Sql 在查询末尾插入一行,其中包含总和列的总计
我目前有一个查询,它汇总了一组值,并按日期对它们进行分组。结果如下所示:Sql 在查询末尾插入一行,其中包含总和列的总计,sql,sql-server,sql-server-2008,tsql,Sql,Sql Server,Sql Server 2008,Tsql,我目前有一个查询,它汇总了一组值,并按日期对它们进行分组。结果如下所示: Date Item2 Item2 Item3 Item4 Item5 2013-05-31 1 30 0 0 129 2013-06-03 0 90 0 15 78 2013-06-04 0 50 0 1 124 2013-06-05 0
Date Item2 Item2 Item3 Item4 Item5
2013-05-31 1 30 0 0 129
2013-06-03 0 90 0 15 78
2013-06-04 0 50 0 1 124
2013-06-05 0 100 0 17 58
2013-06-06 0 24 0 0 105
2013-06-07 0 50 0 1 83
2013-06-10 0 45 2 42 64
2013-06-11 3 43 0 14 90
2013-06-12 2 44 0 36 88
2013-06-13 1 34 0 15 92
我用于检索该结果的查询如下所示
SELECT CONVERT(NVARCHAR(10), TheDate, 120) 'Date',
(SUM(CASE WHEN itemID = 1 THEN 1 ELSE 0 END)) AS Item1,
(SUM(CASE WHEN itemID = 2 THEN 1 ELSE 0 END)) AS Item2,
(SUM(CASE WHEN itemID = 3 THEN 1 ELSE 0 END)) AS Item3,
(SUM(CASE WHEN itemID = 4 THEN 1 ELSE 0 END)) AS Item4,
(SUM(CASE WHEN itemID = 5 THEN 1 ELSE 0 END)) AS Item5
FROM Table1 AS a INNER JOIN
Table2 AS tab2 ON tab2.Table1ID = a.Table1ID LEFT OUTER JOIN
Table3 AS tab3 ON tab3.Table2ID = tab2.Table2ID
WHERE someOtherID = 3 AND UserID = 40
GROUP BY CONVERT(NVARCHAR(10), TheDate, 120)
ORDER BY CONVERT(NVARCHAR(10), TheDate, 120)
我希望看到的是在结果末尾插入一个“总计”行。最终输出如下所示
Date Item2 Item2 Item3 Item4 Item5
2013-05-31 1 30 0 0 129
2013-06-03 0 90 0 15 78
2013-06-04 0 50 0 1 124
2013-06-05 0 100 0 17 58
2013-06-06 0 24 0 0 105
2013-06-07 0 50 0 1 83
2013-06-10 0 45 2 42 64
2013-06-11 3 43 0 14 90
2013-06-12 2 44 0 36 88
2013-06-13 1 34 0 15 92
GRAND TOTAL 7 510 2 141 911
有没有人对这样做的最佳方法有什么建议
Thank you=D联合查询将是一种快速而肮脏的方法
SELECT CONVERT(NVARCHAR(10), TheDate, 120) 'Date',
(SUM(CASE WHEN itemID = 1 THEN 1 ELSE 0 END)) AS Item1,
(SUM(CASE WHEN itemID = 2 THEN 1 ELSE 0 END)) AS Item2,
(SUM(CASE WHEN itemID = 3 THEN 1 ELSE 0 END)) AS Item3,
(SUM(CASE WHEN itemID = 4 THEN 1 ELSE 0 END)) AS Item4,
(SUM(CASE WHEN itemID = 5 THEN 1 ELSE 0 END)) AS Item5
FROM Table1 AS a INNER JOIN
Table2 AS tab2 ON tab2.Table1ID = a.Table1ID LEFT OUTER JOIN
Table3 AS tab3 ON tab3.Table2ID = tab2.Table2ID
WHERE someOtherID = 3 AND UserID = 40
GROUP BY CONVERT(NVARCHAR(10), TheDate, 120)
ORDER BY CONVERT(NVARCHAR(10), TheDate, 120)
UNION
SELECT 'GrandTotal',
(SUM(CASE WHEN itemID = 1 THEN 1 ELSE 0 END)) AS Item1,
(SUM(CASE WHEN itemID = 2 THEN 1 ELSE 0 END)) AS Item2,
(SUM(CASE WHEN itemID = 3 THEN 1 ELSE 0 END)) AS Item3,
(SUM(CASE WHEN itemID = 4 THEN 1 ELSE 0 END)) AS Item4,
(SUM(CASE WHEN itemID = 5 THEN 1 ELSE 0 END)) AS Item5
FROM Table1 AS a INNER JOIN
Table2 AS tab2 ON tab2.Table1ID = a.Table1ID LEFT OUTER JOIN
Table3 AS tab3 ON tab3.Table2ID = tab2.Table2ID
WHERE someOtherID = 3 AND UserID = 40
您还可以在GROUP BY子句上使用WITHROLLUP选项
SELECT CASE GROUPING([TheDate])
WHEN 1 THEN 'GRAND TOTAL'
ELSE CONVERT(NVARCHAR(10), TheDate, 120)
END as Date
...
FROM Table1 AS a INNER JOIN
Table2 AS tab2 ON tab2.Table1ID = a.Table1ID LEFT OUTER JOIN
Table3 AS tab3 ON tab3.Table2ID = tab2.Table2ID
WHERE someOtherID = 3 AND UserID = 40
GROUP BY CONVERT(NVARCHAR(10), TheDate, 120) WITH ROLLUP
ORDER BY CONVERT(NVARCHAR(10), TheDate, 120)
写得真快,埃利亚斯!我很精通抄袭。不开玩笑,非常令人印象深刻的埃利亚斯。Thank you=d在几分钟内无法选择作为答案。。。我没有忘记你!实际上,还有另一种方法可以使用group by上的
和Rollup
,如果性能是一个问题,那么可能值得研究,EDIT Sparky在他的回答中提到了这一点,