Sql 为前一行添加值

Sql 为前一行添加值,sql,sql-server,sql-server-2012,Sql,Sql Server,Sql Server 2012,我有一个表分级机: +--------------------------+ |GraderName | Graded_Items | +--------------------------+ | A | 21 | | B | 7 | | C | 17 | | D | 91 | | E | 84 | | F

我有一个表
分级机

+--------------------------+
|GraderName | Graded_Items |
+--------------------------+
|    A      |       21     |
|    B      |        7     |
|    C      |       17     |
|    D      |       91     |
|    E      |       84     |
|    F      |       52     |
|    G      |       34     |
+--------------------------+
我想把第一行和第二行的
放在第二行<第一行、第二行和第三行的代码>总和
,放在第三行;如此类推到其他行。见下文:

+--------------------------------+
|GraderName | Graded_Items       |
+--------------------------------+
|    A      |21                  |
|    B      |21+7                |
|    C      |21+7+17             |
|    D      |21+7+17+91          |
|    E      |21+7+17+91+84       |
|    F      |21+7+17+91+84+52    |
|    G      |21+7+17+91+84+52+34 |
+--------------------------------+
我想达到这个结果:

+--------------------------+
|GraderName | Graded_Items |
+--------------------------+
|    A      |       21     |
|    B      |       28     |
|    C      |       45     |
|    D      |      136     |
|    E      |      220     |
|    F      |      272     |
|    G      |      306     |
+--------------------------+
我尝试了以下查询:

SELECT Grader,Graded_Items FROM Grader WHERE Grader='A'
UNION ALL
SELECT MAX(Grader),SUM(Graded_Items) FROM Grader WHERE Grader in ('A','B')
UNION ALL
SELECT MAX(Grader),SUM(Graded_Items) FROM Grader WHERE Grader in ('A','B','C')
UNION ALL
SELECT MAX(Grader),SUM(Graded_Items) FROM Grader WHERE Grader in ('A','B','C','D')
UNION ALL
SELECT MAX(Grader),SUM(Graded_Items) FROM Grader WHERE Grader in ('A','B','C','D','E')
UNION ALL
SELECT MAX(Grader),SUM(Graded_Items) FROM Grader WHERE Grader in ('A','B','C','D','E','F')
但是,我的问题是表一直在变化,例如
GraderName
同时填充其相应的
Graded\u项。还有其他方法可以达到我的预期结果吗?

使用
Sum over()
技巧获得运行总数

select GraderName, 
       sum(Graded_Items) over(order by GraderName) As Graded_Items
From yourtable  
使用
Sum over()

select GraderName, 
       sum(Graded_Items) over(order by GraderName) As Graded_Items
From yourtable  

哇!我不知道。我会帮上大忙的。谢谢^_^真 的!我不知道。我会帮上大忙的。谢谢^_^可能的重复可能的重复