sql查询以找出每个部门的插槽总数

我有一个表tempslotsassignedfordept，如下所示

DEPT        ScheduledStartDate          ScheduledEndDate            TotalSlots

DevEng      2012-07-17 00:00:00.000     2012-08-28 00:00:00.000     39
DevEng      2012-07-17 00:00:00.000     2012-08-31 00:00:00.000     18
DevEng      2012-07-18 00:00:00.000     2012-08-29 00:00:00.000     9
DevEng      2012-07-19 00:00:00.000     2012-08-30 00:00:00.000     40
Prod        2012-07-19 00:00:00.000     2012-08-30 00:00:00.000     8
Rel         2012-07-19 00:00:00.000     2012-08-30 00:00:00.000     19
Rel         2012-07-19 00:00:00.000     2013-08-15 00:00:00.000     1

我必须捕获每个部门总时段的上述总和。如果某个部门存在连续3天。
如果您看到上表，有一个department deveng的三个预定开始日期为2012-07-172012-07-182012-07-19。

我正在尝试使用下面的查询查看结果，请您帮助更多的实现查看确切的结果是什么

SELECT  Tmain.DepartmentCode, 
                CONVERT(VARCHAR(20), Tmain.ScheduledStartDate, 101) 'ScheduledStartDate',
                SUM(Tmain.TotalSlots) 'Tmain.TotalSlots',T1Sub.TotalSlots 'T1SubTotalSlots', T2Sub.TotalSlots 'T2SubTotalSlots'

                FROM    tempSlotsAssignedForDept Tmain

                        INNER   JOIN (Select    DATEADD(DAY,1,T1.ScheduledStartDate) 'ScheduledStartDate',SUM(T1.TotalSlots) 'TotalSlots'
                                        FROM    tempSlotsAssignedForDept  T1 
                                                INNER JOIN tempSlotsAssignedForDept Tmain                    
                                                ON (T1.ScheduledStartDate = dateadd(day, -1, tmain.ScheduledStartDate ) and  
                                                    T1.DepartmentCode = tmain.DepartmentCode)
                                                GROUP BY T1.ScheduledStartDate ) T1Sub                        
                        ON Tmain.ScheduledStartDate = T1Sub.ScheduledStartDate

                        INNER   JOIN (Select    DATEADD(DAY,2,T2.ScheduledStartDate) 'ScheduledStartDate',SUM(T2.TotalSlots) 'TotalSlots'
                                        FROM    tempSlotsAssignedForDept  T2 
                                                INNER JOIN tempSlotsAssignedForDept Tmain                    
                                                ON (T2.ScheduledStartDate = dateadd(day, -2, tmain.ScheduledStartDate ) and  
                                                    T2.DepartmentCode = tmain.DepartmentCode)
                                                GROUP BY T2.ScheduledStartDate ) T2Sub                
                        ON Tmain.ScheduledStartDate = T2Sub.ScheduledStartDate

                GROUP BY    Tmain.DepartmentCode,Tmain.ScheduledStartDate,T1Sub.TotalSlots , T2Sub.TotalSlots 
                ORDER BY Tmain.ScheduledStartDate  

上述查询的结果是

DepartmentCode  ScheduledStartDate  Tmain.TotalSlots    T1SubTotalSlots T2SubTotalSlots
DevEng          07/19/2012          40                  9               57
Prod            07/19/2012          8                   9               57
Rel             07/19/2012          20                  9               57  

最终结果应如下所示。
因为，prod和rel部门没有3天的scheduledstartdate系列

DepartmentCode  ScheduledStartDate  Tmain.TotalSlots    T1SubTotalSlots T2SubTotalSlots
DevEng          07/19/2012          40                  9               57  

---

请帮助。

以下是您正在寻找的答案：

Select * from 
(
Select DepartmentCode,ScheduledStartDate,[Tmain.TotalSlots]
,(Select SUM(T1.TotalSlots) from tempSlotsAssignedForDept  T1 where t1.departmentCode=a.DepartmentCode
and T1.ScheduledStartDate = dateadd(day, -1, a.ScheduledStartDate )) T1SubTotalSlots 
,(Select SUM(T1.TotalSlots) from tempSlotsAssignedForDept  T1 where t1.departmentCode=a.DepartmentCode
and T1.ScheduledStartDate = dateadd(day, -2, a.ScheduledStartDate )) T2SubTotalSlots 
from 
(
SELECT  Tmain.DepartmentCode, 
CONVERT(VARCHAR(20), Tmain.ScheduledStartDate, 101) ScheduledStartDate,
SUM(Tmain.TotalSlots) 'Tmain.TotalSlots'
--,(Select SUM(T1.TotalSlots) from tempSlotsAssignedForDept t1 where t1.DepartmentCode=tmain.departmentcode 
--and T1.ScheduledStartDate = dateadd(day, -1, tmain.ScheduledStartDate ))
FROM    tempSlotsAssignedForDept Tmain
GROUP BY    Tmain.DepartmentCode,Tmain.ScheduledStartDate
) a) b where [Tmain.TotalSlots] is not null and T1SubTotalSlots is not null and T2SubTotalSlots is not null

---

恐怕你这样描述它真的没有道理。您试图对Tmain.TotalSlots求和，但在最终结果中，您显示了Tmain.TotalSlots，即40小时？你不想让它持续80小时吗？请clarify@jeschafe，是的，Tmain.TotalSlots应该是40，因为DepartDev只有3个连续日。你说“串行”是什么意思？串行的意思，请在tempslotsassignedfordept表中找到，deveng部门有三个连续的计划开工日期，即2012-07-172012-07-182012-07-19。如果连续三天以上，您希望发生什么？只算最后三个？都是吗？每三天数一次（剩菜怎么办）？只有在三天确实存在的情况下？不要放弃！直接回答，我喜欢。非常感谢。