Sql oracle 10g报告中的错误计算

我们在oracle 10g report builder中创建了两个公式列，当我们减去这些公式列时，答案是错误的

1：第一个公式列

function sale_formulaFormula return Number is

begin
DECLARE
        BALANCE NUMBER;
        n number;
        BEGIN
   SELECT NVL(SUM(PLD.DR),0)-NVL(SUM(PLD.CR),0)
   INTO BALANCE
   FROM 
   LEDGER PLD
  WHERE 
  (PLD.d_ID in (9)) AND PLD.LD_DATE BETWEEN :P_FROM_DATE AND :P_TO_DATE;
        return balance;
        end;
end;

---

2：第二个公式列

    function expence_formulaFormula return Number is
begin
  DECLARE
        BALANCE NUMBER;
        n number;
        BEGIN
   SELECT NVL(SUM(PLD.DR),0)-NVL(SUM(PLD.CR),0)
   INTO BALANCE
   FROM 
   LEDGER PLD
  WHERE 
  (PLD.d_ID in (10,19,20,5,18)) AND PLD.LD_DATE BETWEEN :P_FROM_DATE AND :P_TO_DATE;
        return balance;
        end;
end;

当我在其他公式列中减去这些公式列，但答案不是真的

3：

---

从你的代码开始，我想说函数创建本身是错误的，它不会遵守

其次，我按照你的步骤，检查我得到了什么结果

create table LEDGER(d_ID number,dr number, cr number,LD_DATE date);
--------------------------------------------------------------

Insert into LEDGER   (D_ID, DR, CR, LD_DATE)
 Values   (9, 12, 43, TO_DATE('08/30/2016 00:00:00', 'MM/DD/YYYY HH24:MI:SS'));
Insert into LEDGER   (D_ID, DR, CR, LD_DATE)
 Values  (9, 100, 200, TO_DATE('08/30/2016 00:00:00', 'MM/DD/YYYY HH24:MI:SS'));
Insert into LEDGER    (D_ID, DR, CR, LD_DATE)
 Values  (18, 899, 786, TO_DATE('08/30/2016 00:00:00', 'MM/DD/YYYY HH24:MI:SS'));
Insert into LEDGER (D_ID, DR, CR, LD_DATE)
 Values (19, 665, 77, TO_DATE('08/30/2016 00:00:00', 'MM/DD/YYYY HH24:MI:SS'));
Insert into LEDGER   (D_ID, DR, CR, LD_DATE)
 Values  (9, 354, 35, TO_DATE('08/30/2016 00:00:00', 'MM/DD/YYYY HH24:MI:SS'));
Insert into LEDGER  (D_ID, DR, CR, LD_DATE)
 Values (5, 43.43, 89.4, TO_DATE('08/30/2016 00:00:00', 'MM/DD/YYYY HH24:MI:SS'));
Insert into LEDGER (D_ID, DR, CR, LD_DATE)
 Values  (10, 77, 654, TO_DATE('08/30/2016 00:00:00', 'MM/DD/YYYY HH24:MI:SS'));
Insert into LEDGER (D_ID, DR, CR, LD_DATE)
 Values  (9, 75, 97, TO_DATE('08/30/2016 00:00:00', 'MM/DD/YYYY HH24:MI:SS'));
Insert into LEDGER  (D_ID, DR, CR, LD_DATE)
 Values  (9, 59.45, 69.3, TO_DATE('08/30/2016 00:00:00', 'MM/DD/YYYY HH24:MI:SS'));
COMMIT;

--------------------------------------------------------

--1: first formula column

create or replace function sale_formulaFormula 
return Number is
BALANCE NUMBER;
n number;
BEGIN

   SELECT NVL(SUM(PLD.DR),0)- NVL(SUM(PLD.CR),0)
     INTO BALANCE
   FROM LEDGER PLD
   WHERE (PLD.d_ID in (9)) ;
   --Commenting since am taking only 1 day data
   --AND PLD.LD_DATE BETWEEN :P_FROM_DATE AND :P_TO_DATE; 

   Return balance;

end;

--Call
select sale_formulaFormula from dual; 

--Got result -- 156.15

--------------------------------------------------------------------------------

--2: second formula column
create or replace function expence_formulaFormula 
return Number is
BALANCE NUMBER;
n number;
BEGIN

    SELECT NVL(SUM(PLD.DR),0)-NVL(SUM(PLD.CR),0)
    INTO BALANCE
    FROM  LEDGER PLD
    WHERE (PLD.d_ID in (10,19,20,5,18));
    --Commenting since am taking only 1 day data 
    --AND PLD.LD_DATE BETWEEN :P_FROM_DATE AND :P_TO_DATE;

  Return balance;

end;

