Sql server 计算匹配值并以矩阵形式显示
我有以下表格和一些示例数据:Sql server 计算匹配值并以矩阵形式显示,sql-server,tsql,sql-server-2008-r2,Sql Server,Tsql,Sql Server 2008 R2,我有以下表格和一些示例数据: SELECT DB,MAX(Name) AS Name, MAX(ID) AS ID FROM ( SELECT 'TblDB1' AS DB,COUNT(a.Name) AS Name,0 AS ID FROM TblTestDB a INNER JOIN TblDB1 b ON a.Name = b.Name UNION SELECT 'TblDB2' AS DB,COUNT(a.Name) AS Name,0 AS I
SELECT DB,MAX(Name) AS Name, MAX(ID) AS ID
FROM
(
SELECT 'TblDB1' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB1 b ON a.Name = b.Name
UNION
SELECT 'TblDB2' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB2 b ON a.Name = b.Name
UNION
SELECT 'TblDB3' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB3 b ON a.Name = b.Name
UNION
SELECT 'TblDB1' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB1 b ON a.ID = b.ID
UNION
SELECT 'TblDB2' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB2 b ON a.ID = b.ID
UNION
SELECT 'TblDB3' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB3 b ON a.ID = b.ID
) a
GROUP BY DB
表:TblTestDB
CREATE TABLE TblTestDB (id int,name varchar(100));
INSERT INTO TblTestDB VALUES(1,'Sam'),(2,'Jack'),
(3,'Rock'),(4,'Don'),(5,'Tam');
SELECT DB,MAX(Name) AS Name, MAX(ID) AS ID
FROM
(
SELECT 'TblDB1' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB1 b ON a.Name = b.Name
UNION
SELECT 'TblDB2' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB2 b ON a.Name = b.Name
UNION
SELECT 'TblDB3' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB3 b ON a.Name = b.Name
UNION
SELECT 'TblDB1' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB1 b ON a.ID = b.ID
UNION
SELECT 'TblDB2' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB2 b ON a.ID = b.ID
UNION
SELECT 'TblDB3' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB3 b ON a.ID = b.ID
) a
GROUP BY DB
表:TblDB1
CREATE TABLE TblDB1 (id int,name varchar(100));
INSERT INTO TblDB1 VALUES(1,'Sam'),(2,'Jack'),
(3,'Rock');
SELECT DB,MAX(Name) AS Name, MAX(ID) AS ID
FROM
(
SELECT 'TblDB1' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB1 b ON a.Name = b.Name
UNION
SELECT 'TblDB2' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB2 b ON a.Name = b.Name
UNION
SELECT 'TblDB3' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB3 b ON a.Name = b.Name
UNION
SELECT 'TblDB1' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB1 b ON a.ID = b.ID
UNION
SELECT 'TblDB2' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB2 b ON a.ID = b.ID
UNION
SELECT 'TblDB3' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB3 b ON a.ID = b.ID
) a
GROUP BY DB
表:TblDB2
CREATE TABLE TblDB2 (id int,name varchar(100));
INSERT INTO TblDB2 VALUES(1,'Jazz'),(2,'Dsouze'),
(3,'Rock'),(4,'Jack');
SELECT DB,MAX(Name) AS Name, MAX(ID) AS ID
FROM
(
SELECT 'TblDB1' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB1 b ON a.Name = b.Name
UNION
SELECT 'TblDB2' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB2 b ON a.Name = b.Name
UNION
SELECT 'TblDB3' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB3 b ON a.Name = b.Name
UNION
SELECT 'TblDB1' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB1 b ON a.ID = b.ID
UNION
SELECT 'TblDB2' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB2 b ON a.ID = b.ID
UNION
SELECT 'TblDB3' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB3 b ON a.ID = b.ID
) a
GROUP BY DB
表:TblDB3
CREATE TABLE TblDB3 (id int,name varchar(100));
INSERT INTO TblDB3 VALUES(1,'Sam'),(2,'Jazz'),
(3,'Rock');
SELECT DB,MAX(Name) AS Name, MAX(ID) AS ID
FROM
(
SELECT 'TblDB1' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB1 b ON a.Name = b.Name
UNION
SELECT 'TblDB2' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB2 b ON a.Name = b.Name
UNION
SELECT 'TblDB3' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB3 b ON a.Name = b.Name
UNION
SELECT 'TblDB1' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB1 b ON a.ID = b.ID
UNION
SELECT 'TblDB2' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB2 b ON a.ID = b.ID
UNION
SELECT 'TblDB3' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB3 b ON a.ID = b.ID
) a
GROUP BY DB
我想以以下形式显示结果:
TableName Name ID
------------------------------
TblDB1 3 3
TblDB2 2 4
TblDB3 2 3
SELECT DB,MAX(Name) AS Name, MAX(ID) AS ID
FROM
(
SELECT 'TblDB1' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB1 b ON a.Name = b.Name
UNION
SELECT 'TblDB2' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB2 b ON a.Name = b.Name
UNION
SELECT 'TblDB3' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB3 b ON a.Name = b.Name
UNION
SELECT 'TblDB1' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB1 b ON a.ID = b.ID
