Sql 带IDs的最小最大值-Oracle

尝试在Oracle 8i中获取此输出：

column1 |time
________|_______
  ABC   | 00:00:01
  END   | 00:00:03
  123   | 00:00:04
  END   | 00:00:07
  ABC   | 00:00:08
  END   | 00:00:10

使用来自另一个查询的此输出

   column1  |time       |ID
    ________|___________|
      ABC   | 00:00:01  |  1
      ABC   | 00:00:02  |  1
      ABC   | 00:00:03  |  1 
      123   | 00:00:04  |  1
      123   | 00:00:05  |  1
      123   | 00:00:06  |  1
      123   | 00:00:07  |  1
      ABC   | 00:00:08  |  2
      ABC   | 00:00:09  |  2
      ABC   | 00:00:10  |  2

此查询在不考虑ID的情况下获取最小值和最大值

select (case when n.n = 1 then column1 else 'END' end) as column1,
       (case when n.n = 1 then firsttime else lasttime end) as "time"
from (select column1, min(time) as firsttime, max(time) as lasttime
      from t
      group by column1
     ) t cross join
     (select 1 as n from dual union all select 2 from dual) n
order by column1, n.n;

---

如何做同样的事情，而不是在CulnN1中获得第一个和最后一个值，也考虑ID吗？

< P>你需要在逻辑中包含<代码> ID <代码>，在<>代码>组中按和<<代码>顺序< < /代码>：

select (case when n.n = 1 then column1 else 'END' end) as column1,
       (case when n.n = 1 then firsttime else lasttime end) as "time"
from (select column1, id, min(time) as firsttime, max(time) as lasttime
      from t
      group by column1, id
     ) t cross join
     (select 1 as n from dual union all select 2 from dual) n
order by id, column1, n.n;

---

将

按列分组1

替换为

按列分组1，id

？我想您希望

按t.firsttime，t.column1，n.n进行排序，并将相邻值保持在一起？因此，当我添加对结果进行分组的新列时，我将它们添加到组ny中并按顺序排序？它们的正确顺序是什么？例如，如果我有另一个级别的分组值，我会添加列adter column1？@Dalek。
分组依据中列的顺序没有区别。