Sql server 获取订单最昂贵的客户的姓名_Sql Server_Sql Server 2008 R2

Sql server 获取订单最昂贵的客户的姓名

sql-server sql-server-2008-r2

Sql server 获取订单最昂贵的客户的姓名,sql-server,sql-server-2008-r2,Sql Server,Sql Server 2008 R2,我有一个包含4个表的小数据库：Customer-Order-OrderLine-Product，我正在处理一些查询，并试图获取订单最昂贵的人的姓名经过一番讨论后，我提出了以下查询，其中显示了所有订单的价格： SELECT SUM(OrderLine.Amount * Product.Price) AS OrderLinePrice, Orders.Id, Customer.Lastname FROM OrderLine, Product, Orders, Customer WHERE Orde

我有一个包含4个表的小数据库：Customer-Order-OrderLine-Product，我正在处理一些查询，并试图获取订单最昂贵的人的姓名

经过一番讨论后，我提出了以下查询，其中显示了所有订单的价格：

SELECT SUM(OrderLine.Amount * Product.Price) AS OrderLinePrice, Orders.Id, Customer.Lastname
FROM OrderLine, Product, Orders, Customer
WHERE OrderLine.ProductId = Product.Id
AND Orders.Id = OrderLine.OrderId
AND Customer.Id = Orders.CustomerId
GROUP BY Orders.Id, Customer.Lastname
ORDER BY OrderLinePrice DESC

现在，从概念上讲，我需要做的，或者我认为我需要做的，是应用MAX（）只选择最高的OrderLinePrice，但SQL Server抱怨无法对包含聚合的表达式执行聚合函数，这并不能让我成功

================更新：

当前我的查询如下所示：

SELECT t.CustomerLastName
FROM (
    SELECT SUM(OrderLine.Amount * Product.Price) AS OrderLinePrice, Orders.Id, Customer.Lastname AS CustomerLastName
    FROM OrderLine, Product, Orders, Customer
    WHERE OrderLine.ProductId = Product.Id
    AND Orders.Id = OrderLine.OrderId
    AND Customer.Id = Orders.CustomerId
    GROUP BY Orders.Id, Customer.Lastname
    ) AS t
WHERE t.OrderLinePrice = 
(
    SELECT MAX(s.OrderLinePrice) AS MaxOrderPrice
    FROM (
        SELECT SUM(OrderLine.Amount * Product.Price) AS OrderLinePrice, Orders.Id, Customer.Lastname AS CustomerLastName
        FROM OrderLine, Product, Orders, Customer
        WHERE OrderLine.ProductId = Product.Id
        AND Orders.Id = OrderLine.OrderId
        AND Customer.Id = Orders.CustomerId
        GROUP BY Orders.Id, Customer.Lastname
        ) AS s
)
ORDER BY CustomerLastName

这将检索其订单价格等于最昂贵订单价格的客户列表。这正是我想要的，但感觉太多余了

我应该如何开始提高效率（如果可能的话）？

您可以通过几种方法来实现这一点。以下是一些建议：

CTE

;WITH CTE
AS
(
    SELECT SUM(OrderLine.Amount * Product.Price) AS OrderLinePrice, 
    Orders.Id, Customer.Lastname
    FROM OrderLine, Product, Orders, Customer
    WHERE OrderLine.ProductId = Product.Id
    AND Orders.Id = OrderLine.OrderId
    AND Customer.Id = Orders.CustomerId
    GROUP BY Orders.Id, Customer.Lastname
)
SELECT
    MAX(OrderLinePrice) AS MaxorderPrice
FROM
    CTE

具有最大值的子查询

SELECT MAX(t.OrderLinePrice) AS MaxorderPrice FROM ( SELECT SUM(OrderLine.Amount * Product.Price) AS OrderLinePrice, Orders.Id, Customer.Lastname FROM OrderLine, Product, Orders, Customer WHERE OrderLine.ProductId = Product.Id AND Orders.Id = OrderLine.OrderId AND Customer.Id = Orders.CustomerId GROUP BY Orders.Id, Customer.Lastname ) AS t
排名靠前1的订单商

