Sql 如果组中的所有文档的值都设置为1，如何计数？

在文档审阅工具中，可以创建批文档。批次是一组相关文档，由GroupID标识

这些文档组将呈现给审阅者，审阅者将更新名为Testcompleted的字段。此字段有3种可能的状态：1、0或null。组中的文档数量各不相同

在下面的示例中，我有3组批文档。例如，第一批_0001有两个文档58和59

#Document

ArtifactID    Testcompleted    GroupID
--------------------------------------
58            1                4
59            1                4
60            null             6
61            1                6
62            null             7
63            null             7
64            null             7

#DocumentBatch

BatchArtifactID    DocumentArtifactID
-------------------------------------
66                 58
66                 59
67                 60
67                 61
68                 62
68                 63
68                 64


#Batch

ArtifactID    Name
------------------------
66            batch_0001
67            batch_0002
68            batch_0003

我需要知道批处理何时完成，也就是说，当该批处理中的所有文档都将Testcompleted字段设置为1时。在本例中，批次_0001就是这种情况

我想要的输出是：

batch           documents       reviewed     completed
------------------------------------------------------
batch_0001      2               2            yes
batch_0002      2               1            no
batch_0003      3               0            no

我从加入表格开始：

select
    *
from
    #Document d

    left join #DocumentBatch db
    on db.DocumentArtifactID = b.ArtifactID

    left join #Batch b
    on db.BatchArtifactID = b.ArtifactID
where
    d.Testcompleted = 1
;

---

这显然没有返回我需要的结果，但我被卡住了。非常感谢您对如何解决此问题的帮助。

您可以尝试以下方法：

select b.name
     , count(*) as documents
     , sum(d.Testcompleted) as reviewed
     , (case when count(*) = sum(d.Testcompleted) then 'yes' else 'no' end) as completed
from [#Document] d
join [#DocumentBatch] db on db.DocumentArtifactID = d.ArtifactID
join [#Batch] b on db.BatchArtifactID = b.ArtifactID
group by b.name

select b.name as batchname, count(d.ARtifactID) as numdocuments,
       sum(case when d.testCompleted = 1 then 1 else 0 end) as NumCompleted,
       (case when sum(case when d.testCompleted = 1 then 0 else 1 end) > 0
             then 'No'
             else 'Yes'
        end) as AllCompleted
from #Batch b left join
     #DocumentBatch db     
     on db.BatchArtifactID = b.ArtifactID
     #Document d left join
     on db.DocumentArtifactID = b.ArtifactID left join
group by b.name;

计数*包括计算所有值； Testcompleted仅统计Testcompleted为1的情况；

---

您可以尝试以下方法：

select b.name
     , count(*) as documents
     , sum(d.Testcompleted) as reviewed
     , (case when count(*) = sum(d.Testcompleted) then 'yes' else 'no' end) as completed
from [#Document] d
join [#DocumentBatch] db on db.DocumentArtifactID = d.ArtifactID
join [#Batch] b on db.BatchArtifactID = b.ArtifactID
group by b.name

select b.name as batchname, count(d.ARtifactID) as numdocuments,
       sum(case when d.testCompleted = 1 then 1 else 0 end) as NumCompleted,
       (case when sum(case when d.testCompleted = 1 then 0 else 1 end) > 0
             then 'No'
             else 'Yes'
        end) as AllCompleted
from #Batch b left join
     #DocumentBatch db     
     on db.BatchArtifactID = b.ArtifactID
     #Document d left join
     on db.DocumentArtifactID = b.ArtifactID left join
group by b.name;

计数*包括计算所有值； Testcompleted仅统计Testcompleted为1的情况；

---

您需要的是聚合，因此需要一个分组依据。大概是这样的：

select b.name
     , count(*) as documents
     , sum(d.Testcompleted) as reviewed
     , (case when count(*) = sum(d.Testcompleted) then 'yes' else 'no' end) as completed
from [#Document] d
join [#DocumentBatch] db on db.DocumentArtifactID = d.ArtifactID
join [#Batch] b on db.BatchArtifactID = b.ArtifactID
group by b.name

select b.name as batchname, count(d.ARtifactID) as numdocuments,
       sum(case when d.testCompleted = 1 then 1 else 0 end) as NumCompleted,
       (case when sum(case when d.testCompleted = 1 then 0 else 1 end) > 0
             then 'No'
             else 'Yes'
        end) as AllCompleted
from #Batch b left join
     #DocumentBatch db     
     on db.BatchArtifactID = b.ArtifactID
     #Document d left join
     on db.DocumentArtifactID = b.ArtifactID left join
group by b.name;