------------------------------------------------   
--Call
select expence_formulaFormula from dual;

--Got result  -- 78.03
----------------------------------------------------

--3 Function 3
create or replace function CF_4Formula 
return Char is
begin
  --return type is char so converting the result to char 
  return to_char(nvl(sale_formulaFormula,0) - nvl(expence_formulaFormula,0));
end;


--Call
select CF_4Formula from dual;

得到的结果-->156.15-78.03=78.12，这是正确的

---

从你的代码开始，我想说函数创建本身是错误的，它不会遵守

其次，我按照你的步骤，检查我得到了什么结果

create table LEDGER(d_ID number,dr number, cr number,LD_DATE date);
--------------------------------------------------------------

Insert into LEDGER   (D_ID, DR, CR, LD_DATE)
 Values   (9, 12, 43, TO_DATE('08/30/2016 00:00:00', 'MM/DD/YYYY HH24:MI:SS'));
Insert into LEDGER   (D_ID, DR, CR, LD_DATE)
 Values  (9, 100, 200, TO_DATE('08/30/2016 00:00:00', 'MM/DD/YYYY HH24:MI:SS'));
Insert into LEDGER    (D_ID, DR, CR, LD_DATE)
 Values  (18, 899, 786, TO_DATE('08/30/2016 00:00:00', 'MM/DD/YYYY HH24:MI:SS'));
Insert into LEDGER (D_ID, DR, CR, LD_DATE)
 Values (19, 665, 77, TO_DATE('08/30/2016 00:00:00', 'MM/DD/YYYY HH24:MI:SS'));
Insert into LEDGER   (D_ID, DR, CR, LD_DATE)
 Values  (9, 354, 35, TO_DATE('08/30/2016 00:00:00', 'MM/DD/YYYY HH24:MI:SS'));
Insert into LEDGER  (D_ID, DR, CR, LD_DATE)
 Values (5, 43.43, 89.4, TO_DATE('08/30/2016 00:00:00', 'MM/DD/YYYY HH24:MI:SS'));
Insert into LEDGER (D_ID, DR, CR, LD_DATE)
 Values  (10, 77, 654, TO_DATE('08/30/2016 00:00:00', 'MM/DD/YYYY HH24:MI:SS'));
Insert into LEDGER (D_ID, DR, CR, LD_DATE)
 Values  (9, 75, 97, TO_DATE('08/30/2016 00:00:00', 'MM/DD/YYYY HH24:MI:SS'));
Insert into LEDGER  (D_ID, DR, CR, LD_DATE)
 Values  (9, 59.45, 69.3, TO_DATE('08/30/2016 00:00:00', 'MM/DD/YYYY HH24:MI:SS'));
COMMIT;

--------------------------------------------------------

--1: first formula column

create or replace function sale_formulaFormula 
return Number is
BALANCE NUMBER;
n number;
BEGIN

   SELECT NVL(SUM(PLD.DR),0)- NVL(SUM(PLD.CR),0)
     INTO BALANCE
   FROM LEDGER PLD
   WHERE (PLD.d_ID in (9)) ;
   --Commenting since am taking only 1 day data
   --AND PLD.LD_DATE BETWEEN :P_FROM_DATE AND :P_TO_DATE; 

   Return balance;

end;

--Call
select sale_formulaFormula from dual; 

--Got result -- 156.15

--------------------------------------------------------------------------------

--2: second formula column
create or replace function expence_formulaFormula 
return Number is
BALANCE NUMBER;
n number;
BEGIN

    SELECT NVL(SUM(PLD.DR),0)-NVL(SUM(PLD.CR),0)
    INTO BALANCE
    FROM  LEDGER PLD
    WHERE (PLD.d_ID in (10,19,20,5,18));
    --Commenting since am taking only 1 day data 
    --AND PLD.LD_DATE BETWEEN :P_FROM_DATE AND :P_TO_DATE;

  Return balance;

end;

------------------------------------------------   
--Call
select expence_formulaFormula from dual;

--Got result  -- 78.03
----------------------------------------------------

--3 Function 3
create or replace function CF_4Formula 
return Char is
begin
  --return type is char so converting the result to char 
  return to_char(nvl(sale_formulaFormula,0) - nvl(expence_formulaFormula,0));
end;


--Call
select CF_4Formula from dual;

得到的结果-->156.15-78.03=78.12，这是正确的

---

你能不能也提供一些样本数据。向我们展示您的函数返回的值以及此处期望的值。该函数不会返回

True

，您的公式将返回一个数值，该数值将由函数转换为

Char

。您能否同时提供一些示例数据。显示您的函数返回的值以及此处的预期值。该函数不会返回

True

，您的公式将返回一个数值，该数值将由函数转换为

Char

。