按别名分组的SQL

我有一个smallint列，用于表示时间。我编写了下面的代码，根据时间推导出一个结果：

        CASE
    WHEN 
        CONVERT(varchar, t0.U_ORC_BE_ProdTime, 108) BETWEEN '07:00:00' AND '19:00:00' THEN '1'
    ELSE '2'
END  AS [Shift],
    --If time is between 7am and 7pm then Shift 1, else Shift 2

我想将它插入到我已有的查询中，然后让它也按班次分组

    SELECT 

T6.U_ORC_BE_StyleName AS [Style Name],
T0.[ItemCode],
STUFF(T0.[ItemCode], 1, 6, '') AS [Shortened ItemCode],
SUM(T0.[PlannedQty]) AS [Planned Qty],
SUM(T0.CmpltQty) AS [Actual Qty], 
SUM(T0.CmpltQty) - SUM(T0.PlannedQty) AS [Qty Difference],
SUM(T5.U_ORC_BE_HECTOLITER * T0.CmpltQty) AS [Total Hectoliters],

CASE
    WHEN [.......]
    THEN
    WHEN [.......]
    THEN
END AS [Line],

T0.U_ORC_BE_ProdDate AS [Date Produced]

    FROM [.......]

    GROUP BY T6.U_ORC_BE_StyleName, T0.[ItemCode], T5.Code , T0.U_ORC_BE_ProdDate

它不断抛出一个错误，虽然我怀疑这是由于试图按别名分组

---

“每个GROUP BY表达式必须至少包含一个非外部引用的列。”

要按计算列（如case语句）进行分组，还必须将该语句包含在GROUP BY中。例如：

SELECT
  CASE ... END AS CaseStatement,
  [YourColumns]
FROM YourTable
GROUP BY CASE ... END

---

要按计算列（如case语句）分组，还必须在GROUPBY中包含该语句。例如：

SELECT
  CASE ... END AS CaseStatement,
  [YourColumns]
FROM YourTable
GROUP BY CASE ... END

---

如错误所述，您不能按别名分组。当您的小组结束后，您必须复制整个案例

 select 
 ....
 group by 
 T6.U_ORC_BE_StyleName, T0.[ItemCode], T5.Code , T0.U_ORC_BE_ProdDate,
 CASE
    WHEN [.......]
    THEN
    WHEN [.......]
    THEN
END 

---

如错误所述，您不能按别名分组。当您的小组结束后，您必须复制整个案例

 select 
 ....
 group by 
 T6.U_ORC_BE_StyleName, T0.[ItemCode], T5.Code , T0.U_ORC_BE_ProdDate,
 CASE
    WHEN [.......]
    THEN
    WHEN [.......]
    THEN
END 

---

抛出的错误是什么？抱歉，我已编辑问题以包含错误。选择中的

T0.U\U ORC\U BE\U ProdDate

，如果未选择它，则从

Group by

中删除抛出的错误是什么？抱歉，我已编辑问题以包含错误。选择中的

T0.U\U ORC\U BE\U ProdDate

，如果您没有选择它，那么从

组中删除的
看起来很明显！非常感谢。看起来很明显！非常感谢。这样给我就更有意义了。谢谢你的帮助。这样给我会更有意义。谢谢你的帮助。