Sql server 如何从单个select语句中的某个字符分隔的数据的单行中获取多行
在SQL Server 2008或更高版本中,如何在不使用拆分功能的情况下,为单次选择查询中由某个字符分隔的数据从单行中获取唯一的多行 示例:Sql server 如何从单个select语句中的某个字符分隔的数据的单行中获取多行,sql-server,sql-server-2008,sql-server-2008-r2,sql-server-2012,Sql Server,Sql Server 2008,Sql Server 2008 R2,Sql Server 2012,在SQL Server 2008或更高版本中,如何在不使用拆分功能的情况下,为单次选择查询中由某个字符分隔的数据从单行中获取唯一的多行 示例: ID Data Name 1 '2014-01-01,2014-01-02,2014-01-03,2014-01-04' 'A1' 2 '2014-01-01,2014-01-02'
ID Data Name
1 '2014-01-01,2014-01-02,2014-01-03,2014-01-04' 'A1'
2 '2014-01-01,2014-01-02' 'B1'
3 '2014-01-03,2014-01-05,2014-01-06,2014-01-07' 'A1'
ID Data Name
1 '2014-01-01' 'A1'
1 '2014-01-02' 'A1'
1 '2014-01-03' 'A1'
1 '2014-01-04' 'A1'
3 '2014-01-05' 'A1'
3 '2014-01-06' 'A1'
3 '2014-01-07' 'A1'
2 '2014-01-01' 'B1'
2 '2014-01-02' 'B1'
查看这篇关于字符串拆分的SQLSentry文章。如果检查不同的技术,每种技术的速度和任何陷阱 拆分字符串并获取不同的值 下面的代码使用xml拆分器
-- Just playing
use tempdb;
go
-- drop the table
if object_id('results') > 0
drop table results
go
-- create the table
create table results
(
id int,
data varchar(128),
name varchar(2)
);
go
-- add data
insert into results values
(1,'2014-01-01,2014-01-02,2014-01-03,2014-01-04','A1'),
(2,'2014-01-01,2014-01-02','B1'),
(3,'2014-01-03,2014-01-05,2014-01-06,2014-01-07','A1');
go
-- Just the data
select * from results
-- Split the data
select distinct r.id, r.name, s.item
from results r
cross apply dbo.SplitStrings_XML(data, ',') s
这可能会有帮助