SELECT TOP 1 t.Amount FROM ( SELECT SUM(OrderLine.Amount * Product.Price) AS OrderLinePrice, Orders.Id, Customer.Lastname FROM OrderLine, Product, Orders, Customer WHERE OrderLine.ProductId = Product.Id AND Orders.Id = OrderLine.OrderId AND Customer.Id = Orders.CustomerId GROUP BY Orders.Id, Customer.Lastname ) AS t ORDER BY t.OrderLinePrice DESC
编辑
也许是这样的：

;WITH CTE AS ( SELECT SUM(OrderLine.Amount * Product.Price) AS OrderLinePrice, Orders.Id, Customer.Lastname FROM OrderLine, Product, Orders, Customer WHERE OrderLine.ProductId = Product.Id AND Orders.Id = OrderLine.OrderId AND Customer.Id = Orders.CustomerId GROUP BY Orders.Id, Customer.Lastname ) SELECT * FROM CTE WHERE CTE.OrderLinePrice=(SELECT MAX(CTE2.OrderLinePrice) FROM CTE AS CTE2)

;WITH CTE AS ( SELECT SUM(OrderLine.Amount * Product.Price) AS OrderLinePrice, Orders.Id, Customer.Lastname FROM OrderLine, Product, Orders, Customer WHERE OrderLine.ProductId = Product.Id AND Orders.Id = OrderLine.OrderId AND Customer.Id = Orders.CustomerId GROUP BY Orders.Id, Customer.Lastname ) SELECT MAX(OrderLinePrice) AS MaxPrice, Lastname FROM CTE GROUP BY CTE.Lastname

WITH ranked AS ( SELECT SUM(ol.Amount * p.Price) AS OrderLinePrice, o.Id, c.Lastname AS CustomerLastName FROM OrderLine ol INNER JOIN Product p ON p.Id = ol.ProductId INNER JOIN Orders o ON o.Id = ol.OrderId INNER JOIN Customer c ON c.Id = o.CustomerId GROUP BY Orders.Id, Customer.Lastname ) SELECT * FROM ( SELECT TOP (1) WITH TIES CustomerLastName FROM ranked ORDER BY OrderLinePrice DESC ) s ORDER BY CustomerLastName

WITH ranked AS ( SELECT SUM(ol.Amount * p.Price) AS OrderLinePrice, o.Id, c.Lastname AS CustomerLastName, RANK() OVER (ORDER BY SUM(ol.Amount * p.Price) DESC) AS rnk FROM OrderLine ol INNER JOIN Product p ON p.Id = ol.ProductId INNER JOIN Orders o ON o.Id = ol.OrderId INNER JOIN Customer c ON c.Id = o.CustomerId GROUP BY Orders.Id, Customer.Lastname ) SELECT CustomerLastName FROM ranked WHERE rnk = 1 ORDER BY CustomerLastName
或者，如果您希望按客户姓氏计算最大值。您可以这样做：

;WITH CTE AS ( SELECT SUM(OrderLine.Amount * Product.Price) AS OrderLinePrice, Orders.Id, Customer.Lastname FROM OrderLine, Product, Orders, Customer WHERE OrderLine.ProductId = Product.Id AND Orders.Id = OrderLine.OrderId AND Customer.Id = Orders.CustomerId GROUP BY Orders.Id, Customer.Lastname ) SELECT * FROM CTE WHERE CTE.OrderLinePrice=(SELECT MAX(CTE2.OrderLinePrice) FROM CTE AS CTE2)

;WITH CTE AS ( SELECT SUM(OrderLine.Amount * Product.Price) AS OrderLinePrice, Orders.Id, Customer.Lastname FROM OrderLine, Product, Orders, Customer WHERE OrderLine.ProductId = Product.Id AND Orders.Id = OrderLine.OrderId AND Customer.Id = Orders.CustomerId GROUP BY Orders.Id, Customer.Lastname ) SELECT MAX(OrderLinePrice) AS MaxPrice, Lastname FROM CTE GROUP BY CTE.Lastname

