带分隔符的SQL子查询

我需要能够通过分隔符*将一个字符串拆分为单独的列，而不包括* 表x中的y列如下所示：

column y
*1HS*AB*GXX*123*02*PA45*2013-08-10*
*1R1*B*GX*123*02*PA45*2013-08-10*
*1HS*B*GX*13*01*PA45*2013-08-01*
*1P*C*GXX*123*02*PA45*2013-08-10*

字符串分割不可用

结果应该是：

Column1 Column2 Column3 Column4 Column5 Column6 Column7
1HS     AB      GXX     123     2       PA45    10-08-2013
1R1     B       GX      123     2       PA45    10-08-2013
1HS     B       GX      13      1       PA45    01-08-2013
1P      C       GXX     123     2       PA45    10-08-2013

不幸的是，string_split不能保证它保留值的顺序。而且，SQLServer不提供其他有用的字符串函数

因此，我建议为此使用递归CTE：

with t as (
      select *
      from (values ('*1HS*AB*GXX*123*02*PA45*2013-08-10*'), ('1HSB*GX*13*01*PA45*2013-08-01*')) v(str)
     ),
     cte as (
      select convert(varchar(max), null) as val, 0 as lev, convert(varchar(max), str) as rest,
             row_number() over (order by (select null)) as id
      from t
      union all
      select left(rest, charindex('*', rest) - 1), lev + 1, stuff(rest, 1, charindex('*', rest) + 1, ''), id
      from cte
      where rest <> '' and lev < 10
     )
select max(case when lev = 1 then val end) as col1,
       max(case when lev = 2 then val end) as col2,
       max(case when lev = 3 then val end) as col3,
       max(case when lev = 4 then val end) as col4,
       max(case when lev = 5 then val end) as col5,
       max(case when lev = 6 then val end) as col6,
       max(case when lev = 7 then val end) as col7
from cte
where lev > 0
group by cte.id;

---

是一个dbfiddle。

您会使用下面的查询吗

select RTRIM (REGEXP_SUBSTR (column y, '[^,]*,', 1, 1), ',')    AS column 1
    ,       RTRIM (REGEXP_SUBSTR (column y, '[^,]*,', 1, 2), ',')    AS column 2
    ,       RTRIM (REGEXP_SUBSTR (column y, '[^,]*,', 1, 3), ',')    AS column 3
    ,       LTRIM (REGEXP_SUBSTR (column y, ',[^,]*', 1, 3), ',')    AS column 4
    from YOUR_TABLE

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假设您可以向数据库中添加表值函数，那么Jeff Moden的字符串拆分函数是我遇到的最好的方法。它也能让你维持秩序

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REGEXP_SUBSTR不是T-SQLfunction@GordonLinoff为什么你会建议这不是；它的一个副本似乎是一个完全相同的副本。OP希望将分隔列表转换为列。