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Sql 带子查询的Postgres XMLCONCAT()_Sql_Xml_Postgresql - Fatal编程技术网

Sql 带子查询的Postgres XMLCONCAT()

Sql 带子查询的Postgres XMLCONCAT(),sql,xml,postgresql,Sql,Xml,Postgresql,我试图使用Postgres生成一个XML文档作为输出 假设我有一个关系,客户。它有id、name和email列 我想要如下所示的XML: SELECT XMLELEMENT(NAME customer, XMLELEMENT(NAME 'id', "id"), XMLELEMENT(NAME 'name', name), XMLELEMENT(NAME email, email)) FROM customers; 0 客户

我试图使用Postgres生成一个XML文档作为输出

假设我有一个关系,
客户
。它有
id
name
email

我想要如下所示的XML:

SELECT XMLELEMENT(NAME customer, 
           XMLELEMENT(NAME 'id', "id"),
           XMLELEMENT(NAME 'name', name), 
           XMLELEMENT(NAME email, email))
FROM customers;

0
客户1
customer1@gmail.com
1.
客户2
customer2@gmail.com
到目前为止,我可以为每个客户生成XML,如下所示:

SELECT XMLELEMENT(NAME customer, 
           XMLELEMENT(NAME 'id', "id"),
           XMLELEMENT(NAME 'name', name), 
           XMLELEMENT(NAME email, email))
FROM customers;
但是,将其连接到单个XML文档中是行不通的。我试过:

SELECT XMLELEMENT(NAME customers, XMLCONCAT((
    SELECT XMLELEMENT(NAME customer, 
               XMLELEMENT(NAME 'id', "id"),
               XMLELEMENT(NAME 'name', name), 
               XMLELEMENT(NAME email, email))
FROM customers;
)));

但是,如果子查询返回的消息
超过一行用作表达式,则此操作失败。这将删除重复的行。

实现这一点的方法有很多。一种简单的方法是获取所需的XML元素并使用它们进行聚合

样本数据

CREATE TEMPORARY TABLE customers (id int, name text, email text);
INSERT INTO customers VALUES 
(0,'Customer 1','customer1@gmail.com'),
(0,'Customer 2','customer2@gmail.com');
质疑


你需要把它们聚合起来。由于xmlagg的速度很慢,您可以执行类似于
从客户处选择xmlement(客户名称,STRING_AGG(xmlement(客户名称,xmlement(名称'id','id'),…)::TEXT',')::XML)的操作
有关解决方案,请参阅此链接
SELECT 
  XMLELEMENT(NAME customers, xmlagg((customers)))
FROM (SELECT 
  XMLELEMENT(NAME customer, 
    XMLELEMENT(NAME id, id),
    XMLELEMENT(NAME name, name), 
    XMLELEMENT(NAME email, email)) AS customers
FROM customers) j;