Sql server SQL Server时间表计算
我有一个打卡程序,输出下面的数据集Sql server SQL Server时间表计算,sql-server,tsql,datetime,sql-server-2012,Sql Server,Tsql,Datetime,Sql Server 2012,我有一个打卡程序,输出下面的数据集RECTYP_43是(1)个输入和(2)个输出冲头。我需要一个查询来查看LOGINDATE_43和LOGINTIME_43以及RECTYPE_43并获得1和2之间的差异 我认为这比事实证明的要容易 empid_43 RECTYPE_43 LOGINDATE_43 LOGINTIME_43 ------------------------------------------------------------ 127
RECTYP_43
是(1)个输入和(2)个输出冲头。我需要一个查询来查看LOGINDATE_43
和LOGINTIME_43
以及RECTYPE_43
并获得1和2之间的差异
我认为这比事实证明的要容易
empid_43 RECTYPE_43 LOGINDATE_43 LOGINTIME_43
------------------------------------------------------------
127 1 2016-10-21 00:00:00.000 0558
127 2 2016-10-21 00:00:00.000 1430
127 2 2016-10-21 00:00:00.000 1201
127 1 2016-10-21 00:00:00.000 1228
127 1 2016-10-24 00:00:00.000 0557
127 2 2016-10-24 00:00:00.000 1200
127 1 2016-10-24 00:00:00.000 1228
127 2 2016-10-24 00:00:00.000 1430
2589 2 2016-10-21 00:00:00.000 1431
2589 1 2016-10-21 00:00:00.000 0556
2589 1 2016-10-24 00:00:00.000 0550
2589 2 2016-10-24 00:00:00.000 1431
2589 2 2016-10-24 00:00:00.000 1201
2589 1 2016-10-24 00:00:00.000 1226
69 1 2016-10-24 00:00:00.000 1229
69 2 2016-10-24 00:00:00.000 1430
69 1 2016-10-24 00:00:00.000 0555
69 2 2016-10-24 00:00:00.000 1200
您可以使用一个CTE来获取所有的打孔,然后使用一个子查询来查找该时间之后的第一个打孔
;WITH ctePunchIn AS (
SELECT empid_43, LOGINDATE_43 AS Date_In, LOGINTIME_43 AS Time_In
FROM #Table1
WHERE [RECTYPE_43] = 1
)
SELECT
empid_43, Date_In, Time_In
,(SELECT TOP 1 LOGINTIME_43 FROM #Table1 WHERE
(empid_43 = ctePunchIn.empid_43)
AND
(LOGINDATE_43 = ctePunchIn.Date_In)
AND
(LOGINTIME_43 > ctePunchIn.Time_In)
AND
(RECTYPE_43 = 2)
ORDER BY empid_43, Date_In, LOGINTIME_43) AS Time_Out
FROM
ctePunchIn
您可以使用一个CTE来获取所有的打孔,然后使用一个子查询来查找该时间之后的第一个打孔
;WITH ctePunchIn AS (
SELECT empid_43, LOGINDATE_43 AS Date_In, LOGINTIME_43 AS Time_In
FROM #Table1
WHERE [RECTYPE_43] = 1
)
SELECT
empid_43, Date_In, Time_In
,(SELECT TOP 1 LOGINTIME_43 FROM #Table1 WHERE
(empid_43 = ctePunchIn.empid_43)
AND
(LOGINDATE_43 = ctePunchIn.Date_In)
AND
(LOGINTIME_43 > ctePunchIn.Time_In)
AND
(RECTYPE_43 = 2)
ORDER BY empid_43, Date_In, LOGINTIME_43) AS Time_Out
FROM
ctePunchIn
如果注销时间与登录时间相同,则DazedandFuzzle的方法有效,但如果用户在不同的日期注销以登录,则该方法无效
e、 g
为了适应这种情况,您需要知道表中下一项是针对该员工的。这样,您就可以确保下一个项目也是注销事件。这将有助于捕捉某人忘记打卡的情况
扩展CTE可以提供更完整的解决方案:
WITH Data AS
(
SELECT empId_43,
RecType_43,
LoginDate_43,
LoginTime_43,
RowNum = ROW_NUMBER() OVER (PARTITION BY empId_43
ORDER BY LoginDate_43, LoginTime_43)
FROM Punch
)
SELECT PIn.empId_43 [Employee],
PIn.LoginDate_43 [LoginDate],
PIn.LoginTime_43 [LoginTime],
POut.LoginDate_43 [LogoutDate],
