SQL查询以获得如下结果

转换如下：

结果应该是这样

id   name   Content
 1   abc    khsdchdcdhkj
 1   abc    kjwdfwvkkvj
 1   abc    poiwejefoefoen
 2   def    oiwejfioweocwnf
 2   def    liweenfowejnvouer
 2   def    oiewjvoivoewfoiff
 3   ghi    oljevnjoernvjeno
 3   ghi    oinrevoinewovoewfio
 3   ghi    oljewnfjewnfjwenfjef
 4   xyz    ojnwefojnweuofoioinvc
 4   xyz    kjnwefjonwefojoojn
 4   xyz    oijdofijweoifjoijiojwfvn

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您可以使用条件聚合和行数：

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注意：SQL表表示无序集。因此，这三列的顺序是按内容排列的。如果需要另一个排序，则需要在列中包含有关所需排序的信息。

您可以使用组目录和子字符串索引来实现这一点

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如果有3个以上的值，您只需添加另一个SELECT并在最内层的子字符串中增加数字，如：SUBSTRING_INDEXSUBSTRING_INDEXGROUP_CONCATCENT ORDER BY Content4

尝试了此查询SELECT*from SELECT id，name，group_concatcontent group by id来自测试d枢轴，以id、名称、内容作为piv进行区分；

id   name   Content1       Content2              Content 3
 1   abc    khsdchdcdhkj    kjwdfwvkkvj           poiwejefoefoen
 2   def    oiwejfioweocwnf liweenfowejnvouer     oiewjvoivoewfoiff

select id,
       max(case when seqnum = 1 then content end) as content1,
       max(case when seqnum = 2 then content end) as content2,
       max(case when seqnum = 3 then content end) as content3
from (select t.*, 
             row_number() over (partition by id order by content) as seqnum
      from t
     ) t
group by id

SELECT id,
       name,
       SUBSTRING_INDEX(GROUP_CONCAT(Content ORDER BY Content), ',', 1) AS Content1,
       SUBSTRING_INDEX(SUBSTRING_INDEX(GROUP_CONCAT(Content ORDER BY Content), ',', 2), ',', -1) AS Content2,
       SUBSTRING_INDEX(SUBSTRING_INDEX(GROUP_CONCAT(Content ORDER BY Content), ',', 3), ',', -1) AS Content3
FROM table_name
GROUP BY id, name;