基于Oracle的SQL查询

我换这张桌子有点麻烦：

我的表格是

style

（

id，style

）

我需要将单词“Style XX”更改为Coach XX，其中XX是偶数（0、2、4、6）

看起来是这样的：

id    Style      
------------
01   Coach-02 
02   Style-03 
03   Coach-04
04   Table
06   Chair

我知道它一定是这样的：为了使一个数字是偶数（0，2，4等等）

---

但是我真的不知道如何区分这些词：S

你的问题让我有点困惑，因为这些词与你的例子不太相符。无论如何，使用一个简单的

UPDATE

步骤怎么样，如下所示：

update your_table
from (
   select id
        , case
             when Style = 'Style-01' then 'Coach-02'
             when Style = 'Style-03' then 'Coach-04'
             when Style = 'Style-05' then 'Coach-06'
             when Style = 'Style-07' then 'Coach-08'
             when Style = 'Style-09' then 'Coach-00'
             end as new_style
   from  your_table
   where Style in ('Style-01','Style-03','Style-05'
                   'Style-07','Style-09'
   ) x

set Style = x.new_style

where your_table.id = x.id

我认为最好是显式地做事情，而不是试图解析一个值并进行算术运算。如果您需要重新访问代码，这样做会更容易理解

MERGE INTO style s
USING (
   SELECT id
   FROM style ss
   WHERE ss.style LIKE 'Style%'
   AND  mod(to_number(substr(ss.style,6)),2)=0)e
   ON (s.id = e.id
      )
 WHEN MATCHED THEN
  UPDATE SET style =replace(style,'Style','Coach');

---

SQLFIDLE:

如果需要更改数据：

update STYLES set STYLE = 'Coach-'||substr(STYLE,-2,2)
where STYLE like 'Style-__'
  and substr(STYLE,-2,2) between '00' and '99'
  and mod(to_number(substr(STYLE,-2,2)),2) = 0;

select 
  ID
 ,case
    when STYLE like 'Style-__'
     and substr(STYLE,-2,2) between '00' and '99'
     and mod(to_number(substr(STYLE,-2,2)),2) = 0
    then 'Coach-'||substr(STYLE,-2,2)
    else STYLE
  end as STYLE
from STYLES;

如果您只需要在读取数据时进行转换：

update STYLES set STYLE = 'Coach-'||substr(STYLE,-2,2)
where STYLE like 'Style-__'
  and substr(STYLE,-2,2) between '00' and '99'
  and mod(to_number(substr(STYLE,-2,2)),2) = 0;

select 
  ID
 ,case
    when STYLE like 'Style-__'
     and substr(STYLE,-2,2) between '00' and '99'
     and mod(to_number(substr(STYLE,-2,2)),2) = 0
    then 'Coach-'||substr(STYLE,-2,2)
    else STYLE
  end as STYLE
from STYLES;