POut.LoginTime_43 [LogoutTime]
FROM Data PIn
LEFT JOIN Data POut ON PIn.empId_43 = POut.empId_43
AND POut.RecType_43 = 2
AND POut.RowNum = PIn.RowNum + 1
WHERE PIn.RecType_43 = 1
ORDER BY PIn.empId_43, PIn.LoginDate_43, PIn.LoginTime_43;
但是,行编号
可能效率低下。当查看一个小的子集(例如,特定的日期范围等)时,这样做是最好的。如果注销时间与登录时间相同,则DazedAndFuzzle的方法有效,但如果用户在不同的日期注销登录,则它将不起作用
e、 g
为了适应这种情况,您需要知道表中下一项是针对该员工的。这样,您就可以确保下一个项目也是注销事件。这将有助于捕捉某人忘记打卡的情况
扩展CTE可以提供更完整的解决方案:
WITH Data AS
(
SELECT empId_43,
RecType_43,
LoginDate_43,
LoginTime_43,
RowNum = ROW_NUMBER() OVER (PARTITION BY empId_43
ORDER BY LoginDate_43, LoginTime_43)
FROM Punch
)
SELECT PIn.empId_43 [Employee],
PIn.LoginDate_43 [LoginDate],
PIn.LoginTime_43 [LoginTime],
POut.LoginDate_43 [LogoutDate],
POut.LoginTime_43 [LogoutTime]
FROM Data PIn
LEFT JOIN Data POut ON PIn.empId_43 = POut.empId_43
AND POut.RecType_43 = 2
AND POut.RowNum = PIn.RowNum + 1
WHERE PIn.RecType_43 = 1
ORDER BY PIn.empId_43, PIn.LoginDate_43, PIn.LoginTime_43;
但是,
行编号
可能效率低下。在查看小子集(例如特定日期范围等)时,最好这样做。稍微不同的方法:
select
punchIn.empid_43,
punchIn.login as dateTime_in,
punchout.login as dateTime_out
from
(
SELECT empId_43,
RecType_43,
LoginDate_43,
LoginTime_43,
dateadd('n',right(logintime_43,2),
dateadd('hh',left(LoginTime_43,2),
LoginDate_43)) as login,
RowNum = ROW_NUMBER() OVER (PARTITION BY empId_43
ORDER BY LoginDate_43, LoginTime_43)
FROM Punch
where rectype_43 = 1
) punchIn left outer join
(
SELECT empId_43,
RecType_43,
LoginDate_43,
LoginTime_43,
dateadd('n',right(logintime_43,2),
dateadd('hh',left(LoginTime_43,2),
LoginDate_43)) as login,
RowNum = ROW_NUMBER() OVER (PARTITION BY empId_43
ORDER BY LoginDate_43, LoginTime_43)
FROM Punch
where rectype_43 = 2
) punchOut on
punchin.empID = punchout.empID and
punchin.rownum = punchout.rownum
假设所有punchin行都有相应的punchout行稍微不同的方法:
select
punchIn.empid_43,
punchIn.login as dateTime_in,
punchout.login as dateTime_out
from
(
SELECT empId_43,
RecType_43,
LoginDate_43,
LoginTime_43,
dateadd('n',right(logintime_43,2),
dateadd('hh',left(LoginTime_43,2),
LoginDate_43)) as login,
RowNum = ROW_NUMBER() OVER (PARTITION BY empId_43
ORDER BY LoginDate_43, LoginTime_43)
FROM Punch
where rectype_43 = 1
) punchIn left outer join
(
SELECT empId_43,
RecType_43,
LoginDate_43,
LoginTime_43,
dateadd('n',right(logintime_43,2),
dateadd('hh',left(LoginTime_43,2),
LoginDate_43)) as login,
RowNum = ROW_NUMBER() OVER (PARTITION BY empId_43
ORDER BY LoginDate_43, LoginTime_43)
FROM Punch
where rectype_43 = 2
) punchOut on
punchin.empID = punchout.empID and
punchin.rownum = punchout.rownum
假设所有punchin行都有对应的punchout行