table2.[Number2]) AS SumColumn
FROM         Table1 INNER JOIN
                      Table3 ON Table1.ID = Table3.ID 
                    INNER JOIN
                      Table2 ON Table3.ID = Table2.ID
WHERE     (Table2.[Something] = 'Whatever')

GROUP BY Table1.ID,  Table2.[Number1] , Table2.[Number2]

ID  SumColumn
67  1
67  4
70  2
70  6
70  3
70  6
80  5
97  1
97  3

它给了我一张这样的桌子：

SELECT
    Table1.ID, SUM(Table2.[Number1] + Table2.[Number2]) AS SumColumn
FROM         Table1 INNER JOIN
                      Table3 ON Table1.ID = Table3.ID 
                    INNER JOIN
                      Table2 ON Table3.ID = Table2.ID
WHERE     (Table2.[Something] = 'Whatever')

GROUP BY Table1.ID,  Table2.[Number1] , Table2.[Number2]

ID  SumColumn
67  1
67  4
70  2
70  6
70  3
70  6
80  5
97  1
97  3

我怎样才能让它给我一个这样的表，其中SumColumn被求和，按ID列分组

ID   SumColumn
67   5
70   17
80   5
97   4

我无法按SumColumn分组，因为我收到一个错误，该错误导致列名“SumColumn”无效。联合也不起作用。提前谢谢

编辑：

仅按ID进行分组就产生了一个错误：

[Number1、Number2和我正在选择的其他列名]在选择列表中无效，因为它不包含在聚合函数或GROUP BY子句中

编辑2

不知道为什么，只是按Table.ID进行分组现在似乎起作用了。感谢所有贴出正确答案的人，我希望我能全部勾选

您是否尝试过：

SELECT
    Table1.ID, SUM(Table2.[Number1] + Table2.[Number2]) AS SumColumn
FROM         Table1 INNER JOIN
                      Table3 ON Table1.ID = Table3.ID 
                    INNER JOIN
                      Table2 ON Table3.ID = Table2.ID
WHERE     (Table2.[Something] = 'Whatever')
GROUP BY Table1.ID

我不明白为什么上述方法不起作用，除非您在查询中没有适当地为表别名，这更多的是一个语法错误而不是逻辑错误，但无论如何从SQL引擎的角度来看是“错误的”。每当SQL代码对我不起作用时，我都会简化令人厌恶的查询，直到它失败的原因变得明显为止。在这种情况下，我会尝试：

SELECT ID, SUM(sumCol) as SumColumn
FROM (
    SELECT
        Table1.ID, (Table2.[Number1] + Table2.[Number2]) AS sumCol
    FROM         Table1 INNER JOIN
                          Table3 ON Table1.ID = Table3.ID 
                        INNER JOIN
                          Table2 ON Table3.ID = Table2.ID
    WHERE     (Table2.[Something] = 'Whatever')
)
GROUP BY Table1.ID

。。。我允许以下嵌套查询出现任何错误！通知我进一步调查。

试试这个

SELECT
    Table1.ID, SUM(Table2.[Number1] + Table2.[Number2]) AS SumColumn
FROM         Table1 INNER JOIN
                      Table3 ON Table1.ID = Table3.ID 
                    INNER JOIN
                      Table2 ON Table3.ID = Table2.ID
WHERE     (Table2.[Something] = 'Whatever')

GROUP BY Table1.ID

---

听起来您只需要按Table1.ID进行分组

SELECT
    Table1.ID, SUM(Table2.[Number1] + Table2.[Number2]) AS SumColumn
FROM         Table1 INNER JOIN
                      Table3 ON Table1.ID = Table3.ID 
                    INNER JOIN
                      Table2 ON Table3.ID = Table2.ID
WHERE     (Table2.[Something] = 'Whatever')

GROUP BY Table1.ID

由于SUM是一个聚合函数，它将处理将数字分组在一起的问题，因此您只需指定如何对所需的其他列进行分组

[更新]

演示代码：

CREATE TABLE #T1(
    ID      INT
)
CREATE TABLE #T2 (
    ID              INT,
    Something       VARCHAR(32),
    Number1         INT,
    Number2         INT
)
CREATE TABLE #T3 (
    ID      INT
)
DECLARE @Index INT = 0

WHILE @Index < 50
BEGIN
    DECLARE @Something VARCHAR(32) = ''

    SET @Index = @Index + 1
    IF @Index BETWEEN 0 AND 15
        SET @Something = 'Blah'
    ELSE IF @Index BETWEEN 15 AND 40
        SET @Something = 'Whatever'
    ELSE IF @Index BETWEEN 40 AND 50
        SET @Something = 'Bleh'
    INSERT INTO #T1 VALUES(@Index)
    INSERT INTO #T3 VALUES(@Index)
    INSERT INTO #T2 VALUES(@Index, @Something, RAND()*100, RAND() * 100)
    INSERT INTO #T2 VALUES(@Index, @Something, RAND()*100, RAND() * 100)
    INSERT INTO #T2 VALUES(@Index, @Something, RAND()*100, RAND() * 100)
END

SELECT
    #T1.ID, SUM(#T2.Number1 + #T2.Number2) AS SumColumn
FROM         #T1 INNER JOIN
                      #T3 ON #T1.ID = #T3.ID 
                    INNER JOIN
                      #T2 ON #T3.ID = #T2.ID
WHERE     (#T2.Something = 'Whatever')
GROUP BY #T1.ID

---

您是否尝试过嵌套选择

SELECT ID, SUM(SumColumn) AS SumColumn
FROM (SELECT Table1.ID AS ID, SUM(Table2.[Number1] + Table2.[Number2]) AS SumColumn
      FROM Table1 
           INNER JOIN Table3 ON Table1.ID = Table3.ID 
           INNER JOIN Table2 ON Table3.ID = Table2.ID
      WHERE (Table2.[Something] = 'Whatever')
      GROUP BY Table1.ID,  Table2.[Number1] , Table2.[Number2])
GROUP BY ID

---

SELECT Table1.ID….GROUP BY Table1.Att1应给出一个错误，您无法选择ID，因为它不在GROUP BY或聚合函数中-这两个列是否都是同一列，并且您在示例中忘记更改了一个？回复：您最近的编辑该错误是自解释的，不是吗？SUMNumber1+Number2正常。Number1，Number2不是。无法在用于group by子句的group by列表的表达式中使用聚合或子查询。嗯，这对我很有效。我试图复制错误，但没有成功。请参见上面的示例。@billynomates。。。是的，看到了新的和改进的答案：-我不知道刚刚发生了什么。我开始简化，就像你说的那样，去掉内部的SELECT子句，看看这是否有效，但添加了GROUP by。就像你在第一个例子中说的。它起作用了！我所看到的与我出错时没有什么不同，但还是非常感谢。对于阅读本文的其他人来说，我根本不需要嵌套的SELECT，每个最初发布的人都是正确的。@billynomates-无法告诉您完美的SQL没有运行多少次，但像侦探一样逐步调整代码最终完成了这项工作！