SQL-基于两列选择最新的唯一
我在DB2仓库表中有一个名为TEST的表:SQL-基于两列选择最新的唯一,sql,db2,unique,distinct,Sql,Db2,Unique,Distinct,我在DB2仓库表中有一个名为TEST的表: DATETIME NAME TYPE ANOMALY CRE_DATE 0 2018-03-05 14:50:30 TEST UV 0 2018-03-03 12:48:10.058288 1 2018-03-05 14:51:30 TEST UV 0 2018-03-03 12:50:38.574614 2 2018-03-05 14:51:30 T
DATETIME NAME TYPE ANOMALY CRE_DATE
0 2018-03-05 14:50:30 TEST UV 0 2018-03-03 12:48:10.058288
1 2018-03-05 14:51:30 TEST UV 0 2018-03-03 12:50:38.574614
2 2018-03-05 14:51:30 TEST UV 0 2018-03-03 12:52:01.705416
3 2018-03-05 14:51:30 TEST UV 0 2018-03-05 13:45:56.937965
我要做的是选择最新的行(基于CRE_DATE
),其中DATETIME>=(当前日期-3天)
和NAME='TEST'
。我尝试从该查询开始,但无法使其工作:
SELECT
DISTINCT DATETIME,
NAME,
TYPE,
ANOMALY,
CRE_DATE
FROM
ML_ANOMALY_EVALUATION
WHERE
ANOMALY=FALSE AND
NAME='TEST'
ORDER BY
CRE_DATE DESC
在DB2中,最简单的方法是使用
行数()
非常好,谢谢你!只需移除mae。从子菜单中选择,因为您没有在@GordonLinoff处使用该别名
SELECT mae.*
FROM (SELECT mae.*,
ROW_NUMBER() OVER (PARTITION BY datetime ORDER BY CRE_DATE DESC) as seqnum
FROM ML_ANOMALY_EVALUATION mae
WHERE ANOMALY = FALSE AND NAME = 'HOG.683KQC206'
) mae
WHERE seqnum = 1
ORDER BY CRE_DATE DESC;