WITH ranked AS ( SELECT SUM(ol.Amount * p.Price) AS OrderLinePrice, o.Id, c.Lastname AS CustomerLastName FROM OrderLine ol INNER JOIN Product p ON p.Id = ol.ProductId INNER JOIN Orders o ON o.Id = ol.OrderId INNER JOIN Customer c ON c.Id = o.CustomerId GROUP BY Orders.Id, Customer.Lastname ) SELECT * FROM ( SELECT TOP (1) WITH TIES CustomerLastName FROM ranked ORDER BY OrderLinePrice DESC ) s ORDER BY CustomerLastName

WITH ranked AS ( SELECT SUM(ol.Amount * p.Price) AS OrderLinePrice, o.Id, c.Lastname AS CustomerLastName, RANK() OVER (ORDER BY SUM(ol.Amount * p.Price) DESC) AS rnk FROM OrderLine ol INNER JOIN Product p ON p.Id = ol.ProductId INNER JOIN Orders o ON o.Id = ol.OrderId INNER JOIN Customer c ON c.Id = o.CustomerId GROUP BY Orders.Id, Customer.Lastname ) SELECT CustomerLastName FROM ranked WHERE rnk = 1 ORDER BY CustomerLastName

你可以通过两种方式来做到这一点。以下是一些建议：
CTE

;WITH CTE AS ( SELECT SUM(OrderLine.Amount * Product.Price) AS OrderLinePrice, Orders.Id, Customer.Lastname FROM OrderLine, Product, Orders, Customer WHERE OrderLine.ProductId = Product.Id AND Orders.Id = OrderLine.OrderId AND Customer.Id = Orders.CustomerId GROUP BY Orders.Id, Customer.Lastname ) SELECT MAX(OrderLinePrice) AS MaxorderPrice FROM CTE
具有最大值的子查询

SELECT MAX(t.OrderLinePrice) AS MaxorderPrice FROM ( SELECT SUM(OrderLine.Amount * Product.Price) AS OrderLinePrice, Orders.Id, Customer.Lastname FROM OrderLine, Product, Orders, Customer WHERE OrderLine.ProductId = Product.Id AND Orders.Id = OrderLine.OrderId AND Customer.Id = Orders.CustomerId GROUP BY Orders.Id, Customer.Lastname ) AS t
排名靠前1的订单商

SELECT TOP 1 t.Amount FROM ( SELECT SUM(OrderLine.Amount * Product.Price) AS OrderLinePrice, Orders.Id, Customer.Lastname FROM OrderLine, Product, Orders, Customer WHERE OrderLine.ProductId = Product.Id AND Orders.Id = OrderLine.OrderId AND Customer.Id = Orders.CustomerId GROUP BY Orders.Id, Customer.Lastname ) AS t ORDER BY t.OrderLinePrice DESC
编辑
也许是这样的：

;WITH CTE AS ( SELECT SUM(OrderLine.Amount * Product.Price) AS OrderLinePrice, Orders.Id, Customer.Lastname FROM OrderLine, Product, Orders, Customer WHERE OrderLine.ProductId = Product.Id AND Orders.Id = OrderLine.OrderId AND Customer.Id = Orders.CustomerId GROUP BY Orders.Id, Customer.Lastname ) SELECT * FROM CTE WHERE CTE.OrderLinePrice=(SELECT MAX(CTE2.OrderLinePrice) FROM CTE AS CTE2)

;WITH CTE AS ( SELECT SUM(OrderLine.Amount * Product.Price) AS OrderLinePrice, Orders.Id, Customer.Lastname FROM OrderLine, Product, Orders, Customer WHERE OrderLine.ProductId = Product.Id AND Orders.Id = OrderLine.OrderId AND Customer.Id = Orders.CustomerId GROUP BY Orders.Id, Customer.Lastname ) SELECT MAX(OrderLinePrice) AS MaxPrice, Lastname FROM CTE GROUP BY CTE.Lastname

