Sql 两次合并一个表并计数记录
我有两张桌子。一个是大师,另一个是查阅。 TblMstr和Cmaster TblmstrSql 两次合并一个表并计数记录,sql,sql-server,database,join,Sql,Sql Server,Database,Join,我有两张桌子。一个是大师,另一个是查阅。 TblMstr和Cmaster Tblmstr Id QuestionId ChoiceId ChoiceMaster 1 2 1 Strongly Agree 1 3 2 Disagree 1 4 3 Agree 1 5 11 null 2 2 2
Id QuestionId ChoiceId ChoiceMaster
1 2 1 Strongly Agree
1 3 2 Disagree
1 4 3 Agree
1 5 11 null
2 2 2 Disagree
2 3 5 Disagree
2 4 9 Agree
2 5 12 null
克马斯特
ChoiceId QuestionId ChoiceName
1 2 Strongly Agree
2 2 Disagree
3 2 Agree
4 3 Strongly Agree
5 3 Disagree
6 3 Agree
7 4 Strongly Agree
8 4 Disagree
9 4 Agree
10 5 Registered Nurse
11 5 Nurse Practitioner
12 5 Pharmacist
我需要知道每个问题有多少注册护士强烈同意、不同意和同意。护士从业者和药剂师也是如此。嗯。您可以加入两次。一次了解职业,一次了解其他问题的答案:
select co.choicename as occupation,
sum(case when c.choicename = 'Strongly Agree' then 1 else 0 end) as cnt_strongly_agree,
sum(case when c.choicename = 'Agree' then 1 else 0 end) as cnt_agree,
sum(case when c.choicename = 'Disagree' then 1 else 0 end) as cnt_disagree
from Tblmstr m join
Cmaster co
on co.id = m.choiceid and co.questionid = 5 join
Cmaster c
on co.id = m.choiceid and co.questionid <> 5
group by co.choicename
选择co.choicename作为职业,
求和(c.choicename='Strongly Agree'然后1或0 end时的情况)为cnt_Strongly_Agree,
求和(当c.choicename='Agree'时,则为1,否则为0结束)为cnt_Agree,
求和(当c.choicename='discovere'然后1 else 0 end时的情况)作为cnt_discovere
从Tblmstr m join
克马斯特公司
在co.id=m.choiceid和co.questionid=5时加入
克马斯特c
关于co.id=m.choiceid和co.questionid 5
集团公司choicename