Sql server 逗号分隔字符串
我想使用T-SQL将表中的select签名结果返回到逗号分隔的字符串中 这是我想要的 创建表脚本Sql server 逗号分隔字符串,sql-server,tsql,Sql Server,Tsql,我想使用T-SQL将表中的select签名结果返回到逗号分隔的字符串中 这是我想要的 创建表脚本 CREATE TABLE [dbo].[EVENT_TABLE]( [ID_PERSON] [bigint] IDENTITY(1,1) NOT NULL, [ID_SIGNATURE] [bigint] NULL, [Name] [varchar](250) NULL, [Surname] [varchar](250) NULL, [Age] [varcha
CREATE TABLE [dbo].[EVENT_TABLE](
[ID_PERSON] [bigint] IDENTITY(1,1) NOT NULL,
[ID_SIGNATURE] [bigint] NULL,
[Name] [varchar](250) NULL,
[Surname] [varchar](250) NULL,
[Age] [varchar](250) NULL,
[Department] [varchar](200) NULL,
CONSTRAINT [PK_PERSON_TABLE] PRIMARY KEY CLUSTERED
(
[ID_PERSON] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
GO
选择脚本
SELECT
DISTINCT
A.Department,
CASE
WHEN SUM(A.PEOPLE) < 5 THEN '1 TO 4'
WHEN SUM(A.PEOPLE) >= 5 AND A.PEOPLE < 10 THEN '5 TO 9'
WHEN SUM(A.PEOPLE) >= 10 THEN '10...N'
END
FROM
(
SELECT DISTINCT ID_SIGNATURE, Department, COUNT(NAME) AS PEOPLE
FROM EVENT_TABLE
GROUP BY ID_SIGNATURE, Department
) AS A
GROUP BY A.Department, A.PEOPLE
资料
结果
我希望这就是你需要的。在您的代码中有两种不需要的东西,如Distinct、Aggregate。试试这个
;WITH cte
AS (SELECT A.Department,
CASE
WHEN A.PEOPLE < 5 THEN '1 TO 4'
WHEN A.PEOPLE >= 5 AND A.PEOPLE < 10 THEN '5 TO 9'
WHEN A.PEOPLE >= 10 THEN '10...N'
END [Range],
ID_SIGNATURE
FROM (SELECT ID_SIGNATURE,
Department,
Count(NAME) AS PEOPLE
FROM EVENT_TABLE
GROUP BY ID_SIGNATURE,
Department) AS A)
SELECT Department,
[Range],
(SELECT Stuff((SELECT ',' + CAST(ID_SIGNATURE AS varchar(20))
FROM cte a
WHERE a.Department = b.Department
AND a.[Range] = b.[Range]
FOR XML PATH ('')), 1, 1, '')) Signature
FROM cte B
GROUP BY Department,
[Range]
这与您的问题无关,但您不应将DISTINCT与GROUP BY一起使用。这只会使代码更加混乱。没有DISTINCT,输出将完全相同,因为GROUP BY确保每一行都是唯一的。@Dan感谢以后我不会将DISTINCT与GROUP BYI一起使用。我收到此错误消息8114,级别16,状态5,第1行错误将数据类型varchar转换为bigint.CASTID_签名为VARCHAR20谢谢:D