WITH ranked AS ( SELECT SUM(ol.Amount * p.Price) AS OrderLinePrice, o.Id, c.Lastname AS CustomerLastName FROM OrderLine ol INNER JOIN Product p ON p.Id = ol.ProductId INNER JOIN Orders o ON o.Id = ol.OrderId INNER JOIN Customer c ON c.Id = o.CustomerId GROUP BY Orders.Id, Customer.Lastname ) SELECT * FROM ( SELECT TOP (1) WITH TIES CustomerLastName FROM ranked ORDER BY OrderLinePrice DESC ) s ORDER BY CustomerLastName

WITH ranked AS ( SELECT SUM(ol.Amount * p.Price) AS OrderLinePrice, o.Id, c.Lastname AS CustomerLastName, RANK() OVER (ORDER BY SUM(ol.Amount * p.Price) DESC) AS rnk FROM OrderLine ol INNER JOIN Product p ON p.Id = ol.ProductId INNER JOIN Orders o ON o.Id = ol.OrderId INNER JOIN Customer c ON c.Id = o.CustomerId GROUP BY Orders.Id, Customer.Lastname ) SELECT CustomerLastName FROM ranked WHERE rnk = 1 ORDER BY CustomerLastName
或者，如果您希望按客户姓氏计算最大值。您可以这样做：

;WITH CTE AS ( SELECT SUM(OrderLine.Amount * Product.Price) AS OrderLinePrice, Orders.Id, Customer.Lastname FROM OrderLine, Product, Orders, Customer WHERE OrderLine.ProductId = Product.Id AND Orders.Id = OrderLine.OrderId AND Customer.Id = Orders.CustomerId GROUP BY Orders.Id, Customer.Lastname ) SELECT * FROM CTE WHERE CTE.OrderLinePrice=(SELECT MAX(CTE2.OrderLinePrice) FROM CTE AS CTE2)

;WITH CTE AS ( SELECT SUM(OrderLine.Amount * Product.Price) AS OrderLinePrice, Orders.Id, Customer.Lastname FROM OrderLine, Product, Orders, Customer WHERE OrderLine.ProductId = Product.Id AND Orders.Id = OrderLine.OrderId AND Customer.Id = Orders.CustomerId GROUP BY Orders.Id, Customer.Lastname ) SELECT MAX(OrderLinePrice) AS MaxPrice, Lastname FROM CTE GROUP BY CTE.Lastname

WITH ranked AS ( SELECT SUM(ol.Amount * p.Price) AS OrderLinePrice, o.Id, c.Lastname AS CustomerLastName FROM OrderLine ol INNER JOIN Product p ON p.Id = ol.ProductId INNER JOIN Orders o ON o.Id = ol.OrderId INNER JOIN Customer c ON c.Id = o.CustomerId GROUP BY Orders.Id, Customer.Lastname ) SELECT * FROM ( SELECT TOP (1) WITH TIES CustomerLastName FROM ranked ORDER BY OrderLinePrice DESC ) s ORDER BY CustomerLastName

WITH ranked AS ( SELECT SUM(ol.Amount * p.Price) AS OrderLinePrice, o.Id, c.Lastname AS CustomerLastName, RANK() OVER (ORDER BY SUM(ol.Amount * p.Price) DESC) AS rnk FROM OrderLine ol INNER JOIN Product p ON p.Id = ol.ProductId INNER JOIN Orders o ON o.Id = ol.OrderId INNER JOIN Customer c ON c.Id = o.CustomerId GROUP BY Orders.Id, Customer.Lastname ) SELECT CustomerLastName FROM ranked WHERE rnk = 1 ORDER BY CustomerLastName

