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Sql 每个“重复”组只保留一个报警?@DiegoPerez为了消除重复,必须在进行10秒耐久性测试之前过滤数据。请参阅我的答案中更新的查询。 select t1.ID, t1.PKN_EVENTNAME, t1.RECEIVEDDATE from PARQUI_Sql_Oracle_Datediff_Date Difference - Fatal编程技术网

Sql 每个“重复”组只保留一个报警?@DiegoPerez为了消除重复,必须在进行10秒耐久性测试之前过滤数据。请参阅我的答案中更新的查询。 select t1.ID, t1.PKN_EVENTNAME, t1.RECEIVEDDATE from PARQUI

Sql 每个“重复”组只保留一个报警?@DiegoPerez为了消除重复,必须在进行10秒耐久性测试之前过滤数据。请参阅我的答案中更新的查询。 select t1.ID, t1.PKN_EVENTNAME, t1.RECEIVEDDATE from PARQUI,sql,oracle,datediff,date-difference,Sql,Oracle,Datediff,Date Difference,每个“重复”组只保留一个报警?@DiegoPerez为了消除重复,必须在进行10秒耐久性测试之前过滤数据。请参阅我的答案中更新的查询。 select t1.ID, t1.PKN_EVENTNAME, t1.RECEIVEDDATE from PARQUIMETERS_ALARMS t1 where exists (select 'x' from PARQUIMETERS_ALARMS t2 where t1.id <> t2.id


每个“重复”组只保留一个报警?@DiegoPerez为了消除重复,必须在进行10秒耐久性测试之前过滤数据。请参阅我的答案中更新的查询。
select t1.ID, t1.PKN_EVENTNAME, t1.RECEIVEDDATE 
from PARQUIMETERS_ALARMS t1 
where 
  exists
     (select 'x' 
      from   PARQUIMETERS_ALARMS t2 
      where  t1.id <> t2.id and                                              -- Not the same row
             trunc(t2.RECEIVEDDATE) = trunc(t1.RECEIVEDDATE)                 -- Same date
             and abs(t1.RECEIVEDDATE - t2.RECEIVEDDATE) * 24 * 60 * 60 < 10)  -- < 10 sec
select t1.ID, t1.PKN_EVENTNAME, t1.RECEIVEDDATE 
from PARQUIMETERS_ALARMS t1 
where 
  exists
     (select 'x' 
      from   PARQUIMETERS_ALARMS t2 
      where  t1.id <> t2.id   -- Not the same row                                         
             --trunc(t2.RECEIVEDDATE) = trunc(t1.RECEIVEDDATE)   -- this is not needed
             and t1.PKN_EVENTNAME = t2.PKN_EVENTNAME -- added this
             and abs(t1.RECEIVEDDATE - t2.RECEIVEDDATE) * 24 * 60 * 60 < 10) -- < 5 sec
with alarms as (
  select pa.*,
         lag(pa.RECEIVEDDATE) over (partition by pa.pkn_eventName
                                        order by pa.recievedDate) prior_receivedDate
    from PARQUIMETERS_ALARMS pa
)
select *
  from alarms
 where receivedDate - prior_receivedDate <= interval '10' second;