UNION
SELECT 'TblDB2' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB2 b ON a.ID = b.ID
UNION
SELECT 'TblDB3' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB3 b ON a.ID = b.ID
) a
GROUP BY DB
关于结果集的解释:我想显示表TblTestDB
和其他表(TblDB1
,TblDB2
,TblDB3
)之间匹配的列值计数
SELECT DB,MAX(Name) AS Name, MAX(ID) AS ID
FROM
(
SELECT 'TblDB1' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB1 b ON a.Name = b.Name
UNION
SELECT 'TblDB2' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB2 b ON a.Name = b.Name
UNION
SELECT 'TblDB3' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB3 b ON a.Name = b.Name
UNION
SELECT 'TblDB1' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB1 b ON a.ID = b.ID
UNION
SELECT 'TblDB2' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB2 b ON a.ID = b.ID
UNION
SELECT 'TblDB3' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB3 b ON a.ID = b.ID
) a
GROUP BY DB
尝试使用以下查询:
SELECT DB,MAX(Name) AS Name, MAX(ID) AS ID
FROM
(
SELECT 'TblDB1' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB1 b ON a.Name = b.Name
UNION
SELECT 'TblDB2' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB2 b ON a.Name = b.Name
UNION
SELECT 'TblDB3' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB3 b ON a.Name = b.Name
UNION
SELECT 'TblDB1' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB1 b ON a.ID = b.ID
UNION
SELECT 'TblDB2' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB2 b ON a.ID = b.ID
UNION
SELECT 'TblDB3' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB3 b ON a.ID = b.ID
) a
GROUP BY DB
查询:
SELECT DB,MAX(Name) AS Name, MAX(ID) AS ID
FROM
(
SELECT 'TblDB1' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB1 b ON a.Name = b.Name
UNION
SELECT 'TblDB2' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB2 b ON a.Name = b.Name
UNION
SELECT 'TblDB3' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB3 b ON a.Name = b.Name
UNION
SELECT 'TblDB1' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB1 b ON a.ID = b.ID
UNION
SELECT 'TblDB2' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB2 b ON a.ID = b.ID
UNION
SELECT 'TblDB3' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB3 b ON a.ID = b.ID
) a
GROUP BY DB
问题:我可能会得到10多列来显示,比如矩阵/透视,上面的查询会随着列列表的增长而增长。
有没有更好的方法让它简洁明了 这足够简单吗
SELECT DB,MAX(Name) AS Name, MAX(ID) AS ID
FROM
(
SELECT 'TblDB1' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB1 b ON a.Name = b.Name
UNION
SELECT 'TblDB2' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB2 b ON a.Name = b.Name
UNION
SELECT 'TblDB3' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB3 b ON a.Name = b.Name
UNION
SELECT 'TblDB1' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB1 b ON a.ID = b.ID
UNION
SELECT 'TblDB2' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB2 b ON a.ID = b.ID
UNION
SELECT 'TblDB3' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB3 b ON a.ID = b.ID
) a
GROUP BY DB
SELECT DISTINCT 'TblDB1' AS DB
,COUNT(CASE WHEN a.Name = b.Name THEN 1 ELSE NULL END) AS Name
,COUNT(CASE WHEN a.ID = b.ID THEN 1 ELSE NULL END) AS ID
FROM TblTestDB a
CROSS JOIN TblDB1 b
UNION ALL
SELECT DISTINCT 'TblDB2' AS DB
,COUNT(CASE WHEN a.Name = b.Name THEN 1 ELSE NULL END) AS Name
,COUNT(CASE WHEN a.ID = b.ID THEN 1 ELSE NULL END) AS ID
FROM TblTestDB a
CROSS JOIN TblDB2 b
UNION ALL
SELECT DISTINCT 'TblDB3' AS DB
,COUNT(CASE WHEN a.Name = b.Name THEN 1 ELSE NULL END) AS Name
,COUNT(CASE WHEN a.ID = b.ID THEN 1 ELSE NULL END) AS ID
FROM TblTestDB a
CROSS JOIN TblDB3 b
SELECT
tableName, sum(s.[Name]) as ncnt, max(s.id) as ID
FROM TblTestDB t
cross apply (
SELECT tableName, count(name) as [name], max(id) as ID
FROM (
SELECT 'TblDB1' as tid, * FROM TblDB1
union
SELECT 'TblDB2' as tid, * FROM TblDB2
union
SELECT 'TblDB3' as tid, * FROM TblDB3
) i
where i.name = t.name
group by tableName
) s
group by tableName
我不知道你说的“我可能会有10多列像矩阵/枢轴一样显示”是什么意思。
例如,如果要添加一个姓氏列,应该单独匹配,还是与Name列组合匹配?(前者可能会变得有点复杂…)
SELECT DB,MAX(Name) AS Name, MAX(ID) AS ID
FROM
(
SELECT 'TblDB1' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB1 b ON a.Name = b.Name
UNION
SELECT 'TblDB2' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB2 b ON a.Name = b.Name
UNION
SELECT 'TblDB3' AS DB,COUNT(a.Name) AS Name,0 AS ID
FROM TblTestDB a
INNER JOIN TblDB3 b ON a.Name = b.Name
UNION
SELECT 'TblDB1' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB1 b ON a.ID = b.ID
UNION
SELECT 'TblDB2' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB2 b ON a.ID = b.ID
UNION
SELECT 'TblDB3' AS DB,0 AS Name,COUNT(a.ID) AS ID
FROM TblTestDB a
INNER JOIN TblDB3 b ON a.ID = b.ID
) a
GROUP BY DB