首先，您是否考虑过使用显式联接？这可能只是口味的问题，但您可能会发现使用显式连接的查询比使用隐式连接（或“逗号”连接）的查询更清晰，如您的示例中所示
关于这个问题，你可以使用带领带的
TOP（1），如下所示： ;WITH CTE AS ( SELECT SUM(OrderLine.Amount * Product.Price) AS OrderLinePrice, Orders.Id, Customer.Lastname FROM OrderLine, Product, Orders, Customer WHERE OrderLine.ProductId = Product.Id AND Orders.Id = OrderLine.OrderId AND Customer.Id = Orders.CustomerId GROUP BY Orders.Id, Customer.Lastname ) SELECT * FROM CTE WHERE CTE.OrderLinePrice=(SELECT MAX(CTE2.OrderLinePrice) FROM CTE AS CTE2) ;WITH CTE AS ( SELECT SUM(OrderLine.Amount * Product.Price) AS OrderLinePrice, Orders.Id, Customer.Lastname FROM OrderLine, Product, Orders, Customer WHERE OrderLine.ProductId = Product.Id AND Orders.Id = OrderLine.OrderId AND Customer.Id = Orders.CustomerId GROUP BY Orders.Id, Customer.Lastname ) SELECT MAX(OrderLinePrice) AS MaxPrice, Lastname FROM CTE GROUP BY CTE.Lastname WITH ranked AS ( SELECT SUM(ol.Amount * p.Price) AS OrderLinePrice, o.Id, c.Lastname AS CustomerLastName FROM OrderLine ol INNER JOIN Product p ON p.Id = ol.ProductId INNER JOIN Orders o ON o.Id = ol.OrderId INNER JOIN Customer c ON c.Id = o.CustomerId GROUP BY Orders.Id, Customer.Lastname ) SELECT * FROM ( SELECT TOP (1) WITH TIES CustomerLastName FROM ranked ORDER BY OrderLinePrice DESC ) s ORDER BY CustomerLastName WITH ranked AS ( SELECT SUM(ol.Amount * p.Price) AS OrderLinePrice, o.Id, c.Lastname AS CustomerLastName, RANK() OVER (ORDER BY SUM(ol.Amount * p.Price) DESC) AS rnk FROM OrderLine ol INNER JOIN Product p ON p.Id = ol.ProductId INNER JOIN Orders o ON o.Id = ol.OrderId INNER JOIN Customer c ON c.Id = o.CustomerId GROUP BY Orders.Id, Customer.Lastname ) SELECT CustomerLastName FROM ranked WHERE rnk = 1 ORDER BY CustomerLastName 如果您只对最高的总价感兴趣，RANK（）就足够了，但是如果您希望客户获得最高的n 总价，请使用densite\u RANK（）代替，并将条件从rnk=1 更改为rnk，首先，您考虑过使用显式联接吗？这可能只是口味的问题，但您可能会发现使用显式连接的查询比使用隐式连接（或“逗号”连接）的查询更清晰，如您的示例中所示关于这个问题，你可以使用带领带的TOP（1），如下所示： ;WITH CTE AS ( SELECT SUM(OrderLine.Amount * Product.Price) AS OrderLinePrice, Orders.Id, Customer.Lastname FROM OrderLine, Product, Orders, Customer WHERE OrderLine.ProductId = Product.Id AND Orders.Id = OrderLine.OrderId AND Customer.Id = Orders.CustomerId GROUP BY Orders.Id, Customer.Lastname ) SELECT * FROM CTE WHERE CTE.OrderLinePrice=(SELECT MAX(CTE2.OrderLinePrice) FROM CTE AS CTE2) ;WITH CTE AS ( SELECT SUM(OrderLine.Amount * Product.Price) AS OrderLinePrice, Orders.Id, Customer.Lastname FROM OrderLine, Product, Orders, Customer WHERE OrderLine.ProductId = Product.Id AND Orders.Id = OrderLine.OrderId AND Customer.Id = Orders.CustomerId GROUP BY Orders.Id, Customer.Lastname ) SELECT MAX(OrderLinePrice) AS MaxPrice, Lastname FROM CTE GROUP BY CTE.Lastname WITH ranked AS ( SELECT SUM(ol.Amount * p.Price) AS OrderLinePrice, o.Id, c.Lastname AS CustomerLastName FROM OrderLine ol INNER JOIN Product p ON p.Id = ol.ProductId INNER JOIN Orders o ON o.Id = ol.OrderId INNER JOIN Customer c ON c.Id = o.CustomerId GROUP BY Orders.Id, Customer.Lastname ) SELECT * FROM ( SELECT TOP (1) WITH TIES CustomerLastName FROM ranked ORDER BY OrderLinePrice DESC ) s ORDER BY CustomerLastName WITH ranked AS ( SELECT SUM(ol.Amount * p.Price) AS OrderLinePrice, o.Id, c.Lastname AS CustomerLastName, RANK() OVER (ORDER BY SUM(ol.Amount * p.Price) DESC) AS rnk FROM OrderLine ol INNER JOIN Product p ON p.Id = ol.ProductId INNER JOIN Orders o ON o.Id = ol.OrderId INNER JOIN Customer c ON c.Id = o.CustomerId GROUP BY Orders.Id, Customer.Lastname ) SELECT CustomerLastName FROM ranked WHERE rnk = 1 ORDER BY CustomerLastName 如果您只对最高的总价感兴趣，RANK（）就足够了，但是如果您希望客户获得最高的n 总价，请使用densite\u RANK（），并将条件从rnk=1 更改为rnk您使用的是什么版本的sql server？我已经有一段时间没有使用sql了，但是如何“选择前1名金额（订单行金额…）？假设您只需要一个结果…我正在查找订单与最昂贵订单一样昂贵的客户列表（请参见编辑）您使用的是什么版本的sql server？我已经有一段时间没有使用sql了，但是“选择前1名金额（OrderLine.Amt…）怎么样？假设您只需要一个结果…我正在查找订单与最昂贵订单一样昂贵的客户列表（请参见编辑）几乎：）我需要订单最昂贵的人的姓名列表。因此，基本上我需要这个列表来获取最昂贵订单的价格，然后将该值作为分隔符发送给同一个查询..听起来效率很低：）那么您需要哪位客户。如果您像现在这样订购OrderLinePrice。您将获得该列表，您正在接受关于。或者你如何限制他们更多？我正在寻找订单价格等于最高价格的客户列表。这看起来像：选择t.CustomerLastName FROM（选择SUM（OrderLine.Amount*Product.price）作为OrderLinePrice，Orders.Id，Customer.Lastname作为CustomerLastName，来自OrderLine，Product，Orders，Customer，其中OrderLine.ProductId=Product.Id和Orders.Id=OrderLine.OrderId和Customer.Id=Orders.CustomerId按Orders.Id分组，Customer.Lastname）作为t，其中t.OrderLinePrice=（//查询以获取最昂贵订单的价格），但这似乎有点多余：）更新了答案。查看一下：）我需要拥有最昂贵订单的人员的姓名列表。因此，基本上我需要这个列表来获取最昂贵订单的价格，然后将该值作为分隔符发送给同一个查询..听起来效率很低：）那么您需要哪个客户。如果您像现在一样订购OrderLinePrice，您将获取您要查看的列表。或者如何限制它们？我正在查找订单价格等于最高价格的客户列表。该列表如下所示：选择t.CustomerLastName FROM（选择SUM（OrderLine.Amount*Product.price）作为OrderLinePrice，Orders.Id，Customer.Lastname作为CustomerLastName，来自OrderLine，Product，Orders，Customer，其中OrderLine.ProductId=Product.Id和Orders.Id=OrderLine.OrderId和Customer.Id=Orders.CustomerId按Orders.Id分组，Customer.Lastname）作为t，其中t.OrderLinePrice=（//查询以获取最昂贵订单的价格）但这似乎有些多余：）更新了答案。请查看