Sql Oracle-用于获取重复字段的基于条件的查询

有人能帮我查询这个复杂的场景吗

我有以下三张桌子

表格：位置

ID      LOCATION_ID     START_DT    END_DT
21234   123             19-JUL-17   (null)
12345   345             19-JUL-17   (null)
12345   456             19-JUL-17   19-DEC-17
12345   567             19-JUL-16   (null)
12345   678             19-JUL-16   (null)
12345   789             19-JUL-17   (null)
12345   890             19-JUL-17   (null)
23456   901             07-JAN-18   (null)
23456   902             19-JAN-17   (null)

表格：联系人组

LOCATION_ID     METHOD_ID
123             9999
345             8888
456             7777
567             6666
678             5555
789             4444
890             3333
901             2222
902             1111

表格：联系方式

METHOD_ID   REF_NUM     METHOD_TYPE
9999        24856584    CELL PHONE
8888        64896572    HOME PHONE
7777        65948725    HOME PHONE
6666        36564852    HOME PHONE
5555        abc@xyz.com PRIMARY EMAIL
4444        cde@xyz.com PRIMARY EMAIL
3333        45789658    ALTERNATE PHONE
2222        86594758    HOME PHONE
1111        59857468    HOME PHONE

预期结果：

ID      LOCATION_ID     REF_NUM         METHOD_TYPE     START_DT    END_DT
12345   567             36564852        HOME PHONE      19-JUL-16   (null)
12345   678             abc@xyz.com     PRIMARY EMAIL   19-JUL-16   (null)
23456   902             59857468        HOME PHONE      19-JAN-17   (null)

标准：

ID      LOCATION_ID     REF_NUM         METHOD_TYPE     START_DT    END_DT
12345   567             36564852        HOME PHONE      19-JUL-16   (null)
12345   678             abc@xyz.com     PRIMARY EMAIL   19-JUL-16   (null)
23456   902             59857468        HOME PHONE      19-JAN-17   (null)

返回的字段

• END_DT为空（即激活的ID）
• 方法类型字段重复（即REF\u NUM不必相同，但 方法（类型重复）
• 选择多个值中最早的值（即 多个重复字段，结果位置\u ID必须为 其中最早的是通过比较START_DT）

在某种程度上，我一直在尝试

SELECT L.id, 
       L.location_id, 
       CM.ref_num, 
       CM.method_type, 
       L.start_dt, 
       L.end_dt 
FROM   location L 
       JOIN contactgroup CG 
         ON CG.location_id = L.location_id 
       JOIN contactmethod CM 
         ON CM.method_id = CG.method_id 
WHERE  L.end_dt IS NULL 
GROUP  BY L.id, 
          L.location_id, 
          CM.ref_num, 
          CM.method_type, 
          L.start_dt, 
          L.end_dt 
HAVING Count(*) > 1 

---

单靠GROUPBY和count子句无法实现这一点。您必须使用子查询。

---

此外，纯粹从提交的数据来看，人们需要做出假设。ref_num是否与此相关？因为ref_num中有所有唯一的值。

单靠group by和count子句无法实现这一点。您必须使用子查询。

---

此外，纯粹从提交的数据来看，人们需要做出假设。ref_num是否与此相关？因为在ref_num中有所有唯一的值。

所以可以实现如下所示的预期结果-

SELECT 
    ID,LOCATION_ID,REF_NUM,METHOD_TYPE,START_DT,END_DT
FROM 
(
    SELECT 
        A.* ,
        DENSE_RANK() OVER (PARTITION BY ID, METHOD_TYPE ORDER BY START_DT DESC) AS RNK
    FROM 
    (
        SELECT 
            L.ID,L.LOCATION_ID,CM.REF_NUM,CM.METHOD_TYPE,L.START_DT,L.END_DT
        FROM 
            LOCATION L, CONTACTMETHOD CM, CONTACTGROUP CG
        WHERE 
            L.LOCATION_ID = CG.LOCATION_ID
            AND CG.METHOD_ID = CM.METHOD_ID
            AND L.END_DT IS NULL
    ) A
) 
WHERE RNK = 2
;

