Sql server 如何从sql查询中获取批准人的姓名

我有两个Sql Server 2012表，“Person”和“Report”。各表的说明如下所示：

|ReportID|ReportName|ExecutiveApproved|ManagerApproved|StaffApproved|LegalApproved|AccountingApproved|CreatedBy|CreatedDate

人员表（列名：数据类型）：

注：Person表中的“

前缀

”列指另一个名为“

支持类别

”的表；此数值对应于“先生”、“女士”等

报表表（列名：数据类型）：

您能指定我需要的查询，以“

执行批准、管理批准、staffaproved、法律批准、会计批准和CreatedBy

”的格式获取全名吗？预期结果如下所示：

|ReportID|ReportName|ExecutiveApproved|ManagerApproved|StaffApproved|LegalApproved|AccountingApproved|CreatedBy|CreatedDate

只是一个简单的连接：

select r.ReportID,
       r.ReportName,
       p1.LastName + ' ' + ISNULL(c1.Suffix, '') + ', ' + c1.Code + ' ' + p1.FirstName as ExecutiveApproved,
       p2.LastName + ' ' + ISNULL(c2.Suffix, '') + ', ' + c2.Code + ' ' + p2.FirstName as ManagerApproved,
       p3.LastName + ' ' + ISNULL(c3.Suffix, '') + ', ' + c3.Code + ' ' + p3.FirstName as StaffApproved,
       p4.LastName + ' ' + ISNULL(c4.Suffix, '') + ', ' + c4.Code + ' ' + p4.FirstName as LegalApproved,
       p5.LastName + ' ' + ISNULL(c5.Suffix, '') + ', ' + c5.Code + ' ' + p5.FirstName as AccountingApproved,
       r.CreatedBy,
       r.CreatedDate 
from reports r
left join persons p1 on r.ExecutiveApproved = p1.PersonID
left join persons p2 on r.ManagerApproved = p2.PersonID
left join persons p3 on r.StaffApproved = p3.PersonID
left join persons p4 on r.LegalApproved= p4.PersonID
left join persons p5 on r.AccountingApproved = p5.PersonID
left join SupportCategory c1 on p1.Prefix = c1.Prefix 
left join SupportCategory c2 on p2.Prefix = c2.Prefix 
left join SupportCategory c3 on p3.Prefix = c3.Prefix 
left join SupportCategory c4 on p4.Prefix = c4.Prefix 
left join SupportCategory c5 on p5.Prefix = c5.Prefix 

---

基本上，您必须执行一系列从报表表到Person的连接，每个要转换为名称的列对应一个连接。使用左联接，因为Person的每个联接副本将只匹配其中一列。为了多次加入同一个表，必须为其添加别名。然后使用别名选择名称。基本形式如下：

SELECT ReportID, ReportName, 
  (executive.LastName + ' ' + ISNULL([executive.Suffix], '') + ', ' + executive.Prefix + ' ' + executive.FirstName) AS ExecutiveName, 
  <repeat for each of the other columns>
  FROM Report
  LEFT JOIN Person as executive ON Person.id = Report.ExecutiveApproved
  <repeat for each of the other columns>

选择ReportID、ReportName、，
（executive.LastName+''+ISNULL（[executive.Suffix]，''）+，'+executive.Prefix+''+executive.FirstName）作为ExecutiveName，
来自报告
在Person.id=Report.ExecutiveApproved上以执行官的身份左加入Person

我尝试了Giorgi的方法，但我收到了以下错误：Msg 245，16级，状态1，第2行在将varchar值“”转换为数据类型int时失败。@PublicTechie2015，是的，prefixcategory中应该有一些代码列，我已经编辑过。Giorgi，我想我解决了我遇到的错误。我正在测试，乔治，你的解决方案很好用。感谢您的帮助：-）备注：您有许多字段，如[xxxApproved]。这使它变得复杂，将来需要新类型时，您可能会遇到问题。您可以通过创建一个单独的表来改进您的设计，该表包含ReportID、PersonID、FunctionID，然后FunctionID将链接到Executive、Manager等。这样，您就更加灵活，查询也更加方便。

SELECT ReportID, ReportName, 
  (executive.LastName + ' ' + ISNULL([executive.Suffix], '') + ', ' + executive.Prefix + ' ' + executive.FirstName) AS ExecutiveName, 
  <repeat for each of the other columns>
  FROM Report
  LEFT JOIN Person as executive ON Person.id = Report.ExecutiveApproved
  <repeat for each of the other columns>