SQL Server 2008透视表聚合函数问题

我有此查询，正在尝试按surveyname分组，但我收到以下错误：

Msg 8120，第16级，状态1，第1行
列“pvt.Follow Up”在选择列表中无效，因为它未包含在聚合函数或GROUP BY子句中

以下是查询：

SELECT 
   surveyname, [Follow Up] AS Follow_Up, [Ambiance] AS Ambiance, 
   [Consultation] AS Consultation, [Procedure/Service] AS Procedure_Service
FROM 
   (SELECT
       s.name surveyname, q.question, subq.answer subquestion,aw.answerweight, 
       aw.score, rc.categoryname, sc.cweight
    FROM survey.dbo.results r
    JOIN survey.dbo.questions q ON r.questionidfk = q.id
    LEFT JOIN survey.dbo.answers subq ON r.itemidfk = subq.id
    LEFT JOIN survey.dbo.answers a ON r.answeridfk = a.id
    JOIN survey.dbo.surveys s ON q.surveyidfk = s.id
    join sigweb.dbo.survey_types_main stm on s.id = stm.surveyidfk
    join survey.dbo.survey_results sr on r.owneridfk = sr.ownerid
    join sigweb.dbo.BosleySurvey bs on bs.contactid = sr.contactid and stm.clientsurveytypeid = bs.surveytype
    join sigweb.dbo.contact c on sr.contactid = c.contactid
    join sigweb.dbo.patient p on p.contactid = c.contactid
    join sigweb.dbo.doctor d on p.doctorid = d.doctorid
    join sigweb.dbo.survey_tracking st on st.contactid = c.contactID and st.surveytypeid = stm.surveytypeid
    left join survey.dbo.answerweighting aw on isnull(r.itemidfk, r.questionidfk) = aw.questionitemidfk and r.answeridfk = aw.answeridfk
    left join survey.dbo.rating_categories rc on aw.categoryidfk = rc.id
    left join survey.dbo.survey_categories sc on aw.categoryidfk = sc.categoryidfk and s.id = sc.surveyidfk
    where 
       aw.answerWeight is not null) ps
PIVOT
(
   AVG(score)
   FOR categoryname IN
    ( [Follow Up], [Ambiance], [Consultation], [Procedure/Service])
) AS pvt

按surveyname分组

这是我得到的结果的一个例子

SURVEYNAME      FOLLOW_UP   Ambiance   Consultation   Procedure_Service
Review             NULL     NULL    NULL          9.81
Review             9.54     NULL    NULL          NULL
Consultation       5        NULL    NULL          NULL
Consultation       NULL     5           NULL          NULL
Consultation       NULL     5           NULL          NULL
Consultation       NULL     5           NULL          NULL
Consultation       NULL     5           NULL          NULL
Consultation       NULL     5           NULL          NULL
Consultation       NULL     NULL    5         NULL
Consultation       5        NULL    NULL          NULL
Consultation       NULL     NULL    5         NULL

这是数据透视前的数据示例：

Review          6   Follow Up
Review          9   Procedure/Service
Consultation    5   Ambiance
Consultation    5   Ambiance
Consultation    5   Ambiance
Consultation    5   Ambiance
Consultation    5   Ambiance
Consultation    5   Ambiance
Consultation    5   Consultation
Consultation    5   Consultation

