SQL：如何检查组内的值？

我有一张这样的桌子：

对于每个TaskConfigId，都有一个TaskGuid。如果同一TaskConfigId的TaskGuid相同，则它们似乎用于同一任务。通常，TaskStatusId为10或20。当发生某些事情时，TaskStatusId将是其他值，即15。但对于每个任务，它总是有10和20个

因此，如果任务的状态为10和20，则表示没有发生任何特殊情况

现在，我想了解TaskConfigId（例如100）的最后一个CreatedDate是什么时候，它只有TaskStatusId 10和20，没有其他值。因此，如果TaskConfigId为40，则突出显示的大小写不正确

这是我的

SELECT TOP (1) CreatedDate
FROM [aptfeed].[TaskTracking]
WHERE TaskGuid IN (
        SELECT TaskGuid
        FROM [aptfeed].[TaskTracking]
        WHERE TaskConfigId = 100
        GROUP BY TaskGuid HAVING COUNT(*) = 2               
        )
    AND TaskStatusId = 10   -- start
ORDER BY CreatedDate DESC

基本上，它为TaskConfigId分组TaskGuid，确保它有2个条目。对它进行排序，然后得到最后一个

我的问题是：如果我想确保这两个条目是10和20（如果我们可以确保顺序是先10，然后20，更好），该怎么办

我试过这个：

SELECT TOP (1) CreatedDate
FROM [aptfeed].[TaskTracking]
WHERE TaskGuid IN (
        SELECT TaskGuid
        FROM [aptfeed].[TaskTracking]
        WHERE TaskConfigId = 100
            AND (TaskStatusId = 10 OR TaskStatusId = 20)
        GROUP BY TaskGuid HAVING COUNT(*) = 2               
        )
    AND TaskStatusId = 10   -- start
ORDER BY CreatedDate DESC

但这不起作用，因为它首先过滤了所有其他TaskStatusId。因此，几乎所有计数（*）都将为2，即屏幕截图中的TaskConfigId=40将被选中，因为第14行将被过滤

另外，我觉得我使用的查询速度很慢，因为它必须为TaskConfigId对所有TaskGuid进行分组。有什么改进的建议吗

---

谢谢

您可以通过稍微调整原始查询来找到TaskGuid：

SELECT TaskGuid
FROM [aptfeed].[TaskTracking]
WHERE TaskConfigId = 100
GROUP BY TaskGuid
HAVING COUNT(*) = 2
AND    MIN(TaskStatusId) = 10
AND    MAX(TaskStatusId) = 20

这将解决查找包含10和20（不一定按该顺序）而不包含其他内容的组的问题

但您也可以使用窗口功能：

SELECT TaskConfigId, TaskGuid, MAX(CreatedDate)
FROM (
    SELECT TaskConfigId
         , TaskGuid
         , ItemCount = COUNT(*) OVER (PARTITION BY TaskConfigId, TaskGuid)
         , FirstStatus = FIRST_VALUE(TaskStatusId) OVER (PARTITION BY TaskConfigId, TaskGuid ORDER BY CreatedDate)
         , LastStatus = LAST_VALUE(TaskStatusId) OVER (PARTITION BY TaskConfigId, TaskGuid ORDER BY CreatedDate)
         , CreatedDate
    FROM [aptfeed].[TaskTracking]
) AS cte
WHERE ItemCount = 2
AND FirstStatus = 10
AND LastStatus = 20
GROUP BY TaskConfigId, TaskGuid

---

通过稍微调整原始查询，可以找到TaskGuid：

SELECT TaskGuid
FROM [aptfeed].[TaskTracking]
WHERE TaskConfigId = 100
GROUP BY TaskGuid
HAVING COUNT(*) = 2
AND    MIN(TaskStatusId) = 10
AND    MAX(TaskStatusId) = 20

这将解决查找包含10和20（不一定按该顺序）而不包含其他内容的组的问题

但您也可以使用窗口功能：

SELECT TaskConfigId, TaskGuid, MAX(CreatedDate)
FROM (
    SELECT TaskConfigId
         , TaskGuid
         , ItemCount = COUNT(*) OVER (PARTITION BY TaskConfigId, TaskGuid)
         , FirstStatus = FIRST_VALUE(TaskStatusId) OVER (PARTITION BY TaskConfigId, TaskGuid ORDER BY CreatedDate)
         , LastStatus = LAST_VALUE(TaskStatusId) OVER (PARTITION BY TaskConfigId, TaskGuid ORDER BY CreatedDate)
         , CreatedDate
    FROM [aptfeed].[TaskTracking]
) AS cte
WHERE ItemCount = 2
AND FirstStatus = 10
AND LastStatus = 20
GROUP BY TaskConfigId, TaskGuid

---

如果我没有弄错的话，您将尝试获取每个只有

TaskStatusId

10和20（这两个记录都应该存在）的

TaskConfigId

，并获取每个记录的最后一个

CreatedDate

你可以这样做：

SELECT *
FROM (
    SELECT *
    , COUNT(TaskGuid) OVER (PARTITION BY TaskGuid) TaskCount 
    , ROW_NUMBER() OVER (PARTITION BY TaskGuid ORDER BY CreatedDate DESC) RN    
    FROM 
        [aptfeed].[TaskTracking]
    WHERE 
        TaskConfigId = 100
    AND TaskStatusId IN(10,20)
) D
WHERE 
    TaskCount = 2
AND RN = 1

---

如果我没有弄错的话，您将尝试获取每个只有

TaskStatusId

10和20（这两个记录都应该存在）的

TaskConfigId

，并获取每个记录的最后一个

CreatedDate

你可以这样做：

SELECT *
FROM (
    SELECT *
    , COUNT(TaskGuid) OVER (PARTITION BY TaskGuid) TaskCount 
    , ROW_NUMBER() OVER (PARTITION BY TaskGuid ORDER BY CreatedDate DESC) RN    
    FROM 
        [aptfeed].[TaskTracking]
    WHERE 
        TaskConfigId = 100
    AND TaskStatusId IN(10,20)
) D
WHERE 
    TaskCount = 2
AND RN = 1

---

如果您试图获取TaskStatusId为10和20的每个TaskConfigId（两条记录都应该存在），并查找最后一个CreatedDate，请尝试以下操作：

SELECT TaskGuid
FROM [TaskTracking]
WHERE TaskConfigId = 100
AND (TaskStatusId = 10 OR TaskStatusId = 20)
GROUP BY TaskGuid HAVING COUNT(*) = 2  

如果需要，还可以显示日期：

SELECT TaskGuid, MAX(CreatedDate) AS LastDate
FROM [TaskTracking]
WHERE TaskConfigId = 100
AND (TaskStatusId = 10 OR TaskStatusId = 20)
GROUP BY TaskGuid HAVING COUNT(*) = 2  

---

如果您试图获取TaskStatusId为10和20的每个TaskConfigId（两条记录都应该存在），并查找最后一个CreatedDate，请尝试以下操作：

SELECT TaskGuid
FROM [TaskTracking]
WHERE TaskConfigId = 100
AND (TaskStatusId = 10 OR TaskStatusId = 20)
GROUP BY TaskGuid HAVING COUNT(*) = 2  

如果需要，还可以显示日期：

SELECT TaskGuid, MAX(CreatedDate) AS LastDate
FROM [TaskTracking]
WHERE TaskConfigId = 100
AND (TaskStatusId = 10 OR TaskStatusId = 20)
GROUP BY TaskGuid HAVING COUNT(*) = 2  

---

我真的不理解你试图实现的逻辑。我真的不理解你试图实现的逻辑。