Sql 显示大小写表达式中的空行

Sql 显示大小写表达式中的空行,sql,oracle,case,Sql,Oracle,Case,我正在编写一个sql报告,其中一个要求是为CASE表达式的两个选项都包含行 该报告将显示数据库中所有客户与3个选定客户之间的“成本核算”和“非成本核算”交易的计数 请参见所需的示例布局 CUSTOMER_ID | CUSTOMER_NAME | COSTING | CUST_1 | CUST_2 | CUST_3 12 | Red Corp | Non-costing | 1245 | 734 | 84 12 | Red Corp

我正在编写一个sql报告,其中一个要求是为CASE表达式的两个选项都包含行

该报告将显示数据库中所有客户与3个选定客户之间的“成本核算”和“非成本核算”交易的计数

请参见所需的示例布局

CUSTOMER_ID | CUSTOMER_NAME | COSTING     | CUST_1 | CUST_2 | CUST_3
12          | Red Corp      | Non-costing | 1245   | 734    | 84
12          | Red Corp      | Costing     | 376    | 23     | 2
17          | Blue Corp     | Non-costing | 4538   | 36     | 3256
17          | Blue Corp     | Costing     | 0      | 0      | 0
...
我曾尝试将成本计算列放入案例陈述中。但是,我无法在输出中显示示例“Blue Corp”“Costing”行,因为该行为空

select  CUSTOMER_ID
        ,CUSTOMER_NAME
        ,case 
            when PURCHASE_VALUE = 0 or PURCHASE_VALUE is null then 'Non-costing'
            when PURCHASE_VALUE != 0 or PURCHASE_VALUE is not null then 'Costing'
        end AS COSTING
,count(CASE WHEN CUSTOMER_ID = 11 then 1 ELSE NULL END) as "CUST_1"
,count(CASE WHEN CUSTOMER_ID = 22 then 1 ELSE NULL END) as "CUST_2"
,count(CASE WHEN CUSTOMER_ID = 33 then 1 ELSE NULL END) as "CUST_3"
from schema.CUSTOMER_TRANSACTIONS
group by case 
            when PURCHASE_VALUE = 0 or PURCHASE_VALUE is null then 'Non-costing'
            when PURCHASE_VALUE != 0 or PURCHASE_VALUE is not null then 'Costing'
        end 
        ,CUSTOMER_ID
        ,CUSTOMER_NAME
我目前得到的与示例相同,但缺少0计数行。 请参阅下面我目前得到的输出

CUSTOMER_ID | CUSTOMER_NAME | COSTING     | CUST_1 | CUST_2 | CUST_3
12          | Red Corp      | Non-costing | 1245   | 734    | 84
12          | Red Corp      | Costing     | 376    | 23     | 2
17          | Blue Corp     | Non-costing | 4538   | 36     | 3256
...

你可以试试这个。当没有时,它将给你0

select  CUSTOMER_ID
        ,CUSTOMER_NAME
, CASE WHEN ISNULL(PURCHASE_Value,0) = 0 THEN 'Non-costing' ELSE 'Costing' END        
,SUM(CASE WHEN CUSTOMER_ID = 11 then 1 ELSE 0 END) as "CUST_1"
,SUM(CASE WHEN CUSTOMER_ID = 22 then 1 ELSE 0 END) as "CUST_2"
,SUM(CASE WHEN CUSTOMER_ID = 33 then 1 ELSE 0 END) as "CUST_3"
from schema.CUSTOMER_TRANSACTIONS
group by CUSTOMER_ID
        ,CUSTOMER_NAME
,PURCHASE_Value
从你的评论来看

亚历克斯·普尔,你是对的,没有关于“成本计算”的数据 “蓝色公司”。但是,我希望该行显示0,而不是0 根本没有出现

我认为您需要生成其中一个成本计算不可用的记录

我试图创建一个查询,如果任何客户都没有“成本核算”或“非成本核算”记录,该查询将生成该记录

我无法测试它,所以如果您遇到任何问题,请与我们分享

-- Your original query starts from here
WITH DATAA AS (select  CUSTOMER_ID
        ,CUSTOMER_NAME
        ,case 
            when PURCHASE_VALUE = 0 or PURCHASE_VALUE is null then 'Non-costing'
            when PURCHASE_VALUE != 0 or PURCHASE_VALUE is not null then 'Costng'
        end AS COSTING
,count(CASE WHEN CUSTOMER_ID = 11 then 1 ELSE NULL END) as "CUST_1"
,count(CASE WHEN CUSTOMER_ID = 22 then 1 ELSE NULL END) as "CUST_2"
,count(CASE WHEN CUSTOMER_ID = 33 then 1 ELSE NULL END) as "CUST_3"
from schema.CUSTOMER_TRANSACTIONS
group by case 
            when PURCHASE_VALUE = 0 or PURCHASE_VALUE is null then 'Non-costing'
            when PURCHASE_VALUE != 0 or PURCHASE_VALUE is not null then 'Costing'
        end 
        ,CUSTOMER_ID
        ,CUSTOMER_NAME)
-- Your original query ends here


-- Solution
SELECT
    CUSTOMER_ID,
    CUSTOMER_NAME,
    COSTING,
    CUST_1,
    CUST_2,
    CUST_3
FROM
    DATAA
UNION ALL
( SELECT
    CUSTOMER_ID,
    CUSTOMER_NAME,
    CASE
        WHEN COUNT(CASE
            WHEN COSTING = 'Non-costing' THEN 1
        END) = 0 THEN 'Non-costing'
        WHEN COUNT(CASE
            WHEN COSTING = 'Costing' THEN 1
        END) = 0 THEN 'Costing'
    END AS COSTING,
    0,
    0,
    0
FROM
    DATAA D1
GROUP BY
    CUSTOMER_ID,
    CUSTOMER_NAME
HAVING ( COUNT(CASE
    WHEN COSTING = 'Non-costing' THEN 1
END) = 0
         OR COUNT(CASE
    WHEN COSTING = 'Costng' THEN 1
END) = 0 )
);

干杯

使用
交叉连接
生成行,使用
左连接
添加列:

select c.CUSTOMER_ID, c.CUSTOMER_NAME, t.costing,
       sum(CASE WHEN CUSTOMER_ID = 11 then 1 ELSE 0 END) as CUST_1,
       sum(CASE WHEN CUSTOMER_ID = 22 then 1 ELSE 0 END) as CUST_2,
       sum(CASE WHEN CUSTOMER_ID = 33 then 1 ELSE 0 END) as CUST_3
from (select distinct ct.customer_id, ct.customer_name
      from schema.CUSTOMER_TRANSACTIONS ct
     ) c cross join
     (select 'Non-costing' as costing from dual union all
      select 'Costing' from dual
     ) t left join
     schema.customer_transactions ct
     on c.customer_id = ct.customer_id,
        t.costing = (case when PURCHASE_VALUE = 0 or PURCHASE_VALUE is null
                         then 'Non-costing'
                         else 'Costing'
                     end)
group by c.CUSTOMER_ID, c.CUSTOMER_NAME, t.type;

我不能理解你的问题?你能提供你期望的结果吗?我希望它看起来像顶部的示例表。目前你得到了什么输出?你也可以发布吗?这似乎是由于你的客户端应用程序的格式问题。您使用什么来运行SQL?Standin.Wolf我已经更新了问题,以包含我当前输出的清晰示例。您不认为这会出错,因为
PURCHASE\u Value
直接用于
SELECT
,而不是
groupby
?这很完美,它准确地解决了我的问题。非常感谢。