Sql server 在SQLServer2005（基于集合的方法）中查找范围之间的值？

我有一张像这样的桌子

Id  Value
1   Start
2   Normal
3   End
4   Normal
5   Start
6   Normal
7   Normal
8   End
9   Normal

我必须把输出像

id  Value
1   Start
2   Normal
3   End

5   Start
6   Normal
7   Normal
8   End

i、 e.开始和结束之间的记录。id为4和9的记录在开始和结束之外，因此输出中不存在

如何以基于集合的方式执行此操作（SQLServer2005）？

加载表@t:

declare @t table(Id int,Value nvarchar(100));
insert into @t values (1,'Start'),(2,'Normal'),(3,'End'),(4,'Normal'),(5,'Start'),(6,'Normal'),(7,'Normal'),(8,'End'),(9,'Normal');

查询：

With RangesT as (
    select Id, (select top 1 Id from @t where Id>p.Id and Value='End' order by Id asc) Id_to
    from @t p
    where Value='Start'
)
select crossT.* 
from RangesT p
cross apply (
    select * from @t where Id>=p.Id and Id<=Id_to
) crossT
order by Id

加载一个表@t:

declare @t table(Id int,Value nvarchar(100));
insert into @t values (1,'Start'),(2,'Normal'),(3,'End'),(4,'Normal'),(5,'Start'),(6,'Normal'),(7,'Normal'),(8,'End'),(9,'Normal');

查询：

With RangesT as (
    select Id, (select top 1 Id from @t where Id>p.Id and Value='End' order by Id asc) Id_to
    from @t p
    where Value='Start'
)
select crossT.* 
from RangesT p
cross apply (
    select * from @t where Id>=p.Id and Id<=Id_to
) crossT
order by Id