Sql server 具有激活过程错误的Service broker

我使用service broker在sql server中创建了一个接收消息的目标队列。我的目标队列如下所示：

USE [DatabaseB]
GO

ALTER QUEUE [dbo].[TargetQueue] WITH STATUS = OFF , RETENTION = OFF , ACTIVATION (  STATUS = ON , PROCEDURE_NAME = [dbo].[myp] , MAX_QUEUE_READERS = 10 , EXECUTE AS N'dbo'  ), POISON_MESSAGE_HANDLING (STATUS = ON)

这是我的存储过程，当在目标队列中收到消息时，我调用它

更改过程[dbo].[myp]

AS   


WHILE (1=1)
  BEGIN

  Declare @ConversationHandle as uniqueidentifier
Declare @MessageBody as nvarchar(max)
Declare @MessageType as sysname

Begin Transaction
Print 'Started Receiving ';

RECEIVE top (1)
      @MessageType = message_type_name,
      @ConversationHandle = conversation_handle,
    @MessageBody = message_body
FROM TargetQueue;

if @MessageType = 'SenderMessageType'
      Begin
            SEND 
                  ON CONVERSATION @ConversationHandle
                  Message Type ReceiverMessageType
                  ('Message is received')
            END Conversation @ConversationHandle
            insert into table_1 (dataa)  values ('salam')
      END

Commit


  end

---

但是，当队列接收到消息时，我的存储过程将无限数据添加到

表1

，但我有一个条件，正如您在上面所看到的，我的意思是，对于收到的每条消息，sp应该向表中添加一行，而不是无限行。为什么？

我只是将存储过程更改为：

ALTER PROCEDURE [dbo].[myp]

AS   


WHILE (1=1)
  BEGIN

  Declare @ConversationHandle as uniqueidentifier
Declare @MessageBody as nvarchar(max)
Declare @MessageType as sysname

Begin Transaction
Print 'Started Receiving ';
 WAITFOR
    (
RECEIVE top (1)
      @MessageType = message_type_name,
      @ConversationHandle = conversation_handle,
    @MessageBody = message_body
FROM TargetQueue), TIMEOUT 5000;
IF (@@ROWCOUNT = 0)
    BEGIN
      ROLLBACK TRANSACTION;
      BREAK;
    END

if @MessageType = 'SenderMessageType'
      Begin
            SEND 
                  ON CONVERSATION @ConversationHandle
                  Message Type ReceiverMessageType
                  ('Message is received')
            END Conversation @ConversationHandle
            insert into table_12 (dataa)  values ('salam')
      END

Commit


  end