---

我认为不需要外部连接。您应该能够使用内部联接，除非有没有文档的批处理。如果您确实使用外部联接，那么从批处理开始比从文档开始更有意义，因为您是在批处理级别进行聚合。

您需要的是聚合，因此您需要一个分组依据。大概是这样的：

select b.name
     , count(*) as documents
     , sum(d.Testcompleted) as reviewed
     , (case when count(*) = sum(d.Testcompleted) then 'yes' else 'no' end) as completed
from [#Document] d
join [#DocumentBatch] db on db.DocumentArtifactID = d.ArtifactID
join [#Batch] b on db.BatchArtifactID = b.ArtifactID
group by b.name

select b.name as batchname, count(d.ARtifactID) as numdocuments,
       sum(case when d.testCompleted = 1 then 1 else 0 end) as NumCompleted,
       (case when sum(case when d.testCompleted = 1 then 0 else 1 end) > 0
             then 'No'
             else 'Yes'
        end) as AllCompleted
from #Batch b left join
     #DocumentBatch db     
     on db.BatchArtifactID = b.ArtifactID
     #Document d left join
     on db.DocumentArtifactID = b.ArtifactID left join
group by b.name;

select
    b.name, 
    count(db.DocumentArtifactID) as documents,
    -- count only completed
    count(case when d.Testcompleted = 1 then d.ArtifactID end) as reviewed,
    -- if the minimum = 1 there's no 0 or NULL
    case when min(cast(Testcompleted as tinyint)) = 1 then 'yes' else 'no' end as completed
from
    #Batch b

    left join #DocumentBatch db
    on db.BatchArtifactID = b.ArtifactID

    left join #Document d
    on db.DocumentArtifactID = d.ArtifactID
group by b.name;

我认为不需要外部连接。您应该能够使用内部联接，除非有没有文档的批处理。如果您确实使用外部联接，那么从批处理开始比从文档开始更有意义，因为您是在批处理级别进行聚合的

select
    b.name, 
    count(db.DocumentArtifactID) as documents,
    -- count only completed
    count(case when d.Testcompleted = 1 then d.ArtifactID end) as reviewed,
    -- if the minimum = 1 there's no 0 or NULL
    case when min(cast(Testcompleted as tinyint)) = 1 then 'yes' else 'no' end as completed
from
    #Batch b

    left join #DocumentBatch db
    on db.BatchArtifactID = b.ArtifactID

    left join #Document d
    on db.DocumentArtifactID = d.ArtifactID
group by b.name;

如果没有丢失的行，您可以切换到内部联接

---

如果没有丢失的行，您可以切换到内部联接…

那么，当一个集合的SUMTestCompleted等于同一集合的计数时？@thursdaysgeek Correct:为什么允许空值？那么，当一个集合的SUMTestCompleted等于同一集合的计数时？@thursdaysgeek Correct:你为什么允许空值？我不确定你是否想计算零。如果TestCompleted是零呢？您应该改用SUMd.Testcompleted。事实上-只有当Testcompleted的值=1时，文档才被视为已审阅。在本例中，0也被计数，这是一个错误的结论。我认为您不确定是否要计数0。如果TestCompleted为零怎么办？您应该改用SUMd.Testcompleted。事实上-只有当Testcompleted的值=1时，文档才被视为已审阅。在这种情况下，0也被计数，从而得出错误的结论。我得到一个错误：操作数数据类型位对于min运算符无效？@Pr0no:您没有说它是位，好吧，这是0/1的自然选择。您必须强制转换它，我将编辑我的答案。我得到一个错误：操作数数据类型位对于最小运算符无效？@Pr0no:您没有告诉我它是位，好吧，这是0/1的自然选择。你必须投下它，我会编辑我的答案。