---

我们的想法是按

surveyname

分组，最后只有两个结果。

我不确定您发布的内容中的错误来自何处（我假设是在您尝试将

groupby surveyname

添加到您发布的查询末尾时），但您需要从子查询中删除冗余列，因此，您只需选择所需的3列，

surveyname

、

score

和

categoryname

：

SELECT 
   surveyname, [Follow Up] AS Follow_Up, [Ambiance] AS Ambiance, 
   [Consultation] AS Consultation, [Procedure/Service] AS Procedure_Service
FROM 
   (SELECT
       s.name surveyname, aw.score, rc.categoryname
    FROM survey.dbo.results r
    JOIN survey.dbo.questions q ON r.questionidfk = q.id
    LEFT JOIN survey.dbo.answers subq ON r.itemidfk = subq.id
    LEFT JOIN survey.dbo.answers a ON r.answeridfk = a.id
    JOIN survey.dbo.surveys s ON q.surveyidfk = s.id
    join sigweb.dbo.survey_types_main stm on s.id = stm.surveyidfk
    join survey.dbo.survey_results sr on r.owneridfk = sr.ownerid
    join sigweb.dbo.BosleySurvey bs on bs.contactid = sr.contactid and stm.clientsurveytypeid = bs.surveytype
    join sigweb.dbo.contact c on sr.contactid = c.contactid
    join sigweb.dbo.patient p on p.contactid = c.contactid
    join sigweb.dbo.doctor d on p.doctorid = d.doctorid
    join sigweb.dbo.survey_tracking st on st.contactid = c.contactID and st.surveytypeid = stm.surveytypeid
    left join survey.dbo.answerweighting aw on isnull(r.itemidfk, r.questionidfk) = aw.questionitemidfk and r.answeridfk = aw.answeridfk
    left join survey.dbo.rating_categories rc on aw.categoryidfk = rc.id
    left join survey.dbo.survey_categories sc on aw.categoryidfk = sc.categoryidfk and s.id = sc.surveyidfk
    where 
       aw.answerWeight is not null) ps
PIVOT
(
   AVG(score)
   FOR categoryname IN
    ( [Follow Up], [Ambiance], [Consultation], [Procedure/Service])
) AS pvt

---

在后台，您还通过

q.question、subq.answersubquestion、aw.answerweight、sc.cweight对最终结果进行分组，因为它们包含在子查询中，但是，由于不在选择列表中，您无法立即看到其效果。
似乎您在内部
选择中包含了太多的列，请尝试删除这些列：

q.question, subq.answer subquestion, aw.answerweight, sc.cweight

它们很可能使行
不同
，因此
分组依据
无法正常工作。因此，您的查询将是：

SELECT surveyname, 
    [Follow Up] AS Follow_Up, 
    [Ambiance] AS Ambiance, 
    [Consultation] AS Consultation, 
    [Procedure/Service] AS Procedure_Service
FROM 
(
    SELECT s.name surveyname, 
        aw.score, 
        rc.categoryname, 
    FROM survey.dbo.results r
    JOIN survey.dbo.questions q 
        ON r.questionidfk = q.id
    LEFT JOIN survey.dbo.answers subq 
        ON r.itemidfk = subq.id
    LEFT JOIN survey.dbo.answers a 
        ON r.answeridfk = a.id
    JOIN survey.dbo.surveys s 
        ON q.surveyidfk = s.id
    join sigweb.dbo.survey_types_main stm 
        on s.id = stm.surveyidfk
    join survey.dbo.survey_results sr 
        on r.owneridfk = sr.ownerid
    join sigweb.dbo.BosleySurvey bs 
        on bs.contactid = sr.contactid 
            and stm.clientsurveytypeid = bs.surveytype
    join sigweb.dbo.contact c 
        on sr.contactid = c.contactid
    join sigweb.dbo.patient p 
        on p.contactid = c.contactid
    join sigweb.dbo.doctor d on p.doctorid = d.doctorid
    join sigweb.dbo.survey_tracking st 
        on st.contactid = c.contactID 
            and st.surveytypeid = stm.surveytypeid
    left join survey.dbo.answerweighting aw 
        on isnull(r.itemidfk, r.questionidfk) = aw.questionitemidfk 
            and r.answeridfk = aw.answeridfk
    left join survey.dbo.rating_categories rc 
        on aw.categoryidfk = rc.id
    left join survey.dbo.survey_categories sc 
        on aw.categoryidfk = sc.categoryidfk and s.id = sc.surveyidfk
    where aw.answerWeight is not null
) ps
PIVOT
(
   AVG(score)
   FOR categoryname IN
    ( [Follow Up], [Ambiance], [Consultation], [Procedure/Service])
) AS pvt

我在数据透视之前添加了结果。请尝试从内部选择中删除未包含在最终
select
中的字段-
q.question，subq.answer subquestion，aw.answerweight，sc.cweight
。这些字段可能使行不同，因此
分组依据
不起作用。请将此添加为答案，以便我可以接受它。我从子查询中删除了额外的列，即使没有
groupby
功能化的答案，它也可以正常工作，很高兴你找到了答案。：）我删除了q.question、subq.answer子问题、aw.answerweight、sc.cweight和我的查询工作