Sql 选择每个组的上次更改值

我正在尝试选择每个组的最后更改值

我有一张桌子

MMID列是增量的

在这里，我想要8月18日最后24小时内的最后一次更改“值”。 从下面的查询中，我可以得到。但即使bundle的值发生了变化，我也会得到那一行。 但我只希望在“Value”更改或“Value和Bundle”更改时使用行。但不仅仅是当Bundle被改变时

Desired output

MMID  GID  MID  Value  Bundle DateEntered

4      1    1      0     2       18/8/15 05:05:08
6      2    2      2     2       18/8/15 06:06:06

我尝试的查询是：

select yt1.*
from Table1 yt1
left outer join Table1 yt2
on (yt1.GID = yt2.GID and yt1.MID = yt2.MID
and yt1.MMID < yt2.MMID)
where yt2.MMID is null and yt2.GID is null and yt2.MID is null and yt1.DateEntered > '2015-08-18 00:00:00' ;

我不应该排在最后一排

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有人能告诉我我应该在这里做些什么吗。

并没有真正按照您的尝试逻辑进行，但以下是我将如何获得所需结果：

WITH cte AS (
  SELECT *, 
    ROW_NUMBER() OVER (PARTITION BY GID, MID ORDER BY MMID) AS rn
  FROM Table
)
, cte2 AS (
SELECT t1.* FROM cte t1
INNER JOIN cte t2
 ON t1.GID=t2.GID
 AND t1.MID=t2.MID
 AND t1.value<>t2.value
 AND t1.rn=t2.rn+1
)
SELECT * 
FROM cte2
WHERE MMID=(
  SELECT TOP 1 MMID
  FROM cte2 c2
  WHERE cte2.GID=c2.GID
  AND cte2.MID=c2.MID
  ORDER BY MMID DESC
)

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注意：如果您不想在最终结果中包含rn列，请使用列列表而不是选择*

为什么您的查询引用表1和表2？有不止一张桌子吗？看起来你的查询根本不应该起作用。有yt1.MMIDMMID GID MID Value Bundle DateEntered 4 1 1 0 2 18/8/15 05:05:08 6 2 2 2 2 18/8/15 06:06:06 8 2 4 3 2 18/8/15 06:06:07

WITH cte AS (
  SELECT *, 
    ROW_NUMBER() OVER (PARTITION BY GID, MID ORDER BY MMID) AS rn
  FROM Table
)
, cte2 AS (
SELECT t1.* FROM cte t1
INNER JOIN cte t2
 ON t1.GID=t2.GID
 AND t1.MID=t2.MID
 AND t1.value<>t2.value
 AND t1.rn=t2.rn+1
)
SELECT * 
FROM cte2
WHERE MMID=(
  SELECT TOP 1 MMID
  FROM cte2 c2
  WHERE cte2.GID=c2.GID
  AND cte2.MID=c2.MID
  ORDER BY MMID DESC
)