Sql server 在SQL Server 2008中查找聚合查询的最大值：选择城市最多的美国州

好的，SQL专家开发人员，我希望这听起来很简单。基本上，我希望形成一个查询，以查找每个州的城市数，并且只包含结果集中城市最多的州

比如：

SELECT S.Name, MAX(COUNT(C.StateID) as 'Count') --NO Can do, please help!
FROM tblStates as S JOIN tblCities as C
ON S.StateID = C.StateID
GROUP BY S.Name

请让我知道最简单的方法，使这个查询工作

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谢谢

也许有一种更优雅的方式，但这应该是可行的：

SELECT s.Name, MAX(Count) FROM
    (SELECT S.Name, COUNT(C.StateID) as 'Count' --NO Can do, please help!
    FROM tblStates as S JOIN tblCities as C
    ON S.StateID = C.StateID
    GROUP BY S.Name)

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某些方言（如Postgres）允许在ORDER子句中使用列号：ORDER BY 2 DESC。

LIMIT在2008年不是关键字。SQL server允许按顺序列号进行排序，也可以这样；SQL Server需要TOP n版本。

SELECT s.Name, MAX(Count) FROM
    (SELECT S.Name, COUNT(C.StateID) as 'Count' --NO Can do, please help!
    FROM tblStates as S JOIN tblCities as C
    ON S.StateID = C.StateID
    GROUP BY S.Name)

SELECT S.Name, COUNT(C.StateID) AS 'Count' 
FROM tblStates as S JOIN tblCities as C 
ON S.StateID = C.StateID 
GROUP BY S.Name 
ORDER BY COUNT(C.StateID) DESC LIMIT 1;