Sql server TSQL：全年/每月的连续期间

我试图找到2018年期间每个月至少有一天会员资格的所有客户

我提出了一个解决方案，在每个月初/月中/月末检查他们的会员资格，如下面的代码片段所示，但试图找到更智能的解决方案

我知道我可以使用365天的理货表来检查这一点，但可能有更优雅的解决方案？我对SQL有点陌生，我想我在分组方面遗漏了一些东西

在下面显示的代码片段中，两个Cust都至少有一天的成员资格

期望输出：

代码：

试试这个答案

首先创建一个函数，返回给定日期之间的所有月份和年份

功能：

下面是针对您的需求的T-SQL查询

SELECT CustID
    ,COUNT(DISTINCT [Month]) NoOfMonths
FROM(
    SELECT * 
    FROM #t t
    CROSS APPLY dbo.Fn_GetMonthYear(StartDD,EndDD)
    )D
WHERE [Year] = 2018
GROUP BY CustID
HAVING COUNT(DISTINCT [Month])=12

结果:

查找每个月至少有一天会员资格的所有客户 2018年的月份

我认为这意味着每个客户ID必须在“2018-01-01”和“2018-12-31”之间提供数据

未在所有样本数据中测试此脚本。 但逻辑是明确的，因此可以相应地加以纠正

---

因此，请说明哪些示例数据无效。

给出您的DDL和一些示例数据。这是带有tally的版本：选择不同的custID、datepartmonth、dd-gaps.*、t.dd from gaps join选择前365个cast dateaddday，通过选择1-1在订单上的行数，“2018年1月1日”作为主数据日。StartDD和ENDDDD之间t.dd上的spt_值请尝试我的答案。希望它能帮助你。谢谢你！！！您的Fn_GetMonthYear是特定于用户的，看起来像理货台，对吗？你能告诉我你的fn_的输出是什么，或者把它调整到我以前粘贴的通用计数吗。德克萨斯州again@Mich28，是的，它就像理货表或数字表。@Mich28，这个答案有用吗？谢谢你和所有人

with data as 
(
    select * 
    from (values (1, 1,   '2017-12-11', '2018-01-16'),   (1, 22,  '2018-01-28', '2018-03-9' ), (1, 333, '2018-03-1', '2018-12-31') ,  -- island
                 (22, 1,  '2017-12-31', '2018-01-11'),   (22, 2,  '2017-2-11',  '2019-12-31')) as t (CustID, ContractID, StartDD, EndDD)     ---      
    )
    select 
        isdate(startDD), isdate(EndDD) 
    from 
        data
), gaps as 
(
    select  
        *,  
        datediff(day, lag(EndDD, 1, StartDD) over (partition by CustID order by StartDD), StartDD) as BreakDD          -- negative is island
    from 
        data
)
select 
    *, 
    datepart(month,StartDD) mmS , datepart(month,EndDD) mmE 
from 
    gaps 
    -- and was active any 1+ day during each of the 12 months in 2018    ????
where 
    1 = 1 
    /* and (cast('1/1/2018' as date) between StartDD and EndDD
            or cast('1/15/2018' as date) between StartDD and EndDD     
            or cast('1/31/2018' as date) between StartDD and EndDD)
       ---- etc..  for each month
       and (      cast('12/1/2018'  as date)   between  StartDD  and  EndDD 
              or  cast('12/15/2018' as date)   between  StartDD  and  EndDD  
              or  cast('12/31/2018' as date)   between  StartDD  and  EndDD  
           ) 
*/ 
--select CustID, max(BreakDD) Max_Days
--from gaps
--group by CustID

--SELECT * FROM dbo.Fn_GetMonthYear('2017-12-11','2018-01-16')
ALTER FUNCTION dbo.Fn_GetMonthYear(@StartDate  DATETIME,@EndDate    DATETIME)
RETURNS TABLE
AS

    RETURN(
    SELECT  DATEPART(MONTH, DATEADD(MONTH, x.number, @StartDate)) AS [Month]
            ,DATEPART(YEAR, DATEADD(MONTH, x.number, @StartDate)) AS [Year]
    FROM    master.dbo.spt_values x
    WHERE   x.type = 'P'        
    AND     x.number <= DATEDIFF(MONTH, @StartDate, @EndDate)
    )

CREATE TABLE #t(CustID INT, ContractID INT, StartDD date, EndDD date)

INSERT INTO #t values (1, 1,   '2017-12-11', '2018-01-16'),   (1, 22,  '2018-01-28', '2018-03-9' ), (1, 333, '2018-03-1', '2018-12-31') ,  -- island
                 (22, 1,  '2017-12-31', '2018-01-11'),   (22, 2,  '2017-2-11',  '2019-12-31')

SELECT CustID
    ,COUNT(DISTINCT [Month]) NoOfMonths
FROM(
    SELECT * 
    FROM #t t
    CROSS APPLY dbo.Fn_GetMonthYear(StartDD,EndDD)
    )D
WHERE [Year] = 2018
GROUP BY CustID
HAVING COUNT(DISTINCT [Month])=12

CustID  NoOfMonths
1       12
22      12

CREATE TABLE #t(CustID INT, ContractID INT, StartDD date, EndDD date)

INSERT INTO #t values (1, 1,   '2017-12-11', '2018-01-16'),   (1, 22,  '2018-01-28', '2018-03-9' ), (1, 333, '2018-03-1', '2018-12-31') ,  -- island
 (22, 1,  '2017-12-31', '2018-01-11'),   (22, 2,  '2017-2-11',  '2019-12-31')

declare @From Datetime='2018-01-01'
declare @To datetime='2018-12-31'

;with CTE as
(
select CustID,min(StartDD)StartDD
,max(EndDD)EndDD
from #t
group by CustID
)
select CustID,StartDD
,EndDD
from CTE
where StartDD<=@From and EndDD>=@To