从select插入MS SQL输出和insert

我试图弄清楚如何从SELECT组合INSERT并返回插入记录的id值

INSERT INTO [someDB].[dbo].[OBJ] ( column1, column2, column3 ) 
OUTPUT inserted.ID (SELECT TOP 1 590675, column2, column3 
                    FROM [someDB].[dbo].[OBJ] WHERE ID = 317817)

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这里的语法有点错误

你想要：

INSERT INTO [someDB].[dbo].[OBJ] ( column1, column2, column3 )
OUTPUT inserted.ID
SELECT TOP 1
       590675,
       column2,
       column3
FROM [someDB].[dbo].[OBJ] WHERE ID = 317817
ORDER BY ...?; --You have a TOP 1, thus you really need an ORDER BY as well.

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如果您试图在INSERT语句之后获取新ID，则可以使用。例如：

INSERT INTO [someDB].[dbo].[OBJ] ( column1, column2, column3 )

SELECT TOP 1
   590675,
   column2,
   column3
FROM [someDB].[dbo].[OBJ] WHERE ID = 317817
ORDER BY ...
SELECT SCOPE_IDENTITY(); -- Last identity generated in current session and current scope
SELECT @@IDENTITY; -- Last identity generated in current session across all scopes
SELECT IDENT_CURRENT([someDB].[dbo].[OBJ]) -- Last identity generated for the given table in any session and any scope

因为您只插入一行，所以SCOPE_IDENTIY将是最好的方法

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希望能有帮助。

你的问题是什么？谢谢，括号真的不应该在那里。