        ID LOCATION_ID REF_NUM              METHOD_TYPE          START_DT  END_DT
---------- ----------- -------------------- -------------------- --------- ---------
     12345         567 36564852             HOMEPHONE            19-JUL-16
     12345         678 abc@xyz.com          PRIMARYEMAIL         19-JUL-16
     23456         902 59857468             HOMEPHONE            19-JAN-17

结果：-

SELECT 
    ID,LOCATION_ID,REF_NUM,METHOD_TYPE,START_DT,END_DT
FROM 
(
    SELECT 
        A.* ,
        DENSE_RANK() OVER (PARTITION BY ID, METHOD_TYPE ORDER BY START_DT DESC) AS RNK
    FROM 
    (
        SELECT 
            L.ID,L.LOCATION_ID,CM.REF_NUM,CM.METHOD_TYPE,L.START_DT,L.END_DT
        FROM 
            LOCATION L, CONTACTMETHOD CM, CONTACTGROUP CG
        WHERE 
            L.LOCATION_ID = CG.LOCATION_ID
            AND CG.METHOD_ID = CM.METHOD_ID
            AND L.END_DT IS NULL
    ) A
) 
WHERE RNK = 2
;

        ID LOCATION_ID REF_NUM              METHOD_TYPE          START_DT  END_DT
---------- ----------- -------------------- -------------------- --------- ---------
     12345         567 36564852             HOMEPHONE            19-JUL-16
     12345         678 abc@xyz.com          PRIMARYEMAIL         19-JUL-16
     23456         902 59857468             HOMEPHONE            19-JAN-17

---

可通过以下方式实现所需结果-

SELECT 
    ID,LOCATION_ID,REF_NUM,METHOD_TYPE,START_DT,END_DT
FROM 
(
    SELECT 
        A.* ,
        DENSE_RANK() OVER (PARTITION BY ID, METHOD_TYPE ORDER BY START_DT DESC) AS RNK
    FROM 
    (
        SELECT 
            L.ID,L.LOCATION_ID,CM.REF_NUM,CM.METHOD_TYPE,L.START_DT,L.END_DT
        FROM 
            LOCATION L, CONTACTMETHOD CM, CONTACTGROUP CG
        WHERE 
            L.LOCATION_ID = CG.LOCATION_ID
            AND CG.METHOD_ID = CM.METHOD_ID
            AND L.END_DT IS NULL
    ) A
) 
WHERE RNK = 2
;

        ID LOCATION_ID REF_NUM              METHOD_TYPE          START_DT  END_DT
---------- ----------- -------------------- -------------------- --------- ---------
     12345         567 36564852             HOMEPHONE            19-JUL-16
     12345         678 abc@xyz.com          PRIMARYEMAIL         19-JUL-16
     23456         902 59857468             HOMEPHONE            19-JAN-17

结果：-

SELECT 
    ID,LOCATION_ID,REF_NUM,METHOD_TYPE,START_DT,END_DT
FROM 
(
    SELECT 
        A.* ,
        DENSE_RANK() OVER (PARTITION BY ID, METHOD_TYPE ORDER BY START_DT DESC) AS RNK
    FROM 
    (
        SELECT 
            L.ID,L.LOCATION_ID,CM.REF_NUM,CM.METHOD_TYPE,L.START_DT,L.END_DT
        FROM 
            LOCATION L, CONTACTMETHOD CM, CONTACTGROUP CG
        WHERE 
            L.LOCATION_ID = CG.LOCATION_ID
            AND CG.METHOD_ID = CM.METHOD_ID
            AND L.END_DT IS NULL
    ) A
) 
WHERE RNK = 2
;

        ID LOCATION_ID REF_NUM              METHOD_TYPE          START_DT  END_DT
---------- ----------- -------------------- -------------------- --------- ---------
     12345         567 36564852             HOMEPHONE            19-JUL-16
     12345         678 abc@xyz.com          PRIMARYEMAIL         19-JUL-16
     23456         902 59857468             HOMEPHONE            19-JAN-17

---

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