SQL Server许多不规则测量值之间的差异

我有一个SQL server数据库，表中包含100个测量点的测量数据。每一个都以大约5秒的间隔进行测量。其格式如下：

MeasurementPointID           timestamp              value
001234                       03-01-2015 00:02:03    100
001234                       03-01-2015 00:02:08    120
001234                       03-01-2015 00:02:13    130
001234                       03-01-2015 00:02:19    160
001234                       03-01-2015 00:02:22    200
001236                       03-01-2015 00:02:04    400
001236                       03-01-2015 00:02:09    405
001236                       03-01-2015 00:02:14    420
001236                       03-01-2015 00:02:19    445
001236                       03-01-2015 00:02:25    470
Etc.

我想知道如何使用自前一个时间戳以来测量值的变化除以时间段（自前一个时间戳）来创建视图

MeasurementPointID时间戳changeDivPeriod
001234 03-01-2015 00:02:03 0您可以使用窗口函数和自连接（如果需要，请使用视图包装）：


输出：

╔════════════════════╦═════════════════════╦═════════════════╗
║ MeasurementPointID ║      timestamp      ║ changeDivPeriod ║
╠════════════════════╬═════════════════════╬═════════════════╣
║             001234 ║ 2015-03-01 00:02:03 ║ 0               ║
║             001234 ║ 2015-03-01 00:02:08 ║ 4               ║
║             001234 ║ 2015-03-01 00:02:13 ║ 2               ║
║             001234 ║ 2015-03-01 00:02:19 ║ 5               ║
║             001234 ║ 2015-03-01 00:02:22 ║ 13.333333333333 ║
║             001236 ║ 2015-03-01 00:02:04 ║ 0               ║
║             001236 ║ 2015-03-01 00:02:09 ║ 1               ║
║             001236 ║ 2015-03-01 00:02:14 ║ 3               ║
║             001236 ║ 2015-03-01 00:02:19 ║ 5               ║
║             001236 ║ 2015-03-01 00:02:25 ║ 4.166666666666  ║
╚════════════════════╩═════════════════════╩═════════════════╝


使用
SQL Server 2012+
，您可以利用
超前/滞后：

SELECT 
  MeasurementPointID,
  [timestamp],
  [changeDivPeriod] =  COALESCE(1.0 * ([value] - LAG ([value]) OVER ( PARTITION BY MeasurementPointID ORDER BY [timestamp] )) 
                               / NULLIF(DATEDIFF(second, LAG ([timestamp]) OVER ( PARTITION BY MeasurementPointID ORDER BY [timestamp]), [timestamp]),0),0)
FROM #tab

40/3是13.333333，而不是10。行（160和200）和3秒差异IP：使用适当的软件（MySQL、Oracle、DB2等）和版本标记数据库问题很有帮助，例如
sql-server-2014
。语法和功能的差异通常会影响答案。谢谢。我修正了问题中的错误并添加了额外的标签。非常感谢。工作起来很有魅力！由于是sql server 2012，我尝试了这两种方法，第二种方法的速度要快得多。
╔════════════════════╦═════════════════════╦═════════════════╗
║ MeasurementPointID ║      timestamp      ║ changeDivPeriod ║
╠════════════════════╬═════════════════════╬═════════════════╣
║             001234 ║ 2015-03-01 00:02:03 ║ 0               ║
║             001234 ║ 2015-03-01 00:02:08 ║ 4               ║
║             001234 ║ 2015-03-01 00:02:13 ║ 2               ║
║             001234 ║ 2015-03-01 00:02:19 ║ 5               ║
║             001234 ║ 2015-03-01 00:02:22 ║ 13.333333333333 ║
║             001236 ║ 2015-03-01 00:02:04 ║ 0               ║
║             001236 ║ 2015-03-01 00:02:09 ║ 1               ║
║             001236 ║ 2015-03-01 00:02:14 ║ 3               ║
║             001236 ║ 2015-03-01 00:02:19 ║ 5               ║
║             001236 ║ 2015-03-01 00:02:25 ║ 4.166666666666  ║
╚════════════════════╩═════════════════════╩═════════════════╝

SELECT 
  MeasurementPointID,
  [timestamp],
  [changeDivPeriod] =  COALESCE(1.0 * ([value] - LAG ([value]) OVER ( PARTITION BY MeasurementPointID ORDER BY [timestamp] )) 
                               / NULLIF(DATEDIFF(second, LAG ([timestamp]) OVER ( PARTITION BY MeasurementPointID ORDER BY [timestamp]), [timestamp]),0),0)
FROM #tab