如何使用；“联合所有人”；在SQL中？

我有两个问题

第一个：

SELECT CreatedOn, COUNT(*) AS locationNonProcessed
FROM Table1
WHERE IsActive = 0
GROUP BY CAST(CreatedOn AS DATE), CreatedOn

SELECT CreatedOn, COUNT(*) AS locationProcessed
FROM Table1
WHERE IsActive = 1
GROUP BY CAST(CreatedOn AS DATE), CreatedOn

第二个：

SELECT CreatedOn, COUNT(*) AS locationNonProcessed
FROM Table1
WHERE IsActive = 0
GROUP BY CAST(CreatedOn AS DATE), CreatedOn

SELECT CreatedOn, COUNT(*) AS locationProcessed
FROM Table1
WHERE IsActive = 1
GROUP BY CAST(CreatedOn AS DATE), CreatedOn

---

我应该如何在这些查询中使用

UNION ALL

？

我认为您不是真的想要

UNION ALL

。这是很容易实现的，并且会导致不太合理的结果（您将不知道哪个计数是哪个计数）

我怀疑您想要条件聚合：

SELECT CAST(CreatedOn AS DATE),
       SUM(CASE WHEN IsActive = 0 THEN 1 ELSE 0 END) AS locationNonProcessed,
       SUM(CASE WHEN IsActive = 1 THEN 1 ELSE 0 END) as locationProcessed
FROM Table1
GROUP BY CAST(CreatedOn AS DATE);

注意

选择

和

分组依据

的修正

如果

IsActive

仅采用0、1和可能的

NULL

值，则可简化为：

SELECT CAST(CreatedOn AS DATE),
       SUM(1 - IsActive) AS locationNonProcessed,
       SUM(IsActive) as locationProcessed
FROM Table1
GROUP BY CAST(CreatedOn AS DATE);

---

按演员分组（CreatedOn作为日期），CreatedOn对我来说很奇怪。这与CreatedOn的
分组没有什么不同
您尝试了什么，面临什么问题？无需全部合并。只需在GROUPBY子句和SELECT列表中包含IsActive。您想要什么结果
UNION-ALL
非常简单。写下这两个查询，并在它们之间放置
UNION ALL
。我认为我们必须按照@jarlh@SandipPatel . . . 这是另一种选择。@SandipPatel这取决于您希望将计数作为单独的行还是额外的列。OP可能会选择这个答案，因为他们不知道如何在原来的问题中得到它，
WHERE
子句实际上可能不需要，因为它是布尔型的。当然，如果OP没有
NULL
s。
SELECT createdon,
       SUM(CASE WHEN IsActive = 0 THEN 1 ELSE 0 END) AS locationNonProcessed,
       SUM(CASE WHEN IsActive = 1 THEN 1 ELSE 0 END) as locationProcessed
FROM Table1
GROUP BY CAST(CreatedOn AS DATE), CreatedOn;