Sql 如何在Oracle中的表中查找特定值？

假设我的表是TEST_123，它有以下记录：

id |  cid | result
------------------
1  |  C-1 |   TAM
2  |  C-1 |   TAM
3  |  C-2 |   RAM
4  |  C-2 |   TAM
5  |  C-3 |   SAM
6  |  C-3 |   SAM

---

现在我想要这样的cid，它只有一种结果，所以答案应该是C-1和C-3，而不是C-2，因为它有两种不同类型的结果。需要Oracle查询吗？

使用存在，这有点棘手，因为每个组的结果应该是相同的

 select t1.* from TEST_123 t1 where exists(
             select 1 from TEST_123 t2 where t2.cid=t1.cid
                                      and t2.result=t1.result
                                      group by t2.cid,t2.result
                                      having count(*)=
                                       (select count(*) from TEST_123 t3
                                       where t3.cid=t2.cid)
                                      )

例

with TEST_123 as
(
select 1 as id , 'c-1' as cid , 'tam' as result from dual
union all
select 2 as id , 'c-1' as cid , 'tam' as result from dual
union all
select 3 as id , 'c-2' as cid , 'tam' as result from dual
union all
select 4 as id , 'c-2' as cid , 'ram' as result from dual

)

select distinct t1.cid from TEST_123 t1 where exists(
                 select 1 from TEST_123 t2 where t2.cid=t1.cid
                                          and t2.result=t1.result
                                          group by t2.cid,t2.result
                                          having count(*)=
                                           (select count(*) from TEST_123 t3
                                           where t3.cid=t2.cid)
                                          )

---

使用存在，这有点棘手，因为每个小组的结果应该是相同的

 select t1.* from TEST_123 t1 where exists(
             select 1 from TEST_123 t2 where t2.cid=t1.cid
                                      and t2.result=t1.result
                                      group by t2.cid,t2.result
                                      having count(*)=
                                       (select count(*) from TEST_123 t3
                                       where t3.cid=t2.cid)
                                      )

例

with TEST_123 as
(
select 1 as id , 'c-1' as cid , 'tam' as result from dual
union all
select 2 as id , 'c-1' as cid , 'tam' as result from dual
union all
select 3 as id , 'c-2' as cid , 'tam' as result from dual
union all
select 4 as id , 'c-2' as cid , 'ram' as result from dual

)

select distinct t1.cid from TEST_123 t1 where exists(
                 select 1 from TEST_123 t2 where t2.cid=t1.cid
                                          and t2.result=t1.result
                                          group by t2.cid,t2.result
                                          having count(*)=
                                           (select count(*) from TEST_123 t3
                                           where t3.cid=t2.cid)
                                          )

---

根据@zaynul的回答，这里是另一个变体：

with TEST_123 as
(
select 1 as id , 'c-1' as cid , 'tam' as result from dual
union all
select 2 as id , 'c-1' as cid , 'tam' as result from dual
union all
select 3 as id , 'c-2' as cid , 'tam' as result from dual
union all
select 4 as id , 'c-2' as cid , 'ram' as result from dual
)
select * from test_123 where cid in (
    select cid from test_123 group by cid having count(distinct result) = 1);

---

根据@zaynul的回答，这里是另一个变体：

with TEST_123 as
(
select 1 as id , 'c-1' as cid , 'tam' as result from dual
union all
select 2 as id , 'c-1' as cid , 'tam' as result from dual
union all
select 3 as id , 'c-2' as cid , 'tam' as result from dual
union all
select 4 as id , 'c-2' as cid , 'ram' as result from dual
)
select * from test_123 where cid in (
    select cid from test_123 group by cid having count(distinct result) = 1);

---

您只需要理解GROUPBY和HAVING子句

答案很简单

select cid
from TEST_123
group by cid
having count(distinct result) = 1

---

注释group by从CID中选择不同的键；having filters on条件对组中的所有记录都有效，在您的情况下countdistinct result=1

您只需要理解group BY和having子句

答案很简单

select cid
from TEST_123
group by cid
having count(distinct result) = 1

注释group by从CID中选择不同的键；having filters on条件对组中的所有记录都有效，在您的情况下countdistinct result=1

我应该为你工作

应该为您工作

我将使用不存在的：

我将使用不存在的：

---

欢迎来到堆栈溢出！问问题时请更具体一点：到目前为止，您用代码示例做了哪些尝试？/你期待什么你有什么错误？有关帮助，请查看欢迎使用堆栈溢出！问问题时请更具体一点：到目前为止，您用代码示例做了哪些尝试？/你期待什么你有什么错误？如需帮助，请查看“谢谢Marmite…”。。虽然它很好地回答了我的问题，但我被困在TEST_123组中的select cid上，因为cid的COUNTRUST=1，并没有将其放入distinct。。。但有一个疑问，当我为result=TAM放入where子句时，它给出了C1和C2，但我真正想要的只是C1，你能理解我吗？如果你过滤where only TAM，那么所有剩余的组每个定义只有一个键TAM，所以结果中的C2是可以的。如果您正在寻找一个只有一种结果类型（即TAM）的键，则必须将countdistinct result=1和maxresult='TAM'公式化，您可以很好地使用MINas，因为结果只有一个值。谢谢Marmite。。虽然它很好地回答了我的问题，但我被困在TEST_123组中的select cid上，因为cid的COUNTRUST=1，并没有将其放入distinct。。。但有一个疑问，当我为result=TAM放入where子句时，它给出了C1和C2，但我真正想要的只是C1，你能理解我吗？如果你过滤where only TAM，那么所有剩余的组每个定义只有一个键TAM，所以结果中的C2是可以的。如果您正在寻找一个只有一种结果类型（即TAM）的键，则必须将countdistinct result=1和maxresult='TAM'公式化，您可以很好地使用MINas，因为结果只有一个值。