Sql 获取查询结果集返回的行数，但不包含ROWCOUNT

我有我下面的查询，这将给我的雇员ID和次数，他已经登录到一个应用程序

SELECT E.[EmployeeId], COUNT(*) LoginCount
FROM tblEmployee E
JOIN tblAccessLog AL ON E.EmployeeId = AL.EmployeeId
WHERE AL.[AccessType] = 212
GROUP BY E.[EmployeeId]

我想让那些登录超过特定阈值的员工，让我拿100

SELECT E.[EmployeeId], COUNT(*) LoginCount
FROM tblEmployee E
JOIN tblAccessLog AL ON E.EmployeeId = AL.EmployeeId
WHERE AL.[AccessType] = 212
GROUP BY E.[EmployeeId]
HAVING COUNT(*) > 100

现在我想得到上面查询返回的计数，我指的是访问我的站点超过100次的员工计数

---

我尝试了

@@ROWCOUNT

，它返回了用户数，但返回了2个结果集，我正在寻找是否有更好的方法代替使用

@@ROWCOUNT

只需将当前查询用作子查询即可

SELECT COUNT(*)
FROM (
    SELECT E.[EmployeeId], COUNT(*) LoginCount
    FROM tblEmployee E
    JOIN tblAccessLog AL ON E.EmployeeId = AL.EmployeeId
    WHERE AL.[AccessType] = 212
    GROUP BY E.[EmployeeId]
    HAVING COUNT(*) > 100
) X

---

使用带窗口的

计数

：

Select E.[EmployeeId], COUNT(*) LoginCount, COUNT(*) OVER() AS cnt_of_Employee
FROM tblEmployee E
JOIN tblAccessLog AL ON E.EmployeeId = AL.EmployeeId
WHERE AL.[AccessType] = 212
GROUP BY E.[EmployeeId]
HAVING COUNT(*) > 100