Sql server Sql Server返回最大日期和最接近或大于最大日期的日期

我有一个表，其中有许多ID和两种可能的类型，以及与每个ID和类型关联的许多日期。我想选择ID、类型A的最新日期以及类型B大于类型A的最近日期

Sample Table        
ID  Type    Date
1   A   1/5/2013
1   A   1/10/2013
1   B   1/1/2013
2   A   2/10/2013
2   A   2/9/2013
2   B   2/15/2013
2   B   2/20/2013
3   A   3/15/2013
3   B   3/10/2013
3   B   3/20/2013

期望结果

ID  Date A  Date B
2   2/10/2013   2/15/2013
3   3/15/2013   3/20/2013

ID1被禁用，因为它不满足条件B>MaxtypeA{1/10/13} ID2等于maxtypeA{2/10/13 vs 2/9/13}，日期B{2/15/13}大于日期A以及满足该条件的两个日期中最近的一个。 ID3只等于一个条目和比日期A大的最近的B条目{3/20/13}

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我尝试了几个min、max和row/partition迭代，但结果遗漏了几个符合条件的条目。使用SQLServer2008V10。如果您有任何帮助，我们将不胜感激

假设SQL Server 2005+，您可以使用以下功能：

;WITH CTE AS
(
    SELECT [ID],
           [Type],
           [Date],
           RN = ROW_NUMBER() OVER(PARTITION BY [ID] ORDER BY [Date] DESC)
    FROM YourTable
    WHERE [Type] = 'A'
)
SELECT A.[ID], 
       A.[Date] [Date A],
       B.[Date] [Date B]
FROM (SELECT *
      FROM CTE
      WHERE RN = 1) A
CROSS APPLY (SELECT TOP 1 [Date]
             FROM YourTable
             WHERE [Type] = 'B'
             AND [ID] = A.[ID]
             AND [Date] > A.[Date]
             ORDER BY [Date]) B

结果是：

╔════╦═════════════════════════════════╦═════════════════════════════════╗
║ ID ║             DATE A              ║             DATE B              ║
╠════╬═════════════════════════════════╬═════════════════════════════════╣
║  2 ║ February, 10 2013 00:00:00+0000 ║ February, 15 2013 00:00:00+0000 ║
║  3 ║ March, 15 2013 00:00:00+0000    ║ March, 20 2013 00:00:00+0000    ║
╚════╩═════════════════════════════════╩═════════════════════════════════╝

---

和一个SQLFIDLE供您尝试。

假设SQL Server 2005+，您可以使用：

;WITH CTE AS
(
    SELECT [ID],
           [Type],
           [Date],
           RN = ROW_NUMBER() OVER(PARTITION BY [ID] ORDER BY [Date] DESC)
    FROM YourTable
    WHERE [Type] = 'A'
)
SELECT A.[ID], 
       A.[Date] [Date A],
       B.[Date] [Date B]
FROM (SELECT *
      FROM CTE
      WHERE RN = 1) A
CROSS APPLY (SELECT TOP 1 [Date]
             FROM YourTable
             WHERE [Type] = 'B'
             AND [ID] = A.[ID]
             AND [Date] > A.[Date]
             ORDER BY [Date]) B

结果是：

╔════╦═════════════════════════════════╦═════════════════════════════════╗
║ ID ║             DATE A              ║             DATE B              ║
╠════╬═════════════════════════════════╬═════════════════════════════════╣
║  2 ║ February, 10 2013 00:00:00+0000 ║ February, 15 2013 00:00:00+0000 ║
║  3 ║ March, 15 2013 00:00:00+0000    ║ March, 20 2013 00:00:00+0000    ║
╚════╩═════════════════════════════════╩═════════════════════════════════╝

还有一个sqlfiddle供您尝试。

您可以使用：

SELECT ID, A_Date, B_Date
FROM (
    SELECT a.ID,a.Date 'A_Date', b.Date 'B_Date', ROW_NUMBER() OVER (PARTITION BY a.ID ORDER BY DATEDIFF(day,a.Date,b.Date))'RowRank'
    FROM (SELECT ID,Type, MAX(Date)'Date'
          FROM Table1
          WHERE Type = 'A'
          GROUP BY ID,Type
          )a
    JOIN Table1 b
      ON a.ID = b.ID
      AND a.Type <> b.Type
      AND a.Date < b.Date
  )sub
WHERE RowRank = 1

演示：

您可以使用：

SELECT ID, A_Date, B_Date
FROM (
    SELECT a.ID,a.Date 'A_Date', b.Date 'B_Date', ROW_NUMBER() OVER (PARTITION BY a.ID ORDER BY DATEDIFF(day,a.Date,b.Date))'RowRank'
    FROM (SELECT ID,Type, MAX(Date)'Date'
          FROM Table1
          WHERE Type = 'A'
          GROUP BY ID,Type
          )a
    JOIN Table1 b
      ON a.ID = b.ID
      AND a.Type <> b.Type
      AND a.Date < b.Date
  )sub
WHERE RowRank = 1

演示：