TSQL：获取每小时的销售数据

我目前正在使用下面的代码从我的数据库中获取销售数据。它的问题是，它不会在没有销售的时间显示0。我不介意硬编码时间，但我找不到这样做的方法。所以

1.第一个问题：我如何将下面的代码转换为在以下时间内没有销售的小时显示0

2.第二个问题：我怎样才能从中得到一个有序的列表。以下代码将把9:00-10:00放在列表末尾，因为它不是两位数

-- HOUR BASED SALES
select (CAST(DATEPART(HOUR, INSERTDATE) as varchar(255)) + ':00 -' +
        CAST(DATEPART(HOUR, INSERTDATE) as varchar(255)) + ':59'
       ) as [time],
       SUM (TOTAL) as REVENUE,
       COUNT (RECEIPTID) AS TOTAL_SALES,
       DEPOTID
From INVOICE INV
WHERE DEPOTID IN (25) AND TRANSDATE BETWEEN '20181025' AND '20181025'
Group By cast(datepart(hour, INSERTDATE) AS VARCHAR(255)), DEPOTID
ORDER BY CAST(DATEPART(HOUR, INSERTDATE) AS VARCHAR(255))

---

您可以列出小时数并使用

左键联接

：

select (cast(v.hh as varchar(255)) + ':00 -' +
        cast(v.hh as varchar(255)) + ':59'
       ) as [time],
       sum(TOTAL) as REVENUE,
       sum(RECEIPTID) AS TOTAL_SALES,
       depot
From (values (0), (1), . . . (23)
     ) v(hh) left join
     invoice i
     on datepart(hour, i.insertdate) = v.hh and
        i.depotid in (25) and
        i.transdate between '20181025' and '20181025'
group by v.hh, DEPOTID
order by v.hh

---

您可以列出小时数并使用

左键联接

：

select (cast(v.hh as varchar(255)) + ':00 -' +
        cast(v.hh as varchar(255)) + ':59'
       ) as [time],
       sum(TOTAL) as REVENUE,
       sum(RECEIPTID) AS TOTAL_SALES,
       depot
From (values (0), (1), . . . (23)
     ) v(hh) left join
     invoice i
     on datepart(hour, i.insertdate) = v.hh and
        i.depotid in (25) and
        i.transdate between '20181025' and '20181025'
group by v.hh, DEPOTID
order by v.hh

---

谢谢除了v.insertdate不是唯一的insertdate之外，它工作得很好！。你能告诉我KeithL对“外部应用”的看法吗？@KemalEmin。您可以使用

outer apply

而不是

left join

。但是，

left join

是更传统的方法。谢谢。除了v.insertdate不是唯一的insertdate之外，它工作得很好！。你能告诉我KeithL对“外部应用”的看法吗？@KemalEmin。您可以使用

outer apply

而不是

left join

。然而，

left join

是更传统的方法。