Sql 查询获取瑞士境内计数至少为1的名称

有没有办法解决这个问题

在下面的查询中，我想将所有在瑞士计数至少为1的姓名的结果输入到组合中

我已经尝试按照下面的步骤创建临时表，我认为它是可行的，但必须有一个最简单的方法来解决：

SELECT c.name, 
COUNT(CASE WHEN country = 'Germany' THEN 1 END) as 'Germany', 
COUNT(CASE WHEN country = 'London' THEN 1 END) as 'London',     
COUNT(CASE WHEN country = 'Switzerland' THEN 1 END) as 'Switzerland',   
COUNT(CASE WHEN country NOT IN('London', 'Ireland') THEN 1 END) as 'others' 
FROM a_products p 
JOIN a_customers c 
on id_customer = c.id 
Group By name

潜在解决方案：

select *
into #Swiss
from a_products
where country = 'Switzerland' 

SELECT c.name, 
COUNT(CASE WHEN country = 'Germany' THEN 1 END) as 'Germany', 
COUNT(CASE WHEN country = 'London' THEN 1 END) as 'London',     
COUNT(CASE WHEN country = 'Switzerland' THEN 1 END) as 'Switzerland',   
COUNT(CASE WHEN country NOT IN('London', 'Ireland') THEN 1 END) as 'others' 
FROM a_products p 
JOIN a_customers c 
on p.id_customer = c.id 
JOIN #Swiss s
on p.id_customer = s.id_customer
where s.id_customer is not null
Group By name

---

count用于非空值，并且当country=“…”始终为！=在这种情况下，从null开始，您可以尝试使用SUM，并将选中值管理为1，而将未选中值管理为0

SELECT c.name, 
SUM(CASE WHEN country = 'Germany' THEN 1 ELSE 0 END ) as Germany, 
SUM(CASE WHEN country = 'London' THEN 1 ELSE 0 END ) as London,     
SUM(CASE WHEN country = 'Switzerland' THEN 1 ELSE 0 END ) as Switzerland,   
SUM(CASE WHEN country NOT IN('London', 'Ireland') THEN 1 ELSE 0 END ) as others
FROM a_products p 
JOIN a_customers c 
on id_customer = c.id 
Group By name

对于flilter来说，瑞士的价值可以用

SELECT c.name, 
SUM(CASE WHEN country = 'Germany' THEN 1 ELSE 0 END ) as Germany, 
SUM(CASE WHEN country = 'London' THEN 1 ELSE 0 END ) as London,     
SUM(CASE WHEN country = 'Switzerland' THEN 1 ELSE 0 END ) as Switzerland,   
SUM(CASE WHEN country NOT IN('London', 'Ireland') THEN 1 ELSE 0 END ) as others
FROM a_products p 
JOIN a_customers c 
on id_customer = c.id 
Group By name
HAVING SUM(CASE WHEN country = 'Switzerland' THEN 1 ELSE 0 END ) >=1 

或者干脆

SELECT c.name,  
SUM(CASE WHEN country = 'Switzerland' THEN 1 ELSE 0 END ) as Switzerland 
FROM a_products p 
JOIN a_customers c 
on id_customer = c.id 
Group By name
HAVING SUM(CASE WHEN country = 'Switzerland' THEN 1 ELSE 0 END ) >=1 

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请提供样本输入和输出。这将很容易检查。：-）非常感谢你@Alexansanchez如果我的答案是正确的，请（过去15分钟）将其标记为已接受…看看这里我是如何将SUM替换为have SUM（当country='switzer'然后1 ELSE 0 END）>1（当country='switzer'然后1 ELSE 0 END）>=1，这正好是我所需要的：）@Alexansanchez..正确答案更新为>=