Sql ROW_NUMBER()覆盖(分区依据…)以返回特定行
我的查询如下所示:Sql ROW_NUMBER()覆盖(分区依据…)以返回特定行,sql,oracle,window-functions,row-number,Sql,Oracle,Window Functions,Row Number,我的查询如下所示: with T1 as ( Select Dept_No, Product_No, Order_No, Order_Type Row_number() over (partition by Product_ID order by Order_No desc) as "COUNT" From Orders_Table) Select * from T1 where ("COUNT" = '1' and "Order_Type" <> 'Cancel') or (
with T1 as (
Select
Dept_No,
Product_No,
Order_No,
Order_Type
Row_number() over (partition by Product_ID order by Order_No desc) as "COUNT"
From Orders_Table)
Select * from T1
where ("COUNT" = '1' and "Order_Type" <> 'Cancel')
or ("COUNT" = '2' AND "Order_Type" <> 'Cancel'
因此,我正在尝试提取未取消的最新订单。基本上我的行数超过了分区数。。。函数按顺序标记订单,1表示最近的订单,2表示第二个最近的订单。问题是,通过这个查询,它同时提取最近和第二个最近的订单。我试着把它写在哪里,如果它只给出一个或另一个。因此,如果COUNT=1且订单类型不是cancel,则只显示该记录。如果没有,那么给我看第二个
非常感谢你事先的帮助。这是在Toad for Oracle 9.5中使用SQL选项卡完成的。但是您有一个or。
如果两者都满意,您将得到两行
with T1 as (
Select
Dept_No,
Product_No,
Order_No,
Order_Type
Row_number() over (partition by Product_ID order by Order_No desc) as "COUNT"
From Orders_Table
where "Order_Type" <> 'Cancel')
Select * from T1
where "COUNT" = '1'
使用case表达式控制哪些行从row_number获得结果,这里我们避免对任何已取消的行进行编号:
WITH t1 AS (
SELECT
Dept_No
, Product_No
, Order_No
, Order_Type
/* the most recent order that was not canceled */
, case when order_type <> 'Cancel'
then ROW_NUMBER() OVER (PARTITION BY Product_ID
ORDER BY Order_No DESC)
end AS is_recent
FROM Orders_Table
)
SELECT
*
FROM t1
WHERE is_recent = 1
或者,也许最简单的方法是简单地排除取消的订单,例如
WITH t1 AS (
SELECT
Dept_No
, Product_No
, Order_No
, Order_Type
, ROW_NUMBER() OVER (PARTITION BY Product_ID
ORDER BY Order_No DESC)
AS is_recent
FROM Orders_Table
WHERE order_type <> 'Cancel'
)
SELECT
*
FROM t1
WHERE is_recent = 1
注意:row_number返回一个整数,因此请不要将该列与字符串输入/输出进行比较。将订单类型“Cancel”添加到cte,然后在第二个查询中仅查找Count='1'。试试看。我只是在读你的评论之前就在想。好主意!让我核对一下,然后标上答案