Sql server 带总和的不同行

我有一张费用表

DECLARE @EXPENSE TABLE
(
    ID INT,
    CURRENCY NVARCHAR(4),
    AMOUNT   MONEY
)

INSERT INTO @EXPENSE VALUES
(1,'USD',100),
(2,'USD',10),
(1,'USD',80),
(2,'USD',5),
(1,'EUR',80),
(1,'EUR',30),
(3,'USD',20)

数据如下：

+----+----------+--------+
| ID | CURRENCY | AMOUNT |
+----+----------+--------+
| 1  | USD      | 100    |
+----+----------+--------+
| 2  | USD      | 10     |
+----+----------+--------+
| 1  | USD      | 80     |
+----+----------+--------+
| 2  | USD      | 5      |
+----+----------+--------+
| 1  | EUR      | 80     |
+----+----------+--------+
| 1  | EUR      | 30     |
+----+----------+--------+
| 3  | USD      | 20     |
+----+----------+--------+

我希望得到这样的结果

+----+----------+--------+
| ID | CURRENCY | AMOUNT |
+----+----------+--------+
| 1  | EUR      | 110    |
+----+----------+--------+
| 1  | USD      | 180    |
+----+----------+--------+
| 2  | USD      | 15     |
+----+----------+--------+
| 2  | EUR      | 0      |
+----+----------+--------+
| 3  | USD      | 20     |
+----+----------+--------+
| 3  | EUR      | 0      |
+----+----------+--------+

我写了以下内容：

SELECT E.ID, E.CURRENCY, SUM(E.AMOUNT) AS AMOUNT
FROM @EXPENSE AS E
GROUP BY E.ID, E.CURRENCY

但它并没有给我缺少的货币和零金额

---

有人能帮忙吗？

您需要将不同ID和不同货币进行

交叉连接，然后将
左连接到表中进行聚合：

SELECT i.ID, c.CURRENCY,
       COALESCE(SUM(AMOUNT), 0) TOTAL
FROM (SELECT DISTINCT ID FROM @EXPENSE) i
CROSS JOIN (SELECT DISTINCT CURRENCY FROM @EXPENSE) c
LEFT JOIN @EXPENSE e ON e.ID = i.ID AND e.CURRENCY = c.CURRENCY
GROUP BY i.ID, c.CURRENCY
ORDER BY i.ID, c.CURRENCY

请参阅。

结果:

我认为您的描述中缺少的是，您还希望维护货币类型和金额的占位符。因此，始终会有两种货币类型（美元、欧元），但它们不一定总是有金额，在这种情况下，您希望它默认为0。这准确吗？
> ID | CURRENCY |    TOTAL
> -: | :------- | -------:
>  1 | EUR      |    110
>  1 | USD      |    180
>  2 | EUR      |      0
>  2 | USD      |     15
>  3 | EUR      |      0
>  3 | USD      |     20