Sql server T-SQL数据透视错误：'；0'；

我不确定我在代码中做错了什么。我收到一条错误消息：

味精102，第15级，状态1，第82行
“0”附近的语法不正确

有人能帮我找出我的错误吗？我正在尝试透视表，以便查询返回带有年龄组而不是行的标题

SELECT *
FROM 
    (SELECT
         ID,
         CASE 
            WHEN Age BETWEEN 0 AND 4 THEN '0-4 Years'
            WHEN  Age  BETWEEN 5 AND 24 THEN '5-24 Years' 
            WHEN Age BETWEEN 25 AND 49 THEN '25-49 Years'
            WHEN Age BETWEEN 50 AND 64 THEN '50-64 Years'
            WHEN Age > 64 THEN '> 64 Years'
        END AS GroupAge
    FROM 
        #AD) t
PIVOT
    (COUNT(ID)
         FOR GroupAge IN 
             (0-4 Years,5-24 Years,25-49 Years,> 64 Years)
    ) AS pvt

---

将方括号[]放在数据透视列名周围

PIVOT
(
    COUNT(ID)
    FOR GroupAge IN 
    ([0-4 Years],[5-24 Years],[25-49 Years],[50-64 Years],[> 64 Years])
) AS pvt

---

将方括号[]放在数据透视列名周围

PIVOT
(
    COUNT(ID)
    FOR GroupAge IN 
    ([0-4 Years],[5-24 Years],[25-49 Years],[50-64 Years],[> 64 Years])
) AS pvt

---

该错误导致您需要在轴列中使用方括号，因为

0-4年

。。列不是普通字符串

我将使用条件聚合函数do pivot

SELECT
    COUNT(CASE WHEN Age BETWEEN 0 AND 4 THEN  ID END) '0-4 Years', 
    COUNT(CASE WHEN Age BETWEEN 5 AND 24  THEN  ID END) '5-24 Years' , 
    COUNT(CASE WHEN Age BETWEEN 25 AND 49 THEN  ID END) '25-49 Years', 
    COUNT(CASE WHEN Age BETWEEN 50 AND 64 THEN  ID END) '50-64 Years', 
    COUNT(CASE WHEN  Age > 64 THEN  ID END) '> 64 Years'
FROM #AD

---

该错误导致您需要在轴列中使用方括号，因为

0-4年

。。列不是普通字符串

我将使用条件聚合函数do pivot

SELECT
    COUNT(CASE WHEN Age BETWEEN 0 AND 4 THEN  ID END) '0-4 Years', 
    COUNT(CASE WHEN Age BETWEEN 5 AND 24  THEN  ID END) '5-24 Years' , 
    COUNT(CASE WHEN Age BETWEEN 25 AND 49 THEN  ID END) '25-49 Years', 
    COUNT(CASE WHEN Age BETWEEN 50 AND 64 THEN  ID END) '50-64 Years', 
    COUNT(CASE WHEN  Age > 64 THEN  ID END) '> 64 Years'
FROM #AD

---

你能提供一些样本数据和预期结果吗？你能提供一些样本数